Calculate the Area of an Equilateral Hexagon with Side Length 7 and Height 12.124

The hexagon consists of two equal trapezoids, so we will strive to calculate the area of one of them and multiply it.

AFE is an isosceles triangle,

its height (FG) crosses the base exactly in the center, therefore:

$AG=GE$

$AG=\frac{1}{2}AE$

We replace and discover:

$AE=\frac{1}{2}\times12=6$

We replace the data in the formula for the area of a trapezoid:

$\frac{(base+base)}{2}\times altura$

$\frac{7+14}{2}\times6=\frac{21}{2}\times6=10.5\times6=63$

63 is the area of half of the hexagon, therefore:

$63\times2=126$