Examples with solutions for All Operations in the Order of Operations: Worded problems

Exercise #1

There are 50 lollipops in a sweet shop.

The shop then receives a delivery of 9 boxes that include 18 lollipops each, as well as 6 boxes containing 14 lollipops each.

How many lollipops are there now in the shop?

Step-by-Step Solution

To solve this problem, we need to calculate the total number of lollipops currently in the shop.

1. Begin with the initial number of lollipops.
Initially, there are 50 lollipops in the shop.

2. Calculate the additional lollipops received from the delivery.
There are two sets of boxes delivered:

  • The first set contains 9 boxes, each having 18 lollipops. Therefore, the total number of lollipops from this set is calculated as: 9×189 \times 18.
  • The second set includes 6 boxes, each with 14 lollipops. Thus, the total number from this set is: 6×146 \times 14.

3. Compute the total lollipops from both sets:
Total lollipops from 9 boxes = 9×18=1629 \times 18 = 162.
Total lollipops from 6 boxes = 6×14=846 \times 14 = 84.

4. Add the lollipops from both deliveries to the initial count:
Total = Initial lollipops + Lollipops from 9 boxes + Lollipops from 6 boxes
=50+162+84= 50 + 162 + 84
=296= 296

Therefore, there are 296 lollipops in the shop now.

Answer

296

Exercise #2

There are several types of flowers in a field.

5 flowers grow on one bush and there are are 13 such bushes.

Another area has 9 plants, each of which has 2 flowers.

The flower pickers took 30 flowers from the bushes and 10 from the plants.

How many flowers are left in the field?

Step-by-Step Solution

We will convert the question into an exercise with which we are familiar:

(5×1330)+(9×210) \left(5\times 13-30\right)+\left(9\times 2-10\right)

First, we will solve everything that is in the parentheses, starting with the multiplication and division from left to right:

(6530)+(1810) \left(65-30\right)+\left(18-10\right)

Then the addition and subtraction operations that are in the parentheses:

35+8 35+8

Finally, we perform the operations outside of the parentheses:

35+8=43 35+8=43

Answer

43

Exercise #3

There are three boxes of apples on the table.

Box A contains 22 apples.

Box B contains 24 apples.

Box C contains 14 apples.

How many apples are there on average in each box?

Step-by-Step Solution

To calculate the average number of apples in each box, we need to find the total number of apples in all the boxes and then divide by the number of boxes.

  • First, determine the total number of apples across all boxes. We have:
    22+24+1422 + 24 + 14 apples.

    The sum of apples in each box is:
    22+24+14=6022 + 24 + 14 = 60 apples.


  • Next, we find the average by dividing the total number of apples by the number of boxes. There are 3 boxes:
    603\frac{60}{3}.


  • Perform the division:
    603=20\frac{60}{3} = 20.


Thus, the average number of apples in each box is 2020 apples.

Answer

20

Exercise #4

A Mother is 25 years older than her daughter.

The sum of their ages is 40.

What is the age of the daughter?

Step-by-Step Solution

To solve this problem, we need to set up a system of equations based on the information given. We can start by assigning variables to represent the ages of the mother and daughter:
M M for the mother's age, and D D for the daughter's age.

From the problem statement, we know the following:

  • The mother is 25 years older than her daughter: M=D+25 M = D + 25 .
  • The sum of their ages is 40: M+D=40 M + D = 40 .

We can substitute the first equation into the second equation to solve for D D :

(D+25)+D=40 (D + 25) + D = 40

This simplifies to:

2D+25=40 2D + 25 = 40

Subtract 25 from both sides to isolate the term with D D :

2D+2525=4025 2D + 25 - 25 = 40 - 25

Which is:

2D=15 2D = 15

Now, divide both sides by 2 to solve for D D :

D=152 D = \frac{15}{2}

Thus, the daughter's age is 7.5 7.5 years old.

This solution checks out as it satisfies both given conditions in the problem statement.

Answer

7.5 7.5

Exercise #5

Given a rectangle whose perimeter 30 cm

One side of the rectangle is larger by 2 cm than the adjacent side.

Calculate the small side in the rectangle.

X+2X+2X+2XXX

Video Solution

Step-by-Step Solution

Since in a rectangle every pair of opposite sides are equal to each other, we can claim that:

AB=CD=x+2 AB=CD=x+2

AD=BC=x AD=BC=x

We will create the following equation based on the given data:

30=x+x+2+x+x+2 30=x+x+2+x+x+2

30=4x+4 30=4x+4

304=4x 30-4=4x

26=4x 26=4x

x=6.5 x=6.5

Answer

6.5 6.5

Exercise #6

There are 180 students in the seventh grade of a school.

Male students make up 40%.

How many female students are there in the seventh grade?

Step-by-Step Solution

To find the number of female students in the seventh grade, we first identify the number of male students and then subtract that from the total number of students.

Step 1: Calculate the number of male students.
Percentage of male students = 40% = 0.40
Total number of students = 180
Number of male students = 180 × 0.40
Number of male students = 72 72

Step 2: Calculate the number of female students.
Total number of students = 180
Number of female students = Total number of students - Number of male students
Number of female students = 180 - 72
Number of female students = 108 108

Answer

108 108