All Operations in the Order of Operations: Solving the problem

$21-3-6+9-5=$

Due to the fact that the exercise only involves addition and subtraction operations, we will solve it from left to right:

$21-3=18$

$18-6=12$

$12+9=21$

$21-5=16$

$16$

$25-6-9+7-3=$

Due to the fact that the exercise only involves addition and subtraction operations, we will solve it from left to right:

$25-6=19$

$19-9=10$

$10+7=17$

$17-3=14$

$14$

$(12-6+9)\times(7+3)=$

According to the order of operations, we will first solve the expressions in parentheses, and then multiply:

$(12-6+9)=(6+9)=15$

$(7+3)=10$

Now let's solve the multiplication problem:

$15\times10=150$

$150$

$25+6-19+7=$

Due to the fact that the exercise only involves addition and subtraction operations, we will solve it from left to right:

$25+6=31$

$31-19=12$

$12+7=19$

$19$

$12+6-4+18-12=$

Due to the fact that the exercise only involves addition and subtraction operations, we will solve it from left to right:

$12+6=18$

$18-4=14$

$14+18=32$

$32-12=20$

$20$

$26-6+9+7-12=$

Due to the fact that the exercise only involves addition and subtraction operations, we will solve it from left to right:

$26-6=20$

$20+9=29$

$29+7=36$

$36-12=24$

$24$

$30+6-5+7-17=$

Insofar as the exercise only involves addition and subtraction operations, we will solve it from left to right:

$30+6=36$

$36-5=31$

$31+7=38$

$38-17=21$

$21$

$(15-9)\times(7-3)=$

According to the order of operations rules, we must first solve the expressions inside of the parentheses:

$15-9=6$

$7-3=4$

We obtain the following expression:

$6\times4=24$

$24$

$32-4-19+3-7=$

Due to the fact that the exercise only involves addition and subtraction operations, we will solve it from left to right:

$32-4=28$

$28-19=9$

$9+3=12$

$12-7=5$

$5$

$(16-6)\times9+(7-3)=$

According to the order of operations, we'll first solve the exercises in parentheses:

$(16-6)=10$

$(7-3)=4$

Now we'll get the exercise:

$10\times9+4$

We'll put the multiplication exercise in parentheses to avoid confusion in the rest of the solution:

$(10\times9)+4=$

According to the order of operations, we'll solve the multiplication exercise and then add:

$90+4=94$

$94$

$25\times6-9-41=$

According to the order of operations, we first put the multiplication exercise in parentheses to avoid confusion in the rest of the solution:

$(25\times6)-9-41=$

Let's solve the multiplication exercise first:

$150-9-41=$

Now let's solve the exercise from left to right:

$150-9=141$

$141-41=100$

$100$

$14-5-9+7+2=$

Due to the fact that the exercise only involves addition and subtraction operations, we will solve it from left to right:

$14-5=9$

$9-9=0$

$0+7=7$

$7+2=9$

$9$

$12:3(1+1)=$

First, we perform the operation inside the parentheses:

$12:3(2)$

When there is no mathematical operation between parentheses and a number, we assume it is a multiplication.

Therefore, we can also write the exercise like this:

$12:3\times2$

Here we solve from left to right:

$12:3\times2=4\times2=8$

8

$(85+5):10=$

According to the order of operations rules, we must first solve the expression within the parentheses:

$85+5=90$

We should obtain the following expression:

$90:10=9$

9

$(13\times2)-(12\times1.5)=$

According to the order of operations, we will first solve the multiplication exercises in parentheses:

$(13\times2)=26$

$(12\times1.5)=18$

Now we will subtract:

$26-18=8$

$8$

$20-(1+9:9)=$

First, we solve the exercise in the parentheses

$(1+9:9)=$

According to the order of operations, we first divide and then add:

$1+1=2$

Now we obtain the exercise:

$20-2=18$

$18$

$25-3\times4+4\times2=$

According to the order of operations, we will first solve the multiplication exercises.

We will put them in parentheses so that we don't get confused later in the solution:

$25-(3\times4)+(4\times2)=$

Let's solve the multiplication exercises:

$3\times4=12$

$4\times2=8$

We get:

$25-12+8=$

Let's solve the exercise from left to right:

$25-12=13$

$13+8=21$

$21$

$19\times(20-4\times5)=$

First, we solve the exercise in the parentheses

$(20-4\times5)=$

According to the order of operations, we first multiply and then subtract:

$20-20=0$

Now we obtain the exercise:

$19\times0=0$

0

$\frac{3}{2}\times1\times\frac{1}{3}=$

According to the order of operations rules, we will solve the exercise from left to right since there are only multiplication operations:

$\frac{3}{2}\times1=\frac{3}{2}$

$\frac{3}{2}\times\frac{1}{3}=$

We will multiply the three by three and get:

$\frac{1}{2}\times1=\frac{1}{2}$

1\over2$1\over2$

$25-5-3-17+13=$

Due to the fact that the exercise only involves addition and subtraction operations, we will solve it from left to right:

$25-5=20$

$20-3=17$

$17-17=0$

$0+13=13$

$13$