All Operations in the Order of Operations: Using parentheses

Solve the following exercise:

$4\cdot2-3:(1+3)=$

First, we solve the exercise within the parentheses:

$4\cdot2-3:4=$

We place multiplication and division exercises within parentheses:

$(4\cdot2)-(3:4)=$

We solve the exercises within the parentheses:

$8-\frac{3}{4}=7\frac{1}{4}$

$7\frac{1}{4}$

Solve the exercise:

$3:(4+5)\cdot9-6=$

We solve the exercise in parentheses:

$3:9\cdot9-6=$

$\frac{3}{9}\cdot9-6=$

We simplify and subtract:

$3-6=-3$

-3

Solve the exercise:

$3\cdot(4-1)+5:1=$

We solve the exercise in parentheses:$3\cdot3+5:1=$

We place in parentheses the multiplication and division exercises:

$(3\cdot3)+(5:1)=$

We solve the exercises in parentheses:

$9+5=14$

$14$

Calculate and indicate the answer:

$(5-2)^2-2^3$

Remember that according to the order of arithmetic operations, exponents precede multiplication and division, which precede addition and subtraction (and parentheses always precede everything).

So first calculate the values of the terms with exponents and then subtract the results:

$(5-2)^2-2^3 =3^2-2^3=9-8=1$Therefore, the correct answer is option C.

1

Solve the exercise:

$2\times3-(4+5):2=$

According to the rules of the order of operations, we first solve the exercise within parentheses:

$4+5=9$

Now we obtain the exercise:

$2\times3-9:2=$

We place in parentheses the multiplication and division exercises:

$(2\times3)-(9:2)=$

We solve the exercises within parentheses:

$2\times3=6$

$9:2=4.5$

Now we obtain the exercise:

$6-4.5=1.5$

$1.5$

Solve the following equation:

$\frac{400\colon(-5)-\lbrack-2(93-61)\rbrack}{4}=$

We begin by addressing the numerator of the fraction.

First we solve the division exercise and the exercise within the parentheses:

$400:(-5)=-80$

$(93-61)=32$

We obtain the following:

$\frac{-80-(-2\times32)}{4}=$

We then solve the parentheses in the numerator of the fraction:

$\frac{-80-(-64)}{4}=$

Let's remember that a negative times a negative equals a positive:

$\frac{-80+64}{4}=$

$\frac{-16}{4}=-4$

$-4$

$225:[(26-6:3)\times5]=$

First, we solve the exercise within the innermost parentheses:

$(26-6:3)=$

According to the order of operations, we first divide and then subtract:

$26-2=24$

Now we obtain the exercise:

$225:(24\times5)=$

We solve the multiplication exercise and then divide:

$225:120=1.875$

1.875

Calculate and indicate the answer:

$(10^2-2\cdot5):3^2$

10

Calculate and indicate the answer:

$(\sqrt{9}-\sqrt{4})^2\cdot4^2-5^1$

11

$\frac{1}{3}+(2-1)=$

1 1/3

$0.6\times(1+2)=$

1.8

Calculate and indicate the answer:

$(\sqrt{100}-\sqrt{9})^2:7$

7

Calculate and indicate the answer:

$5:(13^2-12^2)$

$\frac{1}{5}$

Calculate and indicate the answer:

$(4^2+3^2):\sqrt{25}$

5

Calculate and indicate the answer:

$(\sqrt{25}-2^2)^3+2^3$

9

Indicate whether the equality is true or not.

^{$(5^2+3):2^2=5^2+(3:2^2)$}

Not true

Solve the following question:

$(4^2:8):2+3^2=$

10

Solve the following question:

$(18-10)^2+3^3=$

91

Calculate and indicate the answer:

^{$7:(5^2-\sqrt{16})\cdot3+\sqrt{3}\cdot\sqrt{3}$}

4

Solve the following question:

$3-(5^2:5)^2+7^2=$

27