Symmetry in a parabola

🏆Practice symmetry

The axis of symmetry in a parabola is the axis that passes through its vertex in such a way that if we folded the right side over the left side, both sides would appear joined.
Let's see it in an illustration:

Symmetry 1

To find the axis of symmetry, we must locate the value of X X of the vertex of the parabola or do it through the parabola's vertex formula or with the help of two symmetric points on the parabola.

Vertex Formula of the Parabola

X=b2a X=\frac{-b}{2a}

Formula for two symmetric points:

B3 - The formula to find X a vertex using two symmetric points

XVertex=The value of X at the first point + The value of X at the second point2 X_{Vertex}=\frac{The~value~of~X~at~the~first~point~+~The~value~of~X~at~the~second~point}{2}

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Test yourself on symmetry!

einstein

Given the expression of the quadratic function

Finding the symmetry point of the function

\( f(x)=2x^2 \)

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Let's look at an example

First method: Solve for X at the vertex based on the formula.

Given the function x2+8x+5x^2+8x+5
Let's plug it into the formula and we will get:
x=821=81=8x=-\frac{8}{2\cdot1}=-\frac{8}{1}=-8
From this it follows that, the axis of symmetry is X=8X=-8


Second method: Find the axis of symmetry based on symmetrical points.

Given the points (2,2)(2,2),(6,2)(6,2)

Let's plug them into the formula and we will get:
x=6+22=82=4x=\frac{6+2}{2}=\frac{8}{2}=4
The axis of symmetry is X=4X=4


If you are interested in this article, you might also be interested in the following articles:

Symmetry in Trapezoids

Rotational Symmetry in Parallelograms

Symmetry of the Rhombus

In the Tutorela blog, you will find a variety of articles on mathematics.


Examples and exercises with solutions on symmetry

Exercise #1

What is the axis of symmetry of the equation?

y=(x5)2+15 y=(x-5)^2+15

Video Solution

Step-by-Step Solution

The first step in solving the equation you presented:

y=(x-5)²+15

is to expand the parentheses:

y=x²-10x+25+15

y=x²-10x+40

From here, we can use the formula to find the X-coordinate of the vertex:

-b/2a

Let's substitute the values from the equation:

-(-10)/2*1 =

10/2=5

The axis of symmetry of the parabola is X=5

Answer

x=5 x=5

Exercise #2

Given the expression of the quadratic function

Finding the symmetry point of the function

f(x)=2x2 f(x)=2x^2

Video Solution

Answer

(0,0) (0,0)

Exercise #3

Given the expression of the quadratic function

Finding the symmetry point of the function

f(x)=5x2+10 f(x)=-5x^2+10

Video Solution

Answer

(0,10) (0,10)

Exercise #4

Given the expression of the quadratic function

Finding the symmetry point of the function

f(x)=12x2 f(x)=\frac{1}{2}x^2

Video Solution

Answer

(0,0) (0,0)

Exercise #5

Given the expression of the quadratic function

The symmetrical axis of the expression must be found.

f(x)=3x2+3 f(x)=-3x^2+3

Video Solution

Answer

x=0 x=0

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