Standard Form of the Quadratic Function

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Standard Form of the Quadratic Function

The standard form of the quadratic function is:
Y=ax2+bx+cY=ax^2+bx+c

For example:
Y=4x2+3x+15Y=4x^2+3x+15

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Test yourself on standard representation!

Create an algebraic expression based on the following parameters:

\( a=3,b=6,c=9 \)

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How do you go from standard form to vertex form?

  • We need to find the vertex of the parabola using the formula to find the XX vertex.
  • Let's find the YY vertex.
  • Let's place in the vertex form template the X X vertex instead of PP, the YY vertex instead of CC and the aa instead of aa.

How do you go from standard form to factored form?

  • Let's find the points of intersection of the parabola with the xx axis.
  • Let's place it in the factored form template.

Look!
If we were to realize that in the standard form there is a coefficient for X2X^2 we will place it in the factoring formula before locating the intersection points there, as follows:

y=a×(xt)×(xk) y=a\times(x-t)\times(x-k)


Examples and exercises with solutions of the Standard form of the quadratic function

Exercise #1

Create an algebraic expression based on the following parameters:

a=2,b=12,c=4 a=2,b=\frac{1}{2},c=4

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow the steps outlined:

  • Step 1: Identify the given values for the quadratic function's parameters: a=2 a = 2 , b=12 b = \frac{1}{2} , and c=4 c = 4 .
  • Step 2: Apply these values to the standard quadratic form y=ax2+bx+c y = ax^2 + bx + c .
  • Step 3: Substitute the values to construct the algebraic expression.

Now, let's proceed with these steps:

Given the standard form of a quadratic expression y=ax2+bx+c y = ax^2 + bx + c :

Substituting the values, we obtain:

y=2x2+12x+4 y = 2x^2 + \frac{1}{2}x + 4

Therefore, the correct algebraic expression for the quadratic function is 2x2+12x+4 2x^2 + \frac{1}{2}x + 4 .

Answer

2x2+12x+4 2x^2+\frac{1}{2}x+4

Exercise #2

Create an algebraic expression based on the following parameters:

a=2,b=0,c=4 a=2,b=0,c=4

Video Solution

Step-by-Step Solution

To solve this problem, we will derive the algebraic expression step-by-step:

Step 1: Identify the given information:
The problem states a=2 a = 2 , b=0 b = 0 , and c=4 c = 4 .

Step 2: Write the standard quadratic expression:
The general form is y=ax2+bx+c y = ax^2 + bx + c .

Step 3: Substitute the given values into the expression:
Replace a a with 2, b b with 0, and c c with 4:
y=2x2+0x+4 y = 2x^2 + 0x + 4 .

Step 4: Simplify the expression:
Since 0x 0x is zero, the expression simplifies to:
y=2x2+4 y = 2x^2 + 4 .

Thus, the algebraic expression based on the given parameters is 2x2+4 2x^2 + 4 .

The correct answer is: 2x2+4 2x^2 + 4 (Choice 1).

Answer

2x2+4 2x^2+4

Exercise #3

Create an algebraic expression based on the following parameters:

a=2,b=4,c=8 a=2,b=4,c=8

Video Solution

Step-by-Step Solution

To solve this problem, we need to form an algebraic expression for a quadratic function using given parameters.

We start by recalling the standard form of a quadratic function: (ax2+bx+c)( ax^2 + bx + c ). In this expression:

  • a a is the coefficient of x2 x^2
  • b b is the coefficient of x x
  • c c is the constant term

Given the values are a=2 a = 2 , b=4 b = 4 , and c=8 c = 8 , we substitute these into the standard form equation:

ax2+bx+c=2x2+4x+8 ax^2 + bx + c = 2x^2 + 4x + 8

This yields the algebraic expression for the quadratic function.

The correct expression, given all calculations and simplifications, is 2x2+4x+8 2x^2 + 4x + 8 .

Referring to the choices provided, the correct choice is:

: (2x2+4x+8)( 2x^2 + 4x + 8 )

Therefore, the solution to the problem is 2x2+4x+8\boxed{2x^2 + 4x + 8}.

Answer

2x2+4x+8 2x^2+4x+8

Exercise #4

Create an algebraic expression based on the following parameters:

a=3,b=0,c=3 a=3,b=0,c=-3

Video Solution

Step-by-Step Solution

To solve the problem of creating an algebraic expression with the given parameters, we will proceed as follows:

  • Step 1: Identify the given coefficients for the quadratic function, which are a=3 a = 3 , b=0 b = 0 , and c=3 c = -3 .
  • Step 2: Substitute these values into the standard quadratic expression y=ax2+bx+c y = ax^2 + bx + c .

Through substitution, the expression becomes:

y=3x2+0x3 y = 3x^2 + 0x - 3

We can further simplify this expression:

y=3x23 y = 3x^2 - 3

Thus, the algebraic expression with the given parameters is y=3x23 y = 3x^2 - 3 .

The correct answer corresponds to choice number 1: 3x23 3x^2-3 .

Therefore, the solution to the problem is

y=3x23 y = 3x^2 - 3

Answer

3x23 3x^2-3

Exercise #5

Choose the correct algebraic expression based on the parameters:

a=3,b=3,c=7 a=-3,b=3,c=7

Video Solution

Step-by-Step Solution

To solve this problem, we will substitute the given values into the standard quadratic form:

  • Step 1: Identify the formula to use. We need the standard form of a quadratic function, which is y=ax2+bx+c y = ax^2 + bx + c .
  • Step 2: Substitute the given parameters into the formula:
    a=3 a = -3 , b=3 b = 3 , and c=7 c = 7 .
  • Step 3: Perform the substitution:
    Substituting in, we get y=3x2+3x+7 y = -3x^2 + 3x + 7 .

Therefore, the correct algebraic expression is 3x2+3x+7 -3x^2 + 3x + 7 .

This corresponds to choice 2 of the multiple-choice options provided.

Answer

3x2+3x+7 -3x^2+3x+7

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