Square Roots

When we encounter an exercise in which there is a root applied to another root, we will multiply the order of the first root by the order of the second and the order obtained (the product of both) will be raised as a root in our number (as generally power of a power)
Let's put it this way:  

root of root unknowns

Suggested Topics to Practice in Advance

  1. Square root of a product
  2. Square root of a quotient

Practice Root of a Root

Examples with solutions for Root of a Root

Exercise #1

Solve the following exercise:

334= \sqrt[4]{\sqrt[3]{3}}=

Video Solution

Step-by-Step Solution

To simplify the given expression, we will use two laws of exponents:

A. Definition of the root as an exponent:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}}

B. Law of exponents for an exponent on an exponent:

(am)n=amn (a^m)^n=a^{m\cdot n}

Let's begin simplifying the given expression:

334= \sqrt[4]{\sqrt[3]{3}}= \\ We will use the law of exponents shown in A and first convert the roots in the expression to exponents, we will do this in two steps - in the first step we will convert the inner root in the expression and in the next step we will convert the outer root:

334=3134=(313)14= \sqrt[4]{\sqrt[3]{3}}= \\ \sqrt[4]{3^{\frac{1}{3}}}= \\ (3^{\frac{1}{3}})^{\frac{1}{4}}= We continue and use the law of exponents shown in B, then we will multiply the exponents:

(313)14=31314=31134=3112=312 (3^{\frac{1}{3}})^{\frac{1}{4}}= \\ 3^{\frac{1}{3}\cdot\frac{1}{4}}=\\ 3^{\frac{1\cdot1}{3\cdot4}}=\\ \boxed{3^{\frac{1}{12}}}=\\ \boxed{\sqrt[12]{3}} In the final step we return to writing the root, that is - back, using the law of exponents shown in A (in the opposite direction),

Let's summarize the simplification of the given expression:

334=(313)14=3112=312 \sqrt[4]{\sqrt[3]{3}}= \\ (3^{\frac{1}{3}})^{\frac{1}{4}}= \\ \boxed{3^{\frac{1}{12}}}=\\ \boxed{\sqrt[12]{3}} Therefore, note that the correct answer (most) is answer D.

Answer

Answers a + b

Exercise #2

Solve the following exercise:

4= \sqrt{\sqrt{4}}=

Video Solution

Answer

2 \sqrt{2}

Exercise #3

Solve the following exercise:

12= \sqrt{\sqrt{12}}=

Video Solution

Answer

124 \sqrt[4]{12}

Exercise #4

Solve the following exercise:

26= \sqrt[6]{\sqrt{2}}=

Video Solution

Answer

212 \sqrt[12]{2}

Exercise #5

Solve the following exercise:

8= \sqrt[]{\sqrt{8}}=

Video Solution

Answer

814 8^{\frac{1}{4}}

Exercise #6

Solve the following exercise:

26= \sqrt[6]{\sqrt{2}}=

Video Solution

Answer

212 \sqrt[12]{2}

Exercise #7

Solve the following exercise:

11010= \sqrt[10]{\sqrt[10]{1}}=

Video Solution

Answer

All answers are correct.

Exercise #8

Solve the following exercise:

535= \sqrt[5]{\sqrt[3]{5}}=

Video Solution

Answer

515 \sqrt[15]{5}

Exercise #9

Solve the following exercise:

2= \sqrt{\sqrt{2}}=

Video Solution

Answer

24 \sqrt[4]{2}

Exercise #10

Solve the following exercise:

1443= \sqrt[3]{\sqrt{144}}=

Video Solution

Answer

1446 \sqrt[6]{144}

Exercise #11

Complete the following exercise:

5x4= \sqrt[]{\sqrt{5x^4}}=

Video Solution

Answer

54x \sqrt[4]{5}\cdot x

Exercise #12

Complete the following exercise:

x88= \sqrt[8]{\sqrt{x^8}}=

Video Solution

Answer

x \sqrt{x}

Exercise #13

Complete the following exercise:

64x12=3 \sqrt[3]{\sqrt{64\cdot x^{12}}=}

Video Solution

Answer

2x2 2x^2

Exercise #14

Complete the following exercise:

81x4= \sqrt{\sqrt{81\cdot x^4}}=

Video Solution

Answer

3x 3x

Exercise #15

Complete the following exercise:

16x2= \sqrt{\sqrt{16\cdot x^2}}=

Video Solution

Answer

2x 2\sqrt{x}

Topics learned in later sections

  1. Combining Powers and Roots
  2. Square Root Rules