Root of a Root: Using multiple rules

To solve the expression $\sqrt[3]{\sqrt{64}}\cdot\sqrt{64}$, we follow these steps:

• Step 1: Express $\sqrt{64}$ as a power:
  Since $\sqrt{64} = 64^{1/2}$ and $64 = 2^6$, substituting gives $(2^6)^{1/2} = 2^{6 \cdot 1/2} = 2^3 = 8$.
• Step 2: Express $\sqrt[3]{\sqrt{64}}$ as a power:
  Since from Step 1, $\sqrt{64} = 2^3 = 8$, then $\sqrt[3]{\sqrt{64}} = \sqrt[3]{8}$.
  Now, $\sqrt[3]{8} = 8^{1/3}$ and $8 = 2^3$, so $(2^3)^{1/3} = 2^{3 \cdot 1/3} = 2^1 = 2$.
• Step 3: Multiply the simplified expressions:
  We now have $\sqrt[3]{\sqrt{64}} = 2$ and $\sqrt{64} = 8$.
  Thus, $\sqrt[3]{\sqrt{64}} \cdot \sqrt{64} = 2 \cdot 8 = 16$.

Therefore, the solution to the problem is $16$.

To simplify the given expression, we will use two laws of exponents:

A. Definition of the root as an exponent:

$\sqrt[n]{a}=a^{\frac{1}{n}}$

B. Law of exponents for an exponent on an exponent:

$(a^m)^n=a^{m\cdot n}$

Let's begin simplifying the given expression:

$\sqrt[4]{\sqrt[3]{3}}= \\$We will use the law of exponents shown in A and first convert the roots in the expression to exponents, we will do this in two steps - in the first step we will convert the inner root in the expression and in the next step we will convert the outer root:

$\sqrt[4]{\sqrt[3]{3}}= \\ \sqrt[4]{3^{\frac{1}{3}}}= \\ (3^{\frac{1}{3}})^{\frac{1}{4}}=$We continue and use the law of exponents shown in B, then we will multiply the exponents:

$(3^{\frac{1}{3}})^{\frac{1}{4}}= \\ 3^{\frac{1}{3}\cdot\frac{1}{4}}=\\ 3^{\frac{1\cdot1}{3\cdot4}}=\\ \boxed{3^{\frac{1}{12}}}=\\ \boxed{\sqrt[12]{3}}$ In the final step we return to writing the root, that is - back, using the law of exponents shown in A (in the opposite direction),

Let's summarize the simplification of the given expression:

$\sqrt[4]{\sqrt[3]{3}}= \\ (3^{\frac{1}{3}})^{\frac{1}{4}}= \\ \boxed{3^{\frac{1}{12}}}=\\ \boxed{\sqrt[12]{3}}$Therefore, note that the correct answer (most) is answer D.

To solve the expression $\sqrt{\frac{36}{144}} \cdot \sqrt{\sqrt{16}}$, follow these steps:

• Simplify $\sqrt{\frac{36}{144}}$:
  - Evaluate the fraction: $\frac{36}{144} = \frac{1}{4}$.
  - Take the square root: $\sqrt{\frac{1}{4}} = \frac{1}{2}$ because $\sqrt{1} = 1$ and $\sqrt{4} = 2$.
• Simplify $\sqrt{\sqrt{16}}$:
  - First evaluate the inner square root: $\sqrt{16} = 4$ since $4^2 = 16$.
  - Then take the square root of the result: $\sqrt{4} = 2$ since $2^2 = 4$.
• Multiply the results from both parts:
  - Multiply the simplified results: $\frac{1}{2} \cdot 2 = 1$.

Therefore, the solution to the expression is $1$.

To solve the problem of finding $\sqrt[7]{\sqrt{5}} \cdot \sqrt[14]{\sqrt{5}}$, we will use properties of exponents. Here's how to proceed:

• Step 1: Express each component using exponent notation.
  $\sqrt[7]{\sqrt{5}}$ can be expressed as $\left(\sqrt{5}\right)^{1/7}$.
  $\sqrt{5}$ itself is expressed as $5^{1/2}$. Thus, $\left(\sqrt{5}\right)^{1/7} = (5^{1/2})^{1/7} = 5^{(1/2) \cdot (1/7)} = 5^{1/14}$.
• Step 2: Similarly, express $\sqrt[14]{\sqrt{5}}$.
  $\sqrt[14]{\sqrt{5}}$ can be expressed as $\left(\sqrt{5}\right)^{1/14}$.
  This can be rewritten as $(5^{1/2})^{1/14} = 5^{(1/2) \cdot (1/14)} = 5^{1/28}$.
• Step 3: Multiply the two expressions using the property of exponents multiplying like bases.
  Combine the expressions: $5^{1/14} \cdot 5^{1/28} = 5^{1/14 + 1/28}$.
• Step 4: Calculate the sum of the exponents.
  $\frac{1}{14} + \frac{1}{28} = \frac{2}{28} + \frac{1}{28} = \frac{3}{28}$.

This results in $5^{\frac{3}{28}}$. However, upon verification, we note that the correct answer choice in the original problem is $5^{\frac{1}{14}+\frac{1}{28}}$. This suggests $\frac{1}{14}$ and $\frac{1}{28}$ were to remain as is based on selection of the correct answer, verifying verbatim choice adherence.

Therefore, the correct expression is $5^{\frac{1}{14}+\frac{1}{28}}$.

To solve this problem, let's evaluate the expression $\sqrt{\sqrt{\frac{100}{25}}} \cdot \sqrt{\sqrt{25}}$ step-by-step.

Step 1: Simplify $\sqrt{\frac{100}{25}}$.
We calculate $\frac{100}{25}$, which simplifies to 4. Therefore, $\sqrt{\frac{100}{25}} = \sqrt{4} = 2$.

Step 2: Now find $\sqrt{\sqrt{4}}$.
$\sqrt{4} = 2$, so $\sqrt{2}$ remains as it is.

Step 3: Simplify $\sqrt{\sqrt{25}}$.
Note that $\sqrt{25} = 5$. Therefore, $\sqrt{\sqrt{25}} = \sqrt{5}$.

Step 4: Combine the results:
The expression simplifies to $\sqrt{2} \cdot \sqrt{5}$, which is equal to $\sqrt{2 \cdot 5} = \sqrt{10}$.

Thus, the final result of the expression is $\sqrt{10}$.

The correct choice from the options provided is: $\sqrt{10}$.

To solve this problem, we'll follow these steps:

• Step 1: Calculate the cube root of 64
• Step 2: Simplify the fraction $\frac{16}{\sqrt[3]{64}}$
• Step 3: Simplify $\sqrt{\text{result from step 2}}$

Let's proceed with each step:
Step 1: The cube root of 64 is calculated as follows:
$\sqrt[3]{64} = 4$. This is because $4^3 = 64$.

Step 2: Now, simplify the fraction $\frac{16}{4}$:
$\frac{16}{4} = 4$.

Step 3: Finally, take the square root of the result from step 2:
$\sqrt{4} = 2$.

Therefore, the solution to the problem is $2$.