Number Comparison: Determining the Largest Value in a Set

Question

Choose the largest value:

Video Solution

Solution Steps

00:00 Choose the largest value
00:03 A 'regular' root raised to the second power
00:06 A root of the second order is like a power with the inverse of 2
00:10 Apply the same method to the following expressions to determine the largest value
00:18 This is the solution
00:21 Chapter Title

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Convert each expression into exponential form.
  • Step 2: Compare the resulting expressions by examining the exponents.
  • Step 3: Identify which expression corresponds to the largest value.

Let's work through the solution:

Step 1: Convert each root to exponential form:
- 2=20.5 \sqrt{2} = 2^{0.5}
- 23=21/320.333 \sqrt[3]{2} = 2^{1/3} \approx 2^{0.333}
- 24=21/420.25 \sqrt[4]{2} = 2^{1/4} \approx 2^{0.25}
- 25=21/520.2 \sqrt[5]{2} = 2^{1/5} \approx 2^{0.2}

Step 2: Compare the exponents 0.50.5, 0.3330.333, 0.250.25, and 0.20.2. Clearly, 0.50.5 is the largest among these values.

Step 3: The expression with the largest exponent is 2=20.5 \sqrt{2} = 2^{0.5} , so 2 \sqrt{2} is the largest value.

Therefore, the solution to the problem is 2 \sqrt{2} .

Answer

2 \sqrt{2}