Root of a Root: Number of terms

Complete the following exercise:

$\sqrt[3]{\sqrt{16}}\cdot\sqrt[]{\sqrt{16}}=$

$16^{\frac{5}{12}}$

Complete the following exercise:

$\sqrt{\sqrt{4}}\cdot\sqrt{\sqrt{2}}=$

$2^{\frac{1}{4}}\sqrt{2}$

Complete the following exercise:

$\sqrt{\sqrt{49}}\cdot\sqrt{\sqrt{16}}=$

$2\sqrt{7}$

Complete the following exercise:

$\sqrt{25}\cdot\sqrt[3]{\sqrt{25}}=$

$5^{1\frac{1}{3}}$

Complete the following exercise:

$\sqrt{\sqrt{16}}\cdot\sqrt{\sqrt{8}}=$

$$$\sqrt[4]{128}$

Complete the following exercise:

$\sqrt{\sqrt{2}}\cdot\sqrt{\sqrt{4}}=$

$\sqrt[4]{8}$

Complete the following exercise:

$\sqrt[3]{\sqrt{25}}\cdot\sqrt[3]{\sqrt{64}}=$

$2\sqrt[3]{5}$

Complete the following exercise:

$\sqrt[5]{\sqrt{3}}\cdot\sqrt[6]{\sqrt{3}}=$

$3^{\frac{1}{10}+\frac{1}{12}}$

Complete the following exercise:

$\sqrt[3]{\sqrt{3}}\cdot\sqrt[3]{\sqrt{4}}=$

$\sqrt[6]{12}$

Complete the following exercise:

$\sqrt[5]{\sqrt{3}}\cdot\sqrt[5]{\sqrt{3}}=$

$\sqrt[10]{9}$

Complete the following exercise:

$\sqrt[3]{\sqrt{64}}\cdot\sqrt[3]{64}=$

8

Complete the following exercise:

$\sqrt[6]{\sqrt{64}}\cdot\sqrt[4]{\sqrt[3]{16}}=$

$\sqrt[12]{1024}$