Examples with solutions for Root of a Root: Applying the formula

Exercise #1

Solve the following exercise:

535= \sqrt[5]{\sqrt[3]{5}}=

Video Solution

Step-by-Step Solution

To solve the problem of finding 535 \sqrt[5]{\sqrt[3]{5}} , we'll use the formula for a root of a root, which combines the exponents:

  • Step 1: Express each root as an exponent.
    We start with the innermost root: 53=51/3 \sqrt[3]{5} = 5^{1/3} .
  • Step 2: Apply the outer root.
    The square root to the fifth power is expressed as: 51/35=(51/3)1/5 \sqrt[5]{5^{1/3}} = (5^{1/3})^{1/5} .
  • Step 3: Combine the exponents.
    Using the exponent rule (am)n=am×n(a^m)^n = a^{m \times n}, we get:
    (51/3)1/5=5(1/3)×(1/5)=51/15(5^{1/3})^{1/5} = 5^{(1/3) \times (1/5)} = 5^{1/15}.
  • Step 4: Convert the exponent back to root form.
    This can be written as 515 \sqrt[15]{5} .

Therefore, the simplified expression of 535 \sqrt[5]{\sqrt[3]{5}} is 515 \sqrt[15]{5} .

Answer

515 \sqrt[15]{5}

Exercise #2

Solve the following exercise:

4= \sqrt{\sqrt{4}}=

Video Solution

Step-by-Step Solution

To solve the expression 4\sqrt{\sqrt{4}}, we'll proceed with the following steps:

  • Step 1: Evaluate the inner square root.
    The expression 4\sqrt{4} simplifies to 2, because 2 squared is 4.
  • Step 2: Now evaluate the square root of 2.
    Since the result from step 1 is 2, we need to find 2\sqrt{2}. This is the prime representation of the result because 2 cannot be further simplified.

Therefore, the answer to the problem 4\sqrt{\sqrt{4}} is 2\sqrt{2}.

Answer

2 \sqrt{2}

Exercise #3

Solve the following exercise:

26= \sqrt[6]{\sqrt{2}}=

Video Solution

Step-by-Step Solution

Let's use the definition of root as a power:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}}

when we remember that in a square root (also called "root to the power of 2") we don't write the root's power and:

n=2 n=2

meaning:

a=a2=a12 \sqrt{a}=\sqrt[2]{a}=a^{\frac{1}{2}}

Let's return to the problem and convert using the root definition we mentioned above the roots in the problem:

26=2126=(212)16 \sqrt[6]{\sqrt{2}}=\sqrt[6]{2^{\frac{1}{2}}}=\big(2^{\frac{1}{2}}\big)^{\frac{1}{6}}

where in the first stage we applied the root definition as a power mentioned earlier to the inner expression (meaning inside the larger-outer root) and then we used parentheses and applied the same definition to the outer root.

Now let's remember the power law for power of a power:

(am)n=amn (a^m)^n=a^{m\cdot n}

Let's apply this law to the expression we got in the last stage:

(212)16=21216=21126=2112 \big(2^{\frac{1}{2}}\big)^{\frac{1}{6}}=2^{\frac{1}{2}\cdot\frac{1}{6}}=2^{\frac{1\cdot1}{2\cdot6}}=2^{\frac{1}{12}}

where in the first stage we applied the power law mentioned above and then simplified the resulting expression and performed the multiplication of fractions in the power exponent.

Let's summarize the solution steps so far, we got that:

26=(212)16=2112 \sqrt[6]{\sqrt{2}}=\big(2^{\frac{1}{2}}\big)^{\frac{1}{6}} =2^{\frac{1}{12}}

In the next stage we'll apply again the root definition as a power that was mentioned at the beginning of the solution, but in the opposite direction:

a1n=an a^{\frac{1}{n}} = \sqrt[n]{a}

Let's apply this law to go back and present the expression we got in the last stage in root form:

2112=212 2^{\frac{1}{12}} =\sqrt[12]{2}

Therefore we got that:

26=2112=212 \sqrt[6]{\sqrt{2}}=2^{\frac{1}{12}} =\sqrt[12]{2}

Therefore the correct answer is answer A.

Answer

212 \sqrt[12]{2}

Exercise #4

Solve the following exercise:

26= \sqrt[6]{\sqrt{2}}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll simplify the expression 26 \sqrt[6]{\sqrt{2}} using the rule for roots of roots. This rule states that a root of a root can be written as a single root by multiplying the indices of the radicals.

  • Step 1: Identify the given expression 26 \sqrt[6]{\sqrt{2}} .
  • Step 2: Recognize that the inner root, 2\sqrt{2}, can be expressed as 22\sqrt[2]{2}.
  • Step 3: Visualize 26 \sqrt[6]{\sqrt{2}} as 226 \sqrt[6]{\sqrt[2]{2}} .
  • Step 4: Apply the rule amn=an×m\sqrt[n]{\sqrt[m]{a}} = \sqrt[n \times m]{a}.
  • Step 5: Multiply the indices: 6×2=126 \times 2 = 12.
  • Step 6: Replace the compound root with the single root: 212\sqrt[12]{2}.

Thus, the expression 26 \sqrt[6]{\sqrt{2}} simplifies to 212 \sqrt[12]{2} .

Therefore, the solution to the problem is 212 \sqrt[12]{2} .

Answer

212 \sqrt[12]{2}

Exercise #5

Solve the following exercise:

12= \sqrt{\sqrt{12}}=

Video Solution

Step-by-Step Solution

To solve the expression 12 \sqrt{\sqrt{12}} , we simplify using the properties of exponents and roots. Specifically, we apply the rule that states that the square root of a square root can be expressed as a fourth root.

Let's break down this solution step by step:

  • First, represent the inner 12 \sqrt{12} as a power: 121/2 12^{1/2} .
  • Next, take the square root of this result, which involves raising 121/2 12^{1/2} to the power of 1/2 1/2 again:
    (121/2)1/2=12(1/2)(1/2)=121/4\left(12^{1/2}\right)^{1/2} = 12^{(1/2) \cdot (1/2)} = 12^{1/4}.
  • According to the rules of exponents, raising an exponent to another power results in multiplying the exponents.
  • This gives us 121/4 12^{1/4} , which we can write as the fourth root of 12: 124 \sqrt[4]{12} .

We conclude that the simplification of 12 \sqrt{\sqrt{12}} is 124 \sqrt[4]{12} .

Answer

124 \sqrt[4]{12}

Exercise #6

Solve the following exercise:

2= \sqrt{\sqrt{2}}=

Video Solution

Step-by-Step Solution

To solve 2\sqrt{\sqrt{2}}, we will use the property of roots.

  • Step 1: Recognize that 2\sqrt{\sqrt{2}} involves two square roots.
  • Step 2: Each square root can be expressed using exponents: 2=21/2\sqrt{2} = 2^{1/2}.
  • Step 3: Therefore, 2=(21/2)1/2\sqrt{\sqrt{2}} = (2^{1/2})^{1/2}.
  • Step 4: Apply the formula for the root of a root: (xa)b=xab(x^{a})^{b} = x^{ab}.
  • Step 5: For (21/2)1/2(2^{1/2})^{1/2}, this means we compute the product of the exponents: (1/2)×(1/2)=1/4(1/2) \times (1/2) = 1/4.
  • Step 6: The expression simplifies to 21/42^{1/4}, which is written as 24\sqrt[4]{2}.

Therefore, 2=24\sqrt{\sqrt{2}} = \sqrt[4]{2}.

This corresponds to choice 2: 24 \sqrt[4]{2} .

The solution to the problem is 24 \sqrt[4]{2} .

Answer

24 \sqrt[4]{2}

Exercise #7

Solve the following exercise:

11010= \sqrt[10]{\sqrt[10]{1}}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll observe the following process:

  • Step 1: Recognize the expression 11010 \sqrt[10]{\sqrt[10]{1}} involves nested roots.
  • Step 2: Apply the formula for nested roots: xmn=xnm \sqrt[n]{\sqrt[m]{x}} = \sqrt[n \cdot m]{x} .
  • Step 3: Set n=10 n = 10 and m=10 m = 10 , resulting in 110×10=1100 \sqrt[10 \times 10]{1} = \sqrt[100]{1} .
  • Step 4: Simplify 1100 \sqrt[100]{1} . Any root of 1 is 1, as 1k=1 1^k = 1 for any positive rational number k k .

Thus, the evaluation of the original expression 11010 \sqrt[10]{\sqrt[10]{1}} equals 1.

Comparing this result to the provided choices:

  • Choice 1 is 1 1 .
  • Choice 2 is 1100 \sqrt[100]{1} , which is also 1.
  • Choice 3 is 1=1 \sqrt{1} = 1 .
  • Choice 4 states all answers are correct.

Therefore, choice 4 is correct: All answers are equivalent to the solution, being 1.

Thus, the correct selection is: All answers are correct.

Answer

All answers are correct.

Exercise #8

Solve the following exercise:

8= \sqrt[]{\sqrt{8}}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Convert the inner square root to an exponent: 8=81/2\sqrt{8} = 8^{1/2}.
  • Step 2: Apply the root of a root property: 8=(8)1/2=(81/2)1/2\sqrt{\sqrt{8}} = (\sqrt{8})^{1/2} = (8^{1/2})^{1/2}.
  • Step 3: Simplify the expression using exponent rules: (81/2)1/2=8(1/2)(1/2)=81/4(8^{1/2})^{1/2} = 8^{(1/2) \cdot (1/2)} = 8^{1/4}.

The nested root expression simplifies to 81/48^{1/4}.

Therefore, the simplified expression of 8\sqrt{\sqrt{8}} is 814 8^{\frac{1}{4}} .

After comparing this result with the multiple choice answers, choice 2 is correct.

Answer

814 8^{\frac{1}{4}}

Exercise #9

Solve the following exercise:

1447= \sqrt[7]{\sqrt[4]{14}}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the inner and outer roots.
  • Step 2: Apply the root of a root formula.
  • Step 3: Calculate the combined root.

Now, let's work through each step:

Step 1: The expression given is 1447 \sqrt[7]{\sqrt[4]{14}} . The inner root is 144 \sqrt[4]{14} , and the outer root is ()7 \sqrt[7]{(\cdot)} .

Step 2: Use the formula for the root of a root: xmn=xnm \sqrt[n]{\sqrt[m]{x}} = \sqrt[n \cdot m]{x} .

Step 3: Plug in our values: n=7 n = 7 and m=4 m = 4 . Thus, we have:

1447=147×4=1428 \sqrt[7]{\sqrt[4]{14}} = \sqrt[7 \times 4]{14} = \sqrt[28]{14}

Therefore, the simplified form of the given expression is 1428 \sqrt[28]{14} .

Answer

1428 \sqrt[28]{14}

Exercise #10

Solve the following exercise:

100510= \sqrt[10]{\sqrt[5]{100}}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Use the formula for the nested radical: 100510=10010×5 \sqrt[10]{\sqrt[5]{100}} = \sqrt[10 \times 5]{100} .
  • Step 2: Calculate the product of the indices of the roots: 10×5=50 10 \times 5 = 50 .
  • Step 3: Write the simplified expression: 10050 \sqrt[50]{100} .

Let's apply these steps to find the solution:

First, we apply the root of a root property:
100510=10010×5 \sqrt[10]{\sqrt[5]{100}} = \sqrt[10 \times 5]{100}

This simplifies to:
10050 \sqrt[50]{100}

Therefore, the solution to the problem is 10050 \sqrt[50]{100} .

Answer

10050 \sqrt[50]{100}

Exercise #11

Solve the following exercise:

64= \sqrt[4]{\sqrt{6}}=

Video Solution

Step-by-Step Solution

To solve 64 \sqrt[4]{\sqrt{6}} , we'll simplify it using the property of roots:

According to the property xmn=xnm \sqrt[n]{\sqrt[m]{x}} = \sqrt[n \cdot m]{x} , we are to multiply the indices of the roots.

Here, the indices are 4 (for the fourth root) and 2 (for the square root), hence n=4 n = 4 and m=2 m = 2 .

Therefore, we calculate:

4×2=8 4 \times 2 = 8

This indicates that the expression can be rewritten as a single root of index 8, giving us:

64=68 \sqrt[4]{\sqrt{6}} = \sqrt[8]{6}

The answer is therefore 68 \sqrt[8]{6} , which matches answer choice 4.

Answer

68 \sqrt[8]{6}

Exercise #12

Solve the following exercise:

27= \sqrt[7]{\sqrt{2}}=

Video Solution

Step-by-Step Solution

Let's solve the given problem by following these steps:

  • Step 1: Recognize the expression 27 \sqrt[7]{\sqrt{2}} . It involves two roots.
  • Step 2: Rewrite each part using rational exponents. We have 2=21/2 \sqrt{2} = 2^{1/2} .
  • Step 3: Substitute back, giving 21/27 \sqrt[7]{2^{1/2}} or (21/2)1/7(2^{1/2})^{1/7}.
  • Step 4: Use the properties of exponents: (am)n=amn (a^m)^n = a^{m \cdot n} .
  • Step 5: Calculate the exponent: (1/2)(1/7)=1/14 (1/2) \cdot (1/7) = 1/14 .
  • Step 6: This gives us 21/14 2^{1/14} , which is equal to 214\sqrt[14]{2}.

Thus, the simplified expression is 214 \sqrt[14]{2} .

Therefore, the solution to the problem is 214 \sqrt[14]{2} .

Answer

214 \sqrt[14]{2}

Exercise #13

Solve the following exercise:

7293= \sqrt[3]{\sqrt{729}}=

Video Solution

Step-by-Step Solution

To solve this problem, we need to evaluate 7293\sqrt[3]{\sqrt{729}}.

Step 1: Convert the expression into exponent form. We know 729=72912 \sqrt{729} = 729^{\frac{1}{2}} . Thus, 7293=(72912)13\sqrt[3]{\sqrt{729}} = (729^{\frac{1}{2}})^{\frac{1}{3}}.

Step 2: Apply the formula for exponents (am)n=amn(a^m)^n = a^{m \cdot n}. Thus, (72912)13=729121/3=72916(729^{\frac{1}{2}})^{\frac{1}{3}} = 729^{\frac{1}{2 \cdot 1/3}} = 729^{\frac{1}{6}}.

Step 3: Find the base of 729 as a power of an integer. Observing, 729 = 363^6 because 36=7293^6 = 729.

Step 4: Substitute the power of the base: 72916=(36)16=3616=31=3729^{\frac{1}{6}} = (3^6)^{\frac{1}{6}} = 3^{6 \cdot \frac{1}{6}} = 3^1 = 3.

Therefore, the solution to the problem is 7293=3\sqrt[3]{\sqrt{729}} = 3.

Answer

3

Exercise #14

Solve the following exercise:

1443= \sqrt[3]{\sqrt{144}}=

Video Solution

Step-by-Step Solution

To solve this problem, let's follow these steps:

  • Express the square root as a fractional exponent.
  • Express the cube root as another fractional exponent.
  • Multiply the exponents together using the rule (am)n=am×n(a^m)^n = a^{m \times n}.
  • Recapture the result as a root expression.

Let's apply these steps:
Step 1: The square root of 144 can be expressed as 1441/2144^{1/2}.
Step 2: We need the cube root of this expression, so we have (1441/2)1/3(144^{1/2})^{1/3}.
Step 3: Using the property of exponents (am)n=am×n(a^m)^n = a^{m \times n}, we multiply the exponents: (1441/2)1/3=144(1/2)×(1/3)=1441/6(144^{1/2})^{1/3} = 144^{(1/2) \times (1/3)} = 144^{1/6}.
Step 4: Re-express this as a root: Since 1441/6144^{1/6} is equivalent to the sixth root, we have 1446\sqrt[6]{144}.

Therefore, the solution to the problem is 1446\sqrt[6]{144}, which corresponds to choice 3.

Answer

1446 \sqrt[6]{144}

Exercise #15

Solve the following exercise:

1634= \sqrt[4]{\sqrt[3]{16}}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll convert the roots into exponents and simplify:

  • Step 1: Express the nested radicals in terms of exponents.
  • Step 2: Simplify by multiplying the exponents.
  • Step 3: Compare the simplified result to the given choices.

Now, let's work through each step:
Step 1: The cube root of 16 can be written as 1613 16^{\frac{1}{3}} . Thus, our expression becomes 16134 \sqrt[4]{16^{\frac{1}{3}}} .
Step 2: Apply the fourth root, which is an exponent of 14\frac{1}{4}. This gives us (1613)14=161314=16112 (16^{\frac{1}{3}})^{\frac{1}{4}} = 16^{\frac{1}{3} \cdot \frac{1}{4}} = 16^{\frac{1}{12}} .
Step 3: From the original question, the expression simplifies to 16112 16^{\frac{1}{12}} , which is equivalent to 1612 \sqrt[12]{16} . Therefore, the choices that are correct are the ones that reflect this equivalence.

Therefore, the solution to the problem involves recognizing that both 16112 16^{\frac{1}{12}} and 1612 \sqrt[12]{16} represent the same value, and thus, answers a and b are correct.

Answer

Answers a and b are correct

Exercise #16

Solve the following exercise:

643= \sqrt[3]{\sqrt{64}}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll express the nested roots using exponents and then simplify:

We start with the inner expression:

64\sqrt{64} is equivalent to 641/264^{1/2}.

Next, apply the cube root:

641/23\sqrt[3]{64^{1/2}} is equivalent to (641/2)1/3(64^{1/2})^{1/3}.

Using properties of exponents, we simplify the expression:

(641/2)1/3=64(1/2)(1/3)=641/6(64^{1/2})^{1/3} = 64^{(1/2) \cdot (1/3)} = 64^{1/6}.

Now, evaluate 641/664^{1/6}:

Since 64=2664 = 2^6, we have:

641/6=(26)1/6=26(1/6)=21=264^{1/6} = (2^6)^{1/6} = 2^{6 \cdot (1/6)} = 2^{1} = 2.

Therefore, the solution to the exercise 643 \sqrt[3]{\sqrt{64}} is 2\mathbf{2}.

Answer

2

Exercise #17

Solve the following exercise:

625= \sqrt{\sqrt{625}}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Evaluate the innermost square root, 625 \sqrt{625} .
  • Step 2: Evaluate the square root of the result from Step 1.

Now, let's work through each step:

Step 1: Evaluate 625 \sqrt{625} .
The square root of 625 is 25, since 25×25=625 25 \times 25 = 625 . Thus, 625=25 \sqrt{625} = 25 .

Step 2: Evaluate 25 \sqrt{25} .
The square root of 25 is 5, since 5×5=25 5 \times 5 = 25 . Thus, 25=5 \sqrt{25} = 5 .

Therefore, the solution to the problem 625 \sqrt{\sqrt{625}} is 5.

Answer

5

Exercise #18

Solve the following exercise:

10245= \sqrt[5]{\sqrt[]{1024}}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Simplify the inner square root.
  • Step 2: Apply the formula for nested roots.
  • Step 3: Compute the fifth root.

Now, let's work through each step:

Step 1: Calculate the inner square root.
We have 1024\sqrt{1024}. We know that 1024=2101024 = 2^{10}, so 1024=210\sqrt{1024} = \sqrt{2^{10}}.

Applying the property of roots, 210=2102=25=32\sqrt{2^{10}} = 2^{\frac{10}{2}} = 2^5 = 32.

Step 2: Now, apply the fifth root to the result from step 1.
We need to find 325\sqrt[5]{32}.

Step 3: Simplify using the properties of exponents.
From 325=255\sqrt[5]{32} = \sqrt[5]{2^5}, we have 255=21=22^{\frac{5}{5}} = 2^1 = 2.

Therefore, the solution to the problem is 2 2 .

Answer

2

Exercise #19

Complete the following exercise:

363= \sqrt[3]{\sqrt{36}}=

Video Solution

Step-by-Step Solution

To solve this problem, let's analyze and simplify the given expression 363\sqrt[3]{\sqrt{36}}.

  • Step 1: Identify the root operations. We have a square root, 36\sqrt{36}, and a cube root, 3\sqrt[3]{\ldots}.

  • Step 2: Use the formula for roots for a root of a root: xnm=x1mn \sqrt[m]{\sqrt[n]{x}} = x^{\frac{1}{mn}} .

  • Step 3: Apply this formula to the problem. In this case, the first operation is a square root, which can be written as 3612 36^{\frac{1}{2}} , and the second operation is a cube root. Therefore, 363=(3612)13\sqrt[3]{\sqrt{36}} = (36^{\frac{1}{2}})^{\frac{1}{3}}.

  • Step 4: Simplify using the power of a power rule, which allows us to multiply exponents: (3612)13=3612×3=3616(36^{\frac{1}{2}})^{\frac{1}{3}} = 36^{\frac{1}{2 \times 3}} = 36^{\frac{1}{6}} .

Thus, the expression 363\sqrt[3]{\sqrt{36}} simplifies to 361636^{\frac{1}{6}}.

Answer

3616 36^{\frac{1}{6}}

Exercise #20

Solve the following exercise:

51233= \sqrt[3]{\sqrt[3]{512}}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll proceed with the following steps:

  • Step 1: Compute 5123 \sqrt[3]{512} .
    Given 512 512 , recognize that 512=29 512 = 2^9 since 29=512 2^9 = 512 . Thus, we have:
    • 5123=293=29/3=23=8 \sqrt[3]{512} = \sqrt[3]{2^9} = 2^{9/3} = 2^3 = 8 .
  • Step 2: Compute 83 \sqrt[3]{8} .
    From Step 1, we found 5123=8 \sqrt[3]{512} = 8 . Now find 83 \sqrt[3]{8} :
    • 83=233=23/3=2 \sqrt[3]{8} = \sqrt[3]{2^3} = 2^{3/3} = 2 .

Therefore, the solution to the expression 51233 \sqrt[3]{\sqrt[3]{512}} is 2 2 .

Answer

2