−3(4a+8)=27a
a=?
\( -3(4a+8)=27a \)
\( a=\text{?} \)
\( 4(\frac{b}{2}+b)-\frac{1}{3}=6b \)
\( b=\text{?} \)
Solve for X:
\( 8+2(x+1)=7x \)
Solve for X:
\( 3-(x-4)+8x=14 \)
\( \frac{1}{4}a+5=20+a \)
\( a=\text{?} \)
To open the parentheses on the left side, we'll use the formula:
We'll arrange the equation so that the terms with 'a' are on the right side, and maintain the plus and minus signs during the transfer:
Let's group the terms on the right side:
Let's divide both sides by 39:
Note that we can reduce the fraction since both numerator and denominator are divisible by 3:
First, we'll open the parentheses by multiplying each term by 4:
Let's solve the multiplication exercise
Now the equation is:
We'll combine the left side between the two b terms and get:
We'll reduce both sides by 6b and get:
Since the result obtained is impossible, the exercise has no solution.
No solution
Solve for X:
Solve for X:
\( 4y-7+6y=3-10y \)
\( y=? \)
\( 37b+6b+56=90+9 \)
\( b=\text{?} \)
\( 6c+7+4c=3(c-1) \)
\( c=\text{?} \)
\( 7y+10y+5=2(y+3) \)
\( y=\text{?} \)
Solve for X:
\( 6\cdot(5+2x)=3x-6 \)
1
Solve for X:
Solve for X:
\( (3-2x)\cdot5=4+12x \)
\( a^4+7a-5=2a+a^4+3a-(-a) \)
\( a=? \)
\( 3x+\frac{2}{3}=4(x+\frac{1}{12}) \)
\( x=\text{?} \)
\( 12y+3y-10+7(y-4)=2y \)
\( y=? \)
\( \frac{1}{3}(x+9)=4+\frac{2}{3}x \)
\( x=\text{?} \)
Solve for X:
3-
\( 16a-20a+15=2(5-2a) \)
\( a=\text{?} \)
Solve for X:
\( \frac{1}{2}\cdot(8-x)+\frac{1}{2}x=12-x \)
Solve for X:
\( \frac{1}{4}(x-16)+\frac{3}{4}x=8x-11 \)
\( \)\( (x+2)(2x-4)=2x^2+x+10 \)
\( 2x+45-\frac{1}{3}x=5(x+7) \)
\( x=\text{?} \)
No solution
Solve for X:
Solve for X:
3