Solve for X:
Solve for X:
\( \frac{1}{8}x-\frac{2}{3}x+\frac{1}{5}x=1 \)
\( a+2\frac{1}{2}=4 \)
\( a=\text{?} \)
Solve for X:
\( \frac{1}{3}x-\frac{1}{2}x=3 \)
Solve for X:
\( \frac{1}{8}x+\frac{2}{3}x=3 \)
Solve for X:
\( \frac{2}{5}x+\frac{3}{4}x=1 \)
Solve for X:
The common denominator of 8, 3, and 5 is 120.
Now we multiply each numerator by the corresponding number to reach 120 and thus cancel the fractions and obtain the following equation:
We multiply the exercises in parentheses accordingly:
We will solve the left side (from left to right) and will obtain:
We reduce both sides by
We find that x is equal
Solve for X:
Solve for X:
Solve for X:
Solve for X:
\( \frac{2}{7}x-\frac{2}{3}x=4 \)
\( b-3\frac{4}{5}=-8\frac{3}{5} \)
Solve for X:
\( -\frac{1}{4}x+\frac{2}{3}x-\frac{1}{6}x=2 \)
Solve for X:
\( \frac{1}{4}x-\frac{2}{3}x+\frac{1}{8}x=5 \)
Solve for X:
\( \frac{1}{4}x-\frac{1}{5}x+\frac{2}{3}x-\frac{2}{5}x=1 \)
Solve for X:
Solve for X:
Solve for X:
Solve for X:
Solve for X:
\( \frac{2}{3}x+\frac{1}{4}x-\frac{1}{5}x+\frac{1}{2}x=2 \)
Solve for X:
\( \frac{2}{4}x+\frac{1}{2}x+\frac{3}{8}x-\frac{1}{5}x=1 \)
Solve for X:
Solve for X: