Solving Equations by using Addition/ Subtraction: Monomial

To solve for $a$, we need to isolate it on one side of the equation. Starting with:

$a-5=10$

Add $5$ to both sides to get:

$a-5+5=10+5$

This simplifies to:

$a=15$

Therefore, the solution is$a = 15$.

To solve for $b$, we need to isolate it on one side of the equation. Starting with:

$b+6=14$

Subtract$6$ from both sides to get:

$b+6-6=14-6$

This simplifies to:

$b=8$

Therefore, the solution is $b = 8$.

To solve the equation $x - 5 = -10$, we need to isolate $x$.

Step 1: Add 5 to both sides of the equation to cancel out the -5 on the left side.
$x - 5 + 5 = -10 + 5$
Step 2: Simplify both sides.
$x = -5$
Thus, the solution is $x = -5$.

To solve for $x$, we need to isolate it on one side of the equation. Starting with:

$x+7=12$

Subtract$7$ from both sides to get:

$x+7-7=12-7$

This simplifies to:

$x=5$

Therefore, the solution is $x = 5$.

To solve the equation $x - 7 = 14$, we need to isolate $x$.

Step 1: Add 7 to both sides of the equation to cancel out the -7 on the left side.
$x - 7 + 7 = 14 + 7$
Step 2: Simplify both sides.
$x = 21$
Thus, the solution is $x = 21$.

To solve the equation $x + 9 = 3$, we need to isolate $x$.

Step 1: Subtract 9 from both sides of the equation to cancel out the +9 on the left side.
$x + 9 - 9 = 3 - 9$
Step 2: Simplify both sides.
$x = -6$
Thus, the solution is $x = -6$.

To solve for $y$, we need to isolate it on one side of the equation. Starting with:

$y-4=9$

Add $4$ to both sides to get:

$y-4+4=9+4$

This simplifies to:

$y=13$

Therefore, the solution is $y = 13$.

To solve for $z$, we need to isolate it on one side of the equation. Starting with:

$z+2=8$

Subtract $2$ from both sides to get:

$z+2-2=8-2$

This simplifies to:

$z=6$

Therefore, the solution is $z = 6$.

To solve the question, we need to isolate X.

Since in this case X is negative, we will move it to the other side.

(Remember that when moving terms between sides, their signs change - from positive to negative and from negative to positive).

$72=63+x$

Now, we will also move the 63 to the other side.

(Remember that 63 becomes negative when moving sides).

$72-63=x$

And now let's solve the subtraction exercise:

$9=x$