Solving Equations by using Addition/ Subtraction: Equations with variables on both sides

Solve for X:

$5x-8=10x+22$

First, we arrange the two sections so that the right side contains the values with the coefficient x and the left side the numbers without the x

Let's remember to maintain the plus and minus signs accordingly when we move terms between the sections.

First, we move a$5x$ to the right section and then the 22 to the left side. We obtain the following equation:

$-8-22=10x-5x$

We subtract both sides accordingly and obtain the following equation:

$-30=5x$

We divide both sections by 5 and obtain:

$-6=x$

$-6$

$x+7=14$

7

Solve for X:

$3-x=1$

$2$

Solve for X:

$x+3=5$

$2$

$72-x=63$

$9$

Solve for X:

$x+5=11x$

$\frac{1}{2}$

Solve for X:

$5x+4=7x$

$2$

Solve for X:

$6-7x=-5x+8$

$-1$

Solve for X:

$-3x+8=7x-12$

$2$

Solve for X:

$x+3=-5+2x$

$8$

Solve for X:

$x+3-4x=5x+6-1-8x$

No solution

Solve for X:

$-\frac{1}{3}x+5=\frac{6}{9}x$

$5$

Solve for X:

$\frac{1}{2}x+1=\frac{1}{2}$

$-1$

Solve for X:

$-\frac{1}{4}x+3=\frac{1}{2}$

$10$

Solve for X:

$-\frac{1}{4}+x=-\frac{1}{2}x$

$\frac{1}{6}$

$2x+7-5x-12=-8x+3$

$x=\frac{8}{5}$

Solve for X:

$-\frac{1}{2}x+3=7x-27$

$4$

Solve for X:

$-\frac{1}{4}x+8=3x-\frac{1}{2}$

$2\frac{8}{13}$

Solve for X:

$-\frac{1}{8}x+4=7x-\frac{4}{5}$

$\frac{192}{285}$