Simplify (2×3×7×9) Raised to Power (ab+3): Complete Expression Solution

Question

Simplify:

(2379)ab+3 (2\cdot3\cdot7\cdot9)^{ab+3}

Video Solution

Solution Steps

00:00 Simplify the expression
00:03 When there is a power on a product of terms, all terms are raised to that power
00:13 We will use this formula in our exercise
00:17 Raise each factor to the power
00:32 And this is the solution to the question

Step-by-Step Solution

We begin by using the distributive law of exponents.

(xy)n=xnyn (x\cdot y)^n=x^n\cdot y^n

We apply this property to the given problem :

(2379)ab+3=2ab+33ab+37ab+39ab+3 (2\cdot3\cdot7\cdot9)^{ab+3} =2^{ab+3}3^{ab+3}7^{ab+3}9^{ab+3}

When we apply the power of parentheses to each of the terms of the product inside the parentheses separately and maintain the multiplication.

Therefore, the correct answer is option a.

Answer

2ab+33ab+37ab+39ab+3 2^{ab+3}3^{ab+3}7^{ab+3}9^{ab+3}