Simplify (2×3×7×9) Raised to Power (ab+3): Complete Expression Solution

Exponent Laws with Product Simplification

Simplify:

(2379)ab+3 (2\cdot3\cdot7\cdot9)^{ab+3}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following expression
00:03 When there is a power on a product of terms, all terms are raised to that power
00:13 We will use this formula in our exercise
00:17 Raise each factor to the power
00:32 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Simplify:

(2379)ab+3 (2\cdot3\cdot7\cdot9)^{ab+3}

2

Step-by-step solution

We begin by using the distributive law of exponents.

(xy)n=xnyn (x\cdot y)^n=x^n\cdot y^n

We apply this property to the given problem :

(2379)ab+3=2ab+33ab+37ab+39ab+3 (2\cdot3\cdot7\cdot9)^{ab+3} =2^{ab+3}3^{ab+3}7^{ab+3}9^{ab+3}

When we apply the power of parentheses to each of the terms of the product inside the parentheses separately and maintain the multiplication.

Therefore, the correct answer is option a.

3

Final Answer

2ab+33ab+37ab+39ab+3 2^{ab+3}3^{ab+3}7^{ab+3}9^{ab+3}

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: Distribute exponent to each factor in the product
  • Technique: Apply (ab)n=anbn (a \cdot b)^n = a^n \cdot b^n to all terms
  • Check: Each base gets the same exponent (ab+3) individually ✓

Common Mistakes

Avoid these frequent errors
  • Adding instead of multiplying the base values
    Don't calculate 2×3×7×9 = 378 first and write 378ab+3 378^{ab+3} ! This misses the distributive property completely. Always apply the exponent to each individual factor: 2ab+33ab+37ab+39ab+3 2^{ab+3} \cdot 3^{ab+3} \cdot 7^{ab+3} \cdot 9^{ab+3} .

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why can't I just multiply 2×3×7×9 first and then raise it to the power?

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While mathematically equivalent, the question asks you to simplify using exponent laws. The distributive form 2ab+33ab+37ab+39ab+3 2^{ab+3} \cdot 3^{ab+3} \cdot 7^{ab+3} \cdot 9^{ab+3} shows your understanding of how exponents work with products!

Do I need to simplify 9 as 3²?

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Not necessarily! The problem gives you 9 as a separate factor, so treat it as 9. However, if you want to combine powers of the same base later, you could write 9ab+3=(32)ab+3=32(ab+3) 9^{ab+3} = (3^2)^{ab+3} = 3^{2(ab+3)} .

What if the exponent was just a number like 3?

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The same rule applies! (2379)3=23337393 (2 \cdot 3 \cdot 7 \cdot 9)^3 = 2^3 \cdot 3^3 \cdot 7^3 \cdot 9^3 . The distributive property of exponents works with any exponent - variables or numbers.

How do I remember this exponent rule?

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Think of it as "each factor gets its own copy of the exponent". When you have (abc)n (abc)^n , imagine the exponent n being distributed like gifts - everyone gets one!

Can I leave my answer as separate terms or combine them?

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For this type of problem, leave them separate! The answer 2ab+33ab+37ab+39ab+3 2^{ab+3} \cdot 3^{ab+3} \cdot 7^{ab+3} \cdot 9^{ab+3} clearly shows you applied the exponent law correctly to each factor.

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