Examples with solutions for Extended Distributive Property: Applying the formula

Exercise #1

(a+b)(c+d)= (a+b)(c+d)=

Video Solution

Step-by-Step Solution

Let's simplify the given expression, open the parentheses using the distributive property:

(a+b)(c+d)=ac+ad+bc+bd (\textcolor{red}{a}+\textcolor{blue}{b})(c+d)=\textcolor{red}{a}c+\textcolor{red}{a}d+\textcolor{blue}{b}c+\textcolor{blue}{b}d Therefore, the correct answer is option A.

Answer

ac+ad+bc+bd \text{ac+ad}+bc+bd

Exercise #2

(a+4)(c+3)= (a+4)(c+3)=

Video Solution

Step-by-Step Solution

When we encounter a multiplication exercise of this type, we know that we must use the distributive property.

Step 1: Multiply the first factor of the first parentheses by each of the factors of the second parentheses.

Step 2: Multiply the second factor of the first parentheses by each of the factors of the second parentheses.

Step 3: Group like terms.

 

a * (c+3) =

a*c + a*3

4  * (c+3) =

4*c + 4*3

 

ac+3a+4c+12

 

There are no like terms to simplify here, so this is the solution!

Answer

ac+3a+4c+12 ac+3a+4c+12

Exercise #3

(35+4)×(10+5)= (35+4)\times(10+5)=

Video Solution

Step-by-Step Solution

We begin by opening the parentheses using the extended distributive property to create a long addition exercise:

We then multiply the first term of the left parenthesis by the first term of the right parenthesis.

We multiply the first term of the left parenthesis by the second term of the right parenthesis.

Now we multiply the second term of the left parenthesis by the first term of the left parenthesis.

Finally, we multiply the second term of the left parenthesis by the second term of the right parenthesis.

In the following way:

(35×10)+(35×5)+(4×10)+(4×5)= (35\times10)+(35\times5)+(4\times10)+(4\times5)=

We solve each of the exercises within parentheses:

350+175+40+20= 350+175+40+20=

We solve the exercise from left to right:

350+175=525 350+175=525

525+40=565 525+40=565

565+20=585 565+20=585

Answer

585

Exercise #4

Solve the following exercise:

(74y)(5x+6)= (-7-4y)(5x+6)=

Video Solution

Step-by-Step Solution

We will use the expanded distributive law to simplify the given expression, let's recall it:

(a+b)(c+d)=ac+ad+bc+bd (a+b)(c+d)=ac+ad+bc+bd

First, we'll perform the multiplication between the pairs of parentheses, using the mentioned distributive law, and then we'll combine like terms if possible. We'll do this while paying attention to the correct multiplication of signs:

(74y)(5x+6)=35x4220xy24y (-7-4y)(5x+6)=\\ -35x-42-20xy-24y Therefore, the correct answer is answer A.

Answer

35x4220xy24y -35x-42-20xy-24y

Exercise #5

Solve the following exercise

(2x+3)(5x)= (2x+3)(-5-x)=

Video Solution

Step-by-Step Solution

We will use the extended distribution law to simplify the given expression, let's recall it:

(a+b)(c+d)=ac+ad+bc+bd (a+b)(c+d)=ac+ad+bc+bd

First, we'll perform the multiplication between the pairs of parentheses, using the mentioned distribution law, and then we'll combine like terms if possible. We'll do this while paying attention to the correct multiplication of signs:

(2x+3)(5x)=10x2x2153x=2x213x15 (2x+3)(-5-x)= \\ -10x-2x^2-15-3x=\\ \boxed{-2x^2-13x-15} Therefore, the correct answer is answer D.

Answer

2x213x15 -2x^2-13x-15

Exercise #6

Solve the exercise:

(2xy)(43x)= (2x-y)(4-3x)=

Video Solution

Step-by-Step Solution

We will use the expanded distributive law to simplify the given expression, let's recall it:

(a+b)(c+d)=ac+ad+bc+bd (a+b)(c+d)=ac+ad+bc+bd

First, we'll perform the multiplication between the pairs of parentheses, using the mentioned distributive law, and then we'll combine like terms if possible. We'll do this while paying attention to the correct multiplication of signs:

(2xy)(43x)=8x6x24y+3xy (2x-y)(4-3x)= \\ \boxed{8x-6x^2-4y+3xy} Therefore, the correct answer is answer C.

Answer

8x6x24y+3xy 8x-6x^2-4y+3xy

Exercise #7

Solve the exercise:

(3b+7a)(5a+2b)=? (3b+7a)\cdot(-5a+2b)=\text{?}

Video Solution

Step-by-Step Solution

We will use the expanded distribution law to simplify the given expression, let's recall it:

(a+b)(c+d)=ac+ad+bc+bd (a+b)(c+d)=ac+ad+bc+bd

First, we'll perform the multiplication between the pairs of parentheses using the distribution law mentioned, and then we'll combine like terms if possible. We'll do this while paying attention to the correct multiplication of signs:

(3b+7a)(5a+2b)=15ab+6b235a2+14ab=6b2ab35a2 (3b+7a)(-5a+2b)= \\ -15ab+6b^2-35a^2+14ab=\\ \boxed{6b^2-ab-35a^2} Therefore, the correct answer is answer B.

Answer

ab+6b235a2 -ab+6b^2-35a^2

Exercise #8

(2xy)(43x)= (2x-y)(4-3x)=

Video Solution

Step-by-Step Solution

Let's simplify the given expression by factoring the parentheses using the expanded distributive law:

(a+b)(c+d)=ac+ad+bc+bd (\textcolor{red}{a}+\textcolor{blue}{b})(c+d)=\textcolor{red}{a}c+\textcolor{red}{a}d+\textcolor{blue}{b}c+\textcolor{blue}{b}d Note that that the sign before the term is an inseparable part of it.

We will also apply the laws of sign multiplication and thus we can present any term in parentheses to make things simpler.

(2xy)(43x)(2x+(y))(4+(3x)) (2x-y)(4-3x)\\ (\textcolor{red}{2x}+\textcolor{blue}{(-y)})(4+(-3x))\\ Let's start then by opening the parentheses:

(2x+(y))(4+(3x))2x4+2x(3x)+(y)4+(y)(3x)8x6x24y+3xy (\textcolor{red}{2x}+\textcolor{blue}{(-y)})(4+(-3x))\\ \textcolor{red}{2x}\cdot 4+\textcolor{red}{2x}\cdot(-3x)+\textcolor{blue}{(-y)}\cdot 4+\textcolor{blue}{(-y)} \cdot(-3x)\\ 8x-6x^2-4y+3xy In the operations above we used the sign multiplication laws, and the exponent law for multiplying terms with identical bases:

aman=am+n a^m\cdot a^n=a^{m+n}

In the next step we will combine similar terms. We will define similar terms as terms in which the variables, in this case, x and y, have identical powers (in the absence of one of the unknowns from the expression, we will relate to its power as zero power, since raising any number to the power of zero will yield the result 1).

We will arrange the expression from the highest power to the lowest from left to right (we will relate to the free term as the power of zero),

Note that in the expression we received in the last step there are four different terms, since there is not even one pair of terms in which the unknowns (the variables) have the same power, so the expression we already received, is the final and most simplified expression.

We will settle for arranging it again from the highest power to the lowest from left to right:
8x6x24y+3xy6x2+3xy+8x4y \textcolor{purple}{ 8x}\textcolor{green}{-6x^2}-4y\textcolor{orange}{+3xy}\\ \textcolor{green}{-6x^2}\textcolor{orange}{+3xy}\textcolor{purple}{ +8x}-4y\\ We highlighted the different terms using colors, and as already emphasized before, we made sure that the sign before the term is correct.

We thus received that the correct answer is answer D.

Answer

6x2+3xy+8x4y -6x^2+3xy +8x-4y

Exercise #9

(2x3)×(5x7) (2x-3)\times(5x-7)

Video Solution

Step-by-Step Solution

To answer this exercise, we need to understand how the extended distributive property works:

For example:

(a+1)∗(b+2)

To solve this type of exercises, the following steps must be taken:

Step 1: multiply the first factor of the first parentheses by each of the factors of the second parentheses.

Step 2: multiply the second factor of the first parentheses by each of the factors of the second parentheses.

Step 3: group like terms together.

 

ab∗2ab∗2

 

We start from the first number of the exercise: 2x

2x*5x+2x*-7

10x²-14x

 

We will continue with the second factor: -3

-3*5x+-3*-7

-15x+21

 

We add all the data together:

 

10x²-14x-15x+21

10x²-29x+21

 

Answer

10x229x+21 10x^2-29x+21

Exercise #10

(x+4)(x+3)= (x+4)(x+3)=

Video Solution

Answer

x2+7x+12 x^2+7x+12

Exercise #11

(2x+y)(x+3)= (2x+y)(x+3)=

Video Solution

Answer

2x2+xy+6x+3y 2x^2+xy+6x+3y

Exercise #12

(x+13)(y+4)= (x+13)(y+4)=

Video Solution

Answer

xy+4x+13y+52 xy+4x+13y+52

Exercise #13

(x8)(x+y)= (x-8)(x+y)=

Video Solution

Answer

x2+xy8x8y x^2+xy-8x-8y

Exercise #14

(12x)(x3)= (12-x)(x-3)=

Video Solution

Answer

15x36x2 15x-36-x^2

Exercise #15

(a+15)(5+a)= (a+15)(5+a)=

Video Solution

Answer

a2+20a+75 a^2+20a+75

Exercise #16

(7+b)(a+9)= (7+b)(a+9)=

Video Solution

Answer

ab+7a+9b+63 ab+7a+9b+63

Exercise #17

(x+y)(xy)= (x+y)(x-y)=

Video Solution

Answer

x2y2 x^2-y^2

Exercise #18

(x6)(x+2)= (x-6)(x+2)=

Video Solution

Answer

x24x12 x^2-4x-12

Exercise #19

(x6)(x+8)= (x-6)(x+8)=

Video Solution

Answer

x2+2x48 x^2+2x-48

Exercise #20

(x+2)(x4)= (x+2)(x-4)=

Video Solution

Answer

x22x8 x^2-2x-8