Examples with solutions for Extended Distributive Property: Using variables

Exercise #1

(7x+3)×(10+4)=238 (7x+3)\times(10+4)=238

Video Solution

Step-by-Step Solution

We begin by solving the addition exercise in the right parenthesis:

(7x+3)+14=238 (7x+3)+14=238

We then multiply each of the terms inside of the parentheses by 14:

(14×7x)+(14×3)=238 (14\times7x)+(14\times3)=238

Following this we solve each of the exercises inside of the parentheses:

98x+42=238 98x+42=238

We move the sections whilst retaining the appropriate sign:

98x=23842 98x=238-42

98x=196 98x=196

Finally we divide the two parts by 98:

9898x=19698 \frac{98}{98}x=\frac{196}{98}

x=2 x=2

Answer

2

Exercise #2

(9+17x)×(6+1)=420 (9+17x)\times(6+1)=420

Calculate a X

Video Solution

Step-by-Step Solution

We begin by solving the addition exercise in the right parenthesis:

(9+17x)×7=420 (9+17x)\times7=420

We then multiply each of the terms inside the parentheses by 7:

(9×7)+(17x×7)=420 (9\times7)+(17x\times7)=420

We continue by solving each of the exercises inside of the parentheses:

63+119x=420 63+119x=420

Following this we rearrange the sections whilst maintaining the appropriate sign:

119x=42063 119x=420-63

119x=357 119x=357

Finally we divide the two parts by 119:

119119x=357119 \frac{119}{119}x=\frac{357}{119}

x=3 x=3

Answer

3

Exercise #3

(a+3a)×(5+2)=112 (a+3a)\times(5+2)=112

Calculate a a

Video Solution

Step-by-Step Solution

We begin by solving the two exercises inside of the parentheses:

4a×7=112 4a\times7=112

We then divide each of the sections by 4:

4a×74=1124 \frac{4a\times7}{4}=\frac{112}{4}

In the fraction on the left side we simplify by 4 and in the fraction on the right side we divide by 4:

a×7=28 a\times7=28

Remember that:

a×7=a7 a\times7=a7

Lastly we divide both sections by 7:

a77=287 \frac{a7}{7}=\frac{28}{7}

a=4 a=4

Answer

4

Exercise #4

Calculate the area of the rectangle below in terms of a and b.

a+3a+3a+3b+8b+8b+8

Video Solution

Step-by-Step Solution

Let us begin by reminding ourselves of the formula to calculate the area of a rectangle: width X length

S=wh S=w⋅h

When:

S = area

w = width

h = height

We take data from the sides of the rectangle in the figure.w=b+8 w=b+8 h=a+3 h=a+3

We then substitute the above data into the formula in order to calculate the area of the rectangle:

S=wh=(b+8)(a+3) S=w⋅h = (b+8)(a+3)

We use the formula of the extended distributive property:

(a+b)(c+d)=ac+ad+bc+bd (a+b)(c+d)=ac+ad+bc+bd

We substitute once more and solve the problem as follows:

S=(b+8)(a+3)=(b)(a)+(b)(3)+(8)(a)+(8)(3) S=(b+8)(a+3)=(b)(a)+(b)(3)+(8)(a)+(8)(3)

(b)(a)+(b)(3)+(8)(a)+(8)(3)=ab+3b+8a+24 (b)(a)+(b)(3)+(8)(a)+(8)(3)=ab+3b+8a+24

Therefore, the correct answer is option B: ab+8a+3b+24.

Keep in mind that, since there are only addition operations, the order of the terms in the expression can be changed and, therefore,

ab+3b+8a+24=ab+8a+3b+24 ab+3b+8a+24=ab+8a+3b+24

Answer

ab + 8a + 3b + 24

Exercise #5

Calculate the area of the rectangle

y+2y+2y+2x+5x+5x+5

Video Solution

Step-by-Step Solution

Let's begin by reminding ourselves of the formula to calculate the area of a rectangle: width X length

S=wh S=w⋅h

Where:

S = area

w = width

h = height

We extract the data from the sides of the rectangle in the figure.

w=x+5 w=x+5 h=y+2 h=y+2

We then substitute the above data into the formula in order to calculate the area of the rectangle:

S=wh=(x+5)(y+2) S=w⋅h=(x+5)(y+2)

We use the formula of the extended distributive property:

(a+b)(c+d)=ac+ad+bc+bd (a+b)(c+d)=ac+ad+bc+bd

We once again substitute and solve the problem as follows:

S=(x+5)(y+2)=(x)(y)+(x)(2)+(5)(y)+(5)(2) S=(x+5)(y+2)=(x)(y)+(x)(2)+(5)(y)+(5)(2)

(x)(y)+(x)(2)+(5)(y)+(5)(2)=xy+2x+5y+10 (x)(y)+(x)(2)+(5)(y)+(5)(2)=xy+2x+5y+10

Therefore, the correct answer is option C: xy+2x+5y+10.

Answer

xy+2x+5y+10 xy+2x+5y+10

Exercise #6

Express the area of the rectangle below in terms of y and z.

3y3y3yy+3z

Video Solution

Step-by-Step Solution

Let us begin by reminding ourselves of the formula to calculate the area of a rectangle: width X height

S=wh S=w⋅h

Where:

S = area

w = width

h = height

We must first extract the data from the sides of the rectangle shown in the figure.

w=3y w=3y h=y+3z h=y+3z

We then insert the known data into the formula in order to calculate the area of the rectangle:

S=wh=(y+3z)(3y) S=w⋅h=(y+3z)(3y)

We use the distributive property formula:

a(b+c)=ab+ac a\left(b+c\right)=ab+ac

We substitute all known data and solve as follows:

S=(y+3z)(3y)=(3y)(y+3z) S=(y+3z)(3y)=(3y)(y+3z)

(3y)(y+3z)=(3y)(y)+(3y)(3z) (3y)(y+3z)=(3y)(y)+(3y)(3z)

(3y)(y)+(3y)(3z)=3y2+9yz (3y)(y)+(3y)(3z)=3y^2+9yz

Keep in mind that because there is a multiplication operation, the order of the terms in the expression can be changed, hence:

(y+3z)(3y)=(3y)(y+3z) (y+3z)(3y)=(3y)(y+3z)

Therefore, the correct answer is option D: 3y2+9yz 3y^2+9yz

Answer

3y2+9yz 3y^2+9yz

Exercise #7

Look at the rectangle in the figure.

What is its area?

Video Solution

Step-by-Step Solution

We know that the area of a rectangle is equal to its length multiplied by its width.

We begin by writing an equation with the available data.

(4x+x2)×(3x+8+5x) (4x+x^2)\times(3x+8+5x)

Next we use the distributive property to solve the equation.

(4x×3x)+(4x×8)+(4x×5x)+(x2×3x)+(x2×8)+(x2×5x)= (4x\times3x)+(4x\times8)+(4x\times5x)+(x^2\times3x)+(x^2\times8)+(x^2\times5x)=

We then solve each of the exercises within the parentheses:

12x2+32x+20x2+3x3+16x2+5x3= 12x^2+32x+20x^2+3x^3+16x^2+5x^3=

Finally we add up all the coefficients of X squared and all the coefficients of X cubed and we obtain the following:

48x2+8x3+32x 48x^2+8x^3+32x

Answer

8x3+28x2+44x 8x^3+28x^2+44x

Exercise #8

Resolve -

(x3)(x6)= (x-3)(x-6)=

Video Solution

Answer

x29x+18 x^2-9x+18

Exercise #9

Solve the exercise:

(2y3)(y4)= (2y-3)(y-4)=

Video Solution

Answer

2y211y+12 2y^2-11y+12

Exercise #10

Solve the exercise:

(3x1)(x+2)= (3x-1)(x+2)=

Video Solution

Answer

3x2+5x2 3x^2+5x-2

Exercise #11

Solve the exercise:

(5x2)(3+x)= (5x-2)(3+x)=

Video Solution

Answer

5x2+13x6 5x^2+13x-6

Exercise #12

Solve the exercise:

(3a4)(2+3a)= (3a-4)\cdot(2+3a)=

Video Solution

Answer

9a26a8 9a^2-6a-8

Exercise #13

Solve the exercise:

(4ab)(b+3a)= (4a-b)(b+3a)=

Video Solution

Answer

12a2b2ab 12a^2-b^2-ab

Exercise #14

Solve the following exercise:

(4y+3)(3x+2)= (4y+3)\cdot(3x+2)=

Video Solution

Answer

12xy+8y+9x+6 12xy+8y+9x+6

Exercise #15

Solve the exercise:

(xy+2a)(x2b)= (xy+2a)\cdot(x-2b)=

Video Solution

Answer

x2y2xyb+2ax4ab x^2y-2xyb+2ax-4ab

Exercise #16

(7x+4)(3x+4)= (7x+4)(3x+4)=

Video Solution

Answer

21x2+40x+16 21x^2+40x+16

Exercise #17

Solve:

(x+yz)(2xy)= (x+y-z)\cdot(2x-y)=

Video Solution

Answer

2x2+xyy22xz+yz 2x^2+xy-y^2-2xz+yz

Exercise #18

Solve:

(a+b+2c)(3a2b)= (a+b+2c)\cdot(3a-2b)=

Video Solution

Answer

3a2+ab2b2+6ac4bc 3a^2+ab-2b^2+6ac-4bc

Exercise #19

Which expressions represent the area of the rectangle in the drawing?

  1. 56x 56x

  2. 9(3x2+5x) 9(3x^2+5x)

  3. x(3x+5)+9(3x+5) x(3x+5)+9(3x+5)

  4. 32x+x2 32x+x^2

  5. 3x2+45 3x^2+45

  6. 3x2+32x+45 3x^2+32x+45

    3X+53X+53X+5X+9X+9X+9

Video Solution

Answer

3, 6