Solving Quadratic Equations using Factoring: One sided equations

Solve x:

$5(x+3)=0$

We open the parentheses according to the formula:

$a(x+b)=ax+ab$

$5\times x+5\times3=0$

$5x+15=0$

We will move the 15 to the right section and keep the corresponding sign:

$5x=-15$

Divide both sections by 5

$\frac{5x}{5}=\frac{-15}{5}$

$x=-3$

$-3$

$2(x+4)+8=0$

Let's open the parentheses and use the formula:

$a(x+b)=ax+ab$

$(2\times x)+(2\times4)+8=0$

$2x+8+8=0$

We'll input the terms accordingly:

$2x+16=0$

We'll move 16 to the left side and keep the appropriate sign:

$2x=-16$

We'll divide both sides by 2:

$\frac{2x}{2}=-\frac{16}{2}$

$x=-8$

$x=-8$

$-6(7x-6)-(-5-8x)=0$

We will use the extended division rule and the formula:

$a(x+b)=ax+ab$

$-42x+36+5+8x=0$

Let's input the appropriate terms:

$-34x+41=0$

We'll move -34x to the right side and maintain the appropriate sign:

$41=34x$

Let's divide both sides by 34:

$\frac{41}{34}=\frac{34x}{34}$

$\frac{41}{34}=x$

We'll convert the simple fraction to a mixed fraction:

$x=1\frac{7}{34}$

$1\frac{7}{41}$

$5(8+a)-(2a+14)=56$

Let's open the parentheses using the distributive property and use the formula:

$a(x+b)=ax+ab$

$40+5a-2a-14=56$

We'll substitute the terms accordingly:

$26+3a=56$

We'll move 26 to the right side and keep the appropriate sign:

$3a=56-26$

$3a=30$

We'll divide both sides by 3:

$\frac{3a}{3}=\frac{30}{3}$

$a=10$

$10$

Solve for x:

$2(4-x)=8$

0

$8a+2(3a-7)=0$

$a=1$

$3(a+1)-3=0$

$a=0$

$5-(3b-1)=0$

$b=2$

$3x+5(x+4)=0$

$x=-2.5$

Solve for y:

$-2(-4+y)-y=0$

$y=2\frac{2}{3}$

$3(y-2)+2(y+3)=180$

36

$-4(6-x)+(3x+5)=14$

$4\frac{5}{7}$

$11(-3x+4)-7(6x-2)=3$

$\frac{11}{15}$

Solve for a:

$7a(3+\frac{1}{a})-2a=0$

$a=-\frac{7}{19}$

$2(m+8)-3(16+m)=0$

$m=-32$