Solving Quadratic Equations using Factoring: Solving an equation using all techniques

Solve for X:

$\frac{1}{2}(x+3)-8x=3$

$-\frac{1}{5}$

Solve for X:

$5(x-8)+\frac{1}{2}=0$

$\frac{79}{10}$

Solve for X:

$-8(2-x)=\frac{1}{2}+x$

$\frac{33}{14}$

$6c+7+4c=3(c-1)$

$c=\text{?}$

$-1\frac{3}{7}$

$7y+10y+5=2(y+3)$

$y=\text{?}$

$\frac{1}{15}$

Solve for X:

$-\frac{1}{2}(x-\frac{1}{4})=\frac{1}{2}(3-x)$

There is no solution.

Solve for X:

$\frac{1}{8}(\frac{1}{2}-x)=\frac{1}{4}(x-\frac{1}{4})$

0

$16a-20a+15=2(5-2a)$

$a=\text{?}$

No solution

$-3(4a+8)=27a$

$a=\text{?}$

$-\frac{8}{13}$

Solve for X:

$\frac{1}{6}(x-4)=\frac{1}{4}(\frac{1}{3}x+3)$

17

$3x+\frac{2}{3}=4(x+\frac{1}{12})$

$x=\text{?}$

$\frac{1}{3}$

$-\frac{7}{4}(-x)+2x-5(x+3)=-x$

$x=\text{?}$

$-60$

$2x+45-\frac{1}{3}x=5(x+7)$

$x=\text{?}$

3

$150+75m+\frac{m}{8}-\frac{m}{3}=(900-\frac{5m}{2})\cdot\frac{1}{12}$

$m=\text{?}$

$-1$

Solve for X:

$(5-x)\cdot\frac{1}{2}+3x-4(x-2)=\frac{1}{2}(x+4)$

$\frac{17}{4}$

Solve for X:

$8(x+3)-1+4x=8(x+3)-5(x-4)$

$\frac{7}{3}$

$-t+2(4+t)(t+5)=(t-5)(2t-3)$

$t=\text{?}$

$-\frac{5}{6}$

$$$(x+2)(2x-4)=2x^2+x+10$

$-18$

$(x+4)(3x-\frac{1}{4})=3(x^2+5)$

$x=?$

$1\frac{17}{47}$

$-4(x^2+5)=(-x+7)(4x-9)+5$

$x=?$

$1\frac{1}{37}$