Variable

🏆Practice equation (+ what is the unknown)

Variable

What is a variable?

A variable is a specific symbol like a Latin letter – XX/YY/ZZ that can change and represent a quantity/value.

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Test yourself on equation (+ what is the unknown)!

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\( 5x=0 \)

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Variable

What is a variable?

A variable is a certain symbol like a Latin letter – XX/YY/ZZ that can change and take on a different value each time.
The meaning of the variable is to symbolize something for us – quantity, price, an element within a set, or some value.
The variable can appear in a function or as part of some expression and can also be called an unknown or a parameter.

Different forms of a variable:

A variable can be dependent or independent.
A dependent variable is one that depends on something – for example, YY in a function, which will depend on the XX we substitute for it.
An independent variable is one that does not depend on anything - usually XX (it can have a certain range of values) and it will ultimately determine the value of the dependent variable.
Important to know –
Although the variable changes and can take on a different number each time, if the same variable appears several times in the same expression or function, it will be identical in all its occurrences in the function.

Let's see an example:

Given the following function:
Y=X2+2X+6Y=X^2+2X+6

  • How many variables are there in the function?
  • Which is the dependent variable and which is the independent variable?
  • If X=2X=2 what will be the value of the variable YY.

Solution:

  1. In the given function, there are only 22 variables: XX and YY.
    Note that XX appears twice and in different forms – once squared and once multiplied by 22, but it is the same XX with the same value in both instances, so we will treat it as one variable.
  2. The dependent variable in the function is YY because its value depends on what we substitute for XX.
    The independent variable is XX because it does not depend on any other parameter and can take any value.
  3. To know the value of the variable YY when X=2X=2 , we need to substitute X=2X=2 in every instance of XX in the function. We get:
    Y=22+22+6Y=2^2+2*2+6
    Y=4+4+6Y=4+4+6
    Y=12Y=12
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How do you solve a word problem with variables?

Sometimes, we encounter word problems where we are asked to find the value of something specific, like the price of a shirt, the number of slices of cake, or the number of children.

We can take the data from the question and turn it into an algebraic equation using variables.
When we have an algebraic equation composed of various variables based on the data in the question, we can easily solve the word problem.

Let's see an example:

Advanced word problem with variables –

Saar went to the nearby mall and decided to buy 22 shirts, 11 pair of pants, and 33 packs of cards.
It is known that a shirt costs XX ₪ and the price of the pants is 33 times the price of the shirt.
It is also known that the price of a pack of cards is half the price of the pants.
Additionally, Saar paid 88 dollars for parking.

  1. Present the prices of all items using variables.
  2. Find out the price of the pants and the price of the pack of cards if you know that X=30 X=30.
  3. How much did Saar pay in total during his visit to the mall, based on item 2?

Solution:

1.    We will represent the data of the question using variables:
Price of a shirt = XX known according to the data of the question 

Price of pants =
According to the question data, it is known that the price of pants is 33 times higher than the price of the shirt.

Price of a pack of cards = 3X23X \over2
If the price of the pants is 3X 3X , and the price of a pack of cards is half the price of the pants, then the price of the pack of cards is 3X 3X  divided by 22.

2.    If X=30X=30
The price of the pants is 330=903*30=90
9090
And the price of a pack of cards is:
90:2=4590:2=45
3.     To know how much Sa'ar paid in total at the mall, we need to build an equation:
Note that it is given that:
Sa'ar decided to buy 22 shirts, 11 pair of pants, and 33 packs of cards and paid an additional 88 for parking.

Therefore, the equation will be:

230+90+345+8=2*30+90+3*45+8=
60+90+135+8=29360+90+135+8=293

Saar spent 293293 in total during the entire visit to the mall, including parking.

Do you know what the answer is?

Examples with solutions for Equation (+ what is the unknown)

Exercise #1

2x+75x12=8x+3 2x+7-5x-12=-8x+3

Video Solution

Step-by-Step Solution

To solve this exercise, we first need to identify that we have an equation with an unknown,

To solve such equations, the first step will be to arrange the equation so that on one side we have the numbers and on the other side the unknowns.

2X+75X12=8X+3 2X+7-5X-12=-8X+3

First, we'll move all unknowns to one side.
It's important to remember that when moving terms, the sign of the number changes (from negative to positive or vice versa).

2X+75X12+8X=3 2X+7-5X-12+8X=3

Now we'll do the same thing with the regular numbers.

2X5X+8X=37+12 2X-5X+8X=3-7+12

In the next step, we'll calculate the numbers according to the addition and subtraction signs.

2X5X=3X 2X-5X=-3X
3X+8X=5X -3X+8X=5X

37=4 3-7=-4
4+12=8 -4+12=8

5X=8 5X=8

At this stage, we want to get to a state where we have only one X X , not 5X 5X ,
so we'll divide both sides of the equation by the coefficient of the unknown (in this case - 5).

X=85 X={8\over5}

Answer

x=85 x=\frac{8}{5}

Exercise #2

5x=0 5x=0

Video Solution

Answer

x=0 x=0

Exercise #3

5x=1 5x=1

What is the value of x?

Video Solution

Answer

x=15 x=\frac{1}{5}

Exercise #4

14x+3=17 14x+3=17

x=? x=\text{?}

Video Solution

Answer

x=1 x=1

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