12y+3y−10+7(y−4)=2y
y=?
To solve the equation 12y+3y−10+7(y−4)=2y, follow these detailed steps:
- Step 1: Apply the distributive property to 7(y−4).
This results in:
12y+3y−10+7y−28=2y.
- Step 2: Combine like terms on the left side of the equation.
Combining terms, we have:
(12y+3y+7y)−10−28=2y
22y−38=2y.
- Step 3: Move all terms involving y to one side of the equation and constant terms to the other side.
Subtract 2y from both sides:
22y−2y=38
20y=38.
- Step 4: Solve for y by dividing both sides by 20.
y=2038=1.9.
Therefore, the solution to the equation is y=1.9.