Solve Linear Equation: 12y+3y-10+7(y-4)=2y Step-by-Step

Question

12y+3y10+7(y4)=2y 12y+3y-10+7(y-4)=2y

y=? y=?

Video Solution

Solution Steps

00:00 Solution
00:04 Open parentheses properly and multiply by each factor
00:18 Collect terms
00:23 We want to isolate the unknown Y
00:31 We'll arrange the equation so that Y is alone on one side
00:45 Isolate the unknown Y
00:57 And this is the solution to the question

Step-by-Step Solution

To solve the equation 12y+3y10+7(y4)=2y12y + 3y - 10 + 7(y - 4) = 2y, follow these detailed steps:

  • Step 1: Apply the distributive property to 7(y4)7(y - 4).

This results in:
12y+3y10+7y28=2y12y + 3y - 10 + 7y - 28 = 2y.

  • Step 2: Combine like terms on the left side of the equation.

Combining terms, we have:
(12y+3y+7y)1028=2y(12y + 3y + 7y) - 10 - 28 = 2y
22y38=2y22y - 38 = 2y.

  • Step 3: Move all terms involving yy to one side of the equation and constant terms to the other side.

Subtract 2y2y from both sides:
22y2y=3822y - 2y = 38
20y=3820y = 38.

  • Step 4: Solve for yy by dividing both sides by 20.

y=3820=1.9y = \frac{38}{20} = 1.9.

Therefore, the solution to the equation is y=1.9 y = 1.9 .

Answer

1.9 1.9