−3(4a+8)=27a
a=?
\( -3(4a+8)=27a \)
\( a=\text{?} \)
\( \frac{1}{4}a+5=20+a \)
\( a=\text{?} \)
\( 4y-7+6y=3-10y \)
\( y=? \)
\( 37b+6b+56=90+9 \)
\( b=\text{?} \)
\( 6c+7+4c=3(c-1) \)
\( c=\text{?} \)
To open the parentheses on the left side, we'll use the formula:
We'll arrange the equation so that the terms with 'a' are on the right side, and maintain the plus and minus signs during the transfer:
Let's group the terms on the right side:
Let's divide both sides by 39:
Note that we can reduce the fraction since both numerator and denominator are divisible by 3:
1
\( 7y+10y+5=2(y+3) \)
\( y=\text{?} \)
\( a^4+7a-5=2a+a^4+3a-(-a) \)
\( a=? \)
\( 12y+3y-10+7(y-4)=2y \)
\( y=? \)
\( \frac{1}{3}(x+9)=4+\frac{2}{3}x \)
\( x=\text{?} \)
\( 2x+45-\frac{1}{3}x=5(x+7) \)
\( x=\text{?} \)
3-
3
\( -\frac{7}{4}(-x)+2x-5(x+3)=-x \)
\( x=\text{?} \)
\( (x+4)(3x-\frac{1}{4})=3(x^2+5) \)
\( x=? \)
\( -4(x^2+5)=(-x+7)(4x-9)+5 \)
\( x=? \)
\( -\frac{x}{4y}+\frac{4x}{y}+\frac{3x}{4y}-15=20\frac{x}{y}-\frac{x}{2y} \)
\( \frac{x}{y}=? \)
\( 150+75m+\frac{m}{8}-\frac{m}{3}=(900-\frac{5m}{2})\cdot\frac{1}{12} \)
\( m=\text{?} \)
\( -t+2(4+t)(t+5)=(t-5)(2t-3) \)
\( t=\text{?} \)