Solving an Equation by Multiplication/ Division: Solving an equation using all techniques

$\frac{1}{4}a+5=20+a$

$a=\text{?}$

$-20$

$4y-7+6y=3-10y$

$y=?$

$\frac{1}{2}$

$37b+6b+56=90+9$

$b=\text{?}$

1

$6c+7+4c=3(c-1)$

$c=\text{?}$

$-1\frac{3}{7}$

$7y+10y+5=2(y+3)$

$y=\text{?}$

$\frac{1}{15}$

$-3(4a+8)=27a$

$a=\text{?}$

$-\frac{8}{13}$

$a^4+7a-5=2a+a^4+3a-(-a)$

$a=?$

$5$

$12y+3y-10+7(y-4)=2y$

$y=?$

$1.9$

$\frac{1}{3}(x+9)=4+\frac{2}{3}x$

$x=\text{?}$

3-

$2x+45-\frac{1}{3}x=5(x+7)$

$x=\text{?}$

3

$-\frac{7}{4}(-x)+2x-5(x+3)=-x$

$x=\text{?}$

$-60$

$-\frac{x}{4y}+\frac{4x}{y}+\frac{3x}{4y}-15=20\frac{x}{y}-\frac{x}{2y}$

$\frac{x}{y}=?$

$-1$

$150+75m+\frac{m}{8}-\frac{m}{3}=(900-\frac{5m}{2})\cdot\frac{1}{12}$

$m=\text{?}$

$-1$

$-t+2(4+t)(t+5)=(t-5)(2t-3)$

$t=\text{?}$

$-\frac{5}{6}$

$(x+4)(3x-\frac{1}{4})=3(x^2+5)$

$x=?$

$1\frac{17}{47}$

$-4(x^2+5)=(-x+7)(4x-9)+5$

$x=?$

$1\frac{1}{37}$