What is the domain of the above equation?
\( 2x+\frac{6}{x}=18 \)
What is the domain of the above equation?
\( 2x-3=\frac{4}{x} \)
What is the domain of the exercise?
Select the field of application of the following fraction:
\( \frac{3}{x+2} \)
Select the field of application of the following fraction:
\( \frac{8}{-2+x} \)
Select the field of application of the following fraction:
\( \frac{7}{13+x} \)
What is the domain of the above equation?
x≠0
What is the domain of the exercise?
x≠0
Select the field of application of the following fraction:
Select the field of application of the following fraction:
Select the field of application of the following fraction:
Select the field of application of the following fraction:
\( \frac{x+8}{3x} \)
\( 22(\frac{2}{x}-1)=30 \)
What is the domain of the equation above?
What is the domain of the exercise?
\( \frac{5x+8}{2x-6}=30 \)
\( \frac{x+y:3}{2x+6}=4 \)
What is the field of application of the equation?
Select the field of application of the following fraction:
\( 16+\frac{8}{2x} \)
Select the field of application of the following fraction:
What is the domain of the equation above?
x≠0
What is the domain of the exercise?
x≠3
What is the field of application of the equation?
Select the field of application of the following fraction:
Select the field of application of the following fraction:
\( -8+\frac{3}{x+2} \)
Select the field of application of the following fraction:
\( \frac{x}{x+3} \)
Select the field of application of the following fraction:
\( \frac{-8-x}{-x} \)
Choose the field of application of the following fraction:
\( \frac{-8-x}{-3x+2} \)
\( \frac{3x:4}{y+6}=6 \)
What is the field of application of the equation?
Select the field of application of the following fraction:
All numbers except (-2)
Select the field of application of the following fraction:
Select the field of application of the following fraction:
Choose the field of application of the following fraction:
What is the field of application of the equation?
Solve the following equation:
\( \frac{x^3+1}{(x+1)^2}=x \)
Solve the following equation: