Solve: 2^3 × 2^4 + (4^3)^2 + 2^5/2^3 - Complete Exponent Expression

Exponent Laws with Mixed Operations

Solve the following exercise:

23×24+(43)2+2523= 2^3\times2^4+(4^3)^2+\frac{2^5}{2^3}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve the following problem
00:03 When multiplying powers with equal bases
00:08 The power of the result equals the sum of the powers
00:13 We'll apply this formula to our exercise
00:18 When there's a power of a power, the combined power is the product of the powers
00:24 We'll apply this formula to our exercise
00:28 When dividing powers with equal bases
00:31 The power of the result equals the difference of the powers
00:38 We'll apply this formula to our exercise
00:50 Let's calculate all the powers
00:58 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

23×24+(43)2+2523= 2^3\times2^4+(4^3)^2+\frac{2^5}{2^3}=

2

Step-by-step solution

We use the three appropriate power properties to solve the problem:

  1. Power law for multiplication between terms with identical bases:

aman=am+n a^m\cdot a^n=a^{m+n} 2. Power law for an exponent raised to another exponent:

(am)n=amn (a^m)^n=a^{m\cdot n} 3. Power law for the division of terms with identical bases:

aman=amn \frac{a^m}{a^n}=a^{m-n}

We continue and apply the three previous laws to the problem:

2324+(43)2+2523=23+4+432+253=27+46+22 2^3\cdot2^4+(4^3)^2+\frac{2^5}{2^3}=2^{3+4}+4^{3\cdot2}+2^{5-3}=2^7+4^6+2^2

In the first step we apply the power law mentioned in point 1 to the first expression on the left, the power law mentioned in point 2 to the second expression on the left, and the power law mentioned in point 3 to the third expression on the left, separately. In the second step, we simplify the expressions by exponents possession of the received terms,

Then,after using the substitution property for addition, we find that the correct answer is D.

3

Final Answer

22+27+46 2^2+2^7+4^6

Key Points to Remember

Essential concepts to master this topic
  • Multiplication Rule: aman=am+n a^m \cdot a^n = a^{m+n} for same bases
  • Power of Power: (am)n=amn (a^m)^n = a^{m \cdot n} like (43)2=46 (4^3)^2 = 4^6
  • Division Rule: aman=amn \frac{a^m}{a^n} = a^{m-n} so 2523=22 \frac{2^5}{2^3} = 2^2

Common Mistakes

Avoid these frequent errors
  • Adding exponents when bases are different
    Don't treat 2^3 + 4^3 like 2^6 = wrong answer! The bases (2 and 4) are different, so you can't combine their exponents. Always check that bases match before applying exponent rules.

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why can't I just add all the exponents together?

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You can only add exponents when multiplying terms with the same base. Here we have addition between different terms, so each part must be simplified separately first.

How do I handle (4^3)^2 - do I multiply or add the exponents?

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When you have a power raised to another power, you multiply the exponents: (43)2=43×2=46 (4^3)^2 = 4^{3 \times 2} = 4^6

Should I calculate the actual numbers or leave them as powers?

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For this problem, leave them as powers! The answer choices are all in exponential form, so converting to actual numbers would make it harder to match the correct answer.

What's the difference between 2^3 × 2^4 and 2^3 + 2^4?

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Multiplication: 23×24=27 2^3 \times 2^4 = 2^7 (add exponents)
Addition: 23+24=8+16=24 2^3 + 2^4 = 8 + 16 = 24 (calculate each term first)

How do I check if 2^2 + 2^7 + 4^6 is correct?

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Verify each step: 23×24=27 2^3 \times 2^4 = 2^7 ✓, (43)2=46 (4^3)^2 = 4^6 ✓, 2523=22 \frac{2^5}{2^3} = 2^2 ✓. The final form matches answer choice D!

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