Solve: 2^3 × 2^4 + (4^3)^2 + 2^5/2^3 - Complete Exponent Expression

Question

Solve the following exercise:

23×24+(43)2+2523= 2^3\times2^4+(4^3)^2+\frac{2^5}{2^3}=

Video Solution

Solution Steps

00:00 Solve
00:03 When multiplying powers with equal bases
00:08 The power of the result equals the sum of the powers
00:13 We'll use this formula in our exercise
00:18 When there's a power of a power, the combined power is the product of the powers
00:24 We'll use this formula in our exercise
00:28 When dividing powers with equal bases
00:31 The power of the result equals the difference of the powers
00:38 We'll use this formula in our exercise
00:50 Let's calculate all the powers
00:58 And this is the solution to the question

Step-by-Step Solution

We use the three appropriate power properties to solve the problem:

  1. Power law for multiplication between terms with identical bases:

aman=am+n a^m\cdot a^n=a^{m+n} 2. Power law for an exponent raised to another exponent:

(am)n=amn (a^m)^n=a^{m\cdot n} 3. Power law for the division of terms with identical bases:

aman=amn \frac{a^m}{a^n}=a^{m-n}

We continue and apply the three previous laws to the problem:

2324+(43)2+2523=23+4+432+253=27+46+22 2^3\cdot2^4+(4^3)^2+\frac{2^5}{2^3}=2^{3+4}+4^{3\cdot2}+2^{5-3}=2^7+4^6+2^2

In the first step we apply the power law mentioned in point 1 to the first expression on the left, the power law mentioned in point 2 to the second expression on the left, and the power law mentioned in point 3 to the third expression on the left, separately. In the second step, we simplify the expressions by exponents possession of the received terms,

Then,after using the substitution property for addition, we find that the correct answer is D.

Answer

22+27+46 2^2+2^7+4^6