Powers and Roots: Solving the problem

$3\times3+3^2=$

Let's recall the order of operations:

1. Parentheses

2. Exponents and Roots

3. Multiplication and Division

4. Addition and Subtraction

There are no parentheses in this problem, so we'll start with exponents:

3*3+3² =

3*3+9 =

Let's continue to the next step, multiplication operations:

3*3+9 =

9 + 9 =

Now we're left with just a simple addition problem:

9+9= 18

And that's the solution!

18

$5^3:5^2\times2^3=$

In the first stage, let's calculate the powers of each of the terms:

$5^3=5\times5\times5=25\times5=125$

$5^2=5\times5=25$

$2^3=2\times2\times2=4\times2=8$

Now let's write the resulting expression:

$125:25\times8=$

Since the only operations in the expression are multiplication and division, we will solve the expression from left to right

In other words, we will divide first and then multiply:

$125:25=5$

$5\times8=40$

40

$(\sqrt{380.25}-\frac{1}{2})^2-11=$

According to the order of operations, we'll first solve the expression in parentheses:

$(\sqrt{380.25}-\frac{1}{2})=(19.5-\frac{1}{2})=(19)$

In the next step, we'll solve the exponentiation, and finally subtract:

$(19)^2-11=(19\times19)-11=361-11=350$

350

$4+2^2=$$$

8

$6+\sqrt{64}-4=$

10

$4+2+5^2=$

31

$10:2-2^2=$

1

$8-3^2:3=$

$5$

$0:2^2\times1^{10}+3=$

3

$(2+1\times2)^2=$

16

$5+5-5^2+4^2=$

1

$2\times(\sqrt{36}+9)=$

30

$5+\sqrt{36}-1=$

$10$

$100:5^2+3^2=$

13

$(4^2+3)\times\sqrt{9}=$

57

$(20-3\times2^2)^2=$

64

$18^2-(100+\sqrt{9})=$

221

$81+\sqrt{81}+10=$

$100$

$143-\sqrt{121}+18=$

$150$

$(3+1)^2-(4+1)=$

11