6+64−4=
\( 6+\sqrt{64}-4= \)
\( 3\times3+3^2= \)
\( 7 + \sqrt{49} - 5 = \)
\( 3 \times 2 + \sqrt{81} = \)
\( 8 - \sqrt{16} \times 3 = \)
To solve the expression , we need to follow the order of operations (PEMDAS/BODMAS):
In this expression, we first need to evaluate the square root since it falls under the exponent category:
Next, we substitute the computed value back into the expression:
We then perform the addition and subtraction from left to right:
Thus, the final answer is:
10
Let's recall the order of operations:
Parentheses
Exponents and Roots
Multiplication and Division
Addition and Subtraction
There are no parentheses in this problem, so we'll start with exponents:
3*3+3² =
3*3+9 =
Let's continue to the next step, multiplication operations:
3*3+9 =
9 + 9 =
Now we're left with just a simple addition problem:
9+9= 18
And that's the solution!
18
First, evaluate the square root: .
Then, follow the order of operations (PEMDAS/BODMAS):
1. Addition:
2. Subtraction:
So, the correct answer is .
First, evaluate the square root: .
Then, follow the order of operations (PEMDAS/BODMAS):
1. Multiplication:
2. Addition:
So, the correct answer is .
First, evaluate the square root: .
Then, follow the order of operations (PEMDAS/BODMAS):
1. Multiplication:
2. Subtraction:
So, the correct answer is .
\( 10-5^2:5= \)
\( 15-4^2:2= \)
\( 20-3^3:3= \)
\( 8 + 3 \times 2 - 4^2 = \)
\( 6 - 3 + 5 \times 2^2 = \)
First, compute the power: .
Next, divide: .
Finally, subtract: .
First, compute the power: .
Next, divide: .
Finally, subtract: .
First, compute the power: .
Next, divide: .
Finally, subtract: .
First, follow the order of operations (BODMAS/BIDMAS):
Step 1: Calculate the exponent:
Step 2: Perform the multiplication:
Step 3: Perform the addition and subtraction from left to right:
The correct result is: .
First, follow the order of operations (BODMAS/BIDMAS):
Step 1: Calculate the exponent:
Step 2: Perform the multiplication:
Step 3: Perform the addition and subtraction from left to right:
The correct result is: .
\( 4 + \sqrt{49} \times 3 = \)
\( 5^2 - \sqrt{16} + 2 = \)
\( 10:2-2^2= \)
\( 8-3^2:3= \)
\( 4+2+5^2= \)
First, solve the square root: .
Next, multiply 7 by 3: .
Finally, add 4 to 21: .
Start by calculating the power: .
Then, calculate the square root: .
Subtract 4 from 25: .
Finally, add 2: .
1
31
\( 4+2^2= \)\( \)
\( 5+\sqrt{36}-1= \)
8