All Operations in Fractions: The common denominator is smaller than the product of the denominators

$\frac{1}{3}+\frac{1}{6}=$

$\frac{1}{2}$

$\frac{3}{4}+\frac{1}{6}=$

$\frac{11}{12}$

$\frac{1}{2}+\frac{4}{6}=$

$\frac{7}{6}$

$\frac{1}{4}+\frac{7}{8}=$

$\frac{9}{8}$

$\frac{1}{4}+\frac{3}{4}=$

$1$

$\frac{1}{2}+\frac{1}{6}=$

$\frac{2}{3}$

$\frac{4}{6}+\frac{1}{8}=$

$\frac{19}{24}$

Solve the following exercise:

$\frac{1}{4}+\frac{2}{6}=\text{?}$

$\frac{7}{12}$

Solve the following exercise:

$\frac{2}{4}+\frac{2}{6}=\text{?}$

$\frac{10}{12}$

Solve the following exercise:

$\frac{1}{4}+\frac{4}{6}=\text{?}$

$\frac{11}{12}$

Solve the following exercise:

$\frac{3}{4}+\frac{1}{6}=\text{?}$

$\frac{11}{12}$

Solve the following exercise:

$\frac{2}{4}+\frac{1}{6}=\text{?}$

$\frac{8}{12}$

$\frac{3}{5}+\frac{3}{10}=$

$\frac{9}{10}$

$\frac{2}{3}+\frac{7}{9}=$

$\frac{13}{9}$

$\frac{9}{10}+\frac{2}{5}=$

$\frac{13}{10}$

$\frac{3}{8}+\frac{1}{4}=$

$\frac{5}{8}$

$\frac{4}{15}+\frac{2}{5}=$

$\frac{2}{3}$

$\frac{3}{14}+\frac{3}{7}=$

$\frac{9}{14}$

$\frac{3}{4}+\frac{3}{8}=$

$\frac{9}{8}$

$\frac{4}{12}+\frac{5}{6}=$$$

$\frac{7}{6}$