All Operations in Fractions: In combination with other operations

To solve the expression $\frac{2}{7}+\frac{1}{2}-\frac{7}{14}$, follow these steps:

• Step 1: Find the least common multiple (LCM) of the denominators 7, 2, and 14. The LCM is 14.
• Step 2: Convert each fraction to have the denominator of 14:
      $\frac{2}{7}$ becomes $\frac{2 \times 2}{7 \times 2} = \frac{4}{14}$
      $\frac{1}{2}$ becomes $\frac{1 \times 7}{2 \times 7} = \frac{7}{14}$
      $\frac{7}{14}$ remains $\frac{7}{14}$ since it's already over 14.
• Step 3: Perform the operations in the expression $\frac{4}{14} + \frac{7}{14} - \frac{7}{14}$:
      First, add $\frac{4}{14} + \frac{7}{14} = \frac{11}{14}$.
      Then, subtract $\frac{11}{14} - \frac{7}{14} = \frac{4}{14}$.
• Step 4: The result is already simplified. Thus, the solution to the problem is $\frac{4}{14}$.

Therefore, the solution to the problem is $\mathbf{\frac{4}{14}}$, which corresponds to choice $\mathbf{3}$.

To solve the expression $\frac{4}{10} + \frac{1}{5} - \frac{1}{2}$, we will follow these steps:

• Step 1: Find a Common Denominator
  The denominators we have are 10, 5, and 2. The least common denominator (LCD) among these numbers is 10.

• Step 2: Convert Fractions to Equivalent Fractions with the LCD
  - $\frac{4}{10}$ is already using 10 as the denominator.
  - $\frac{1}{5} = \frac{1 \times 2}{5 \times 2} = \frac{2}{10}$.
  - $\frac{1}{2} = \frac{1 \times 5}{2 \times 5} = \frac{5}{10}$.

• Step 3: Perform the Arithmetic Operations
  Substitute the converted fractions into the original expression:
  $\frac{4}{10} + \frac{2}{10} - \frac{5}{10}$
  Combine the numerators over the common denominator:
  $\frac{4 + 2 - 5}{10} = \frac{1}{10}$

• Step 4: Simplify the Result
  The fraction $\frac{1}{10}$ is already in its simplest form.

Therefore, the solution to the problem is $\frac{1}{10}$.

To solve the expression $\frac{6}{7} - \frac{1}{2} + \frac{3}{14}$, we will follow these steps:

• Step 1: Find a common denominator for the fractions.
• Step 2: Convert each fraction to the common denominator.
• Step 3: Perform the subtraction and addition as required.
• Step 4: Simplify the result, if possible.

Let's work through the steps:

Step 1: The denominators are 7, 2, and 14. The least common multiple (LCM) of these numbers is 14.

Step 2: Convert each fraction:

• $\frac{6}{7}$ becomes $\frac{6 \times 2}{7 \times 2} = \frac{12}{14}$.
• $\frac{1}{2}$ becomes $\frac{1 \times 7}{2 \times 7} = \frac{7}{14}$.
• $\frac{3}{14}$ is already in the correct form as $\frac{3}{14}$.

Step 3: Perform the operations:

• Subtract: $\frac{12}{14} - \frac{7}{14} = \frac{5}{14}$.
• Add: $\frac{5}{14} + \frac{3}{14} = \frac{8}{14}$.

Step 4: Simplify the fraction if possible. Here, $\frac{8}{14}$ simplifies to $\frac{4}{7}$; however, since the given choices list $\frac{8}{14}$ and it matches, there is no need for further simplification within the context of this question.

Therefore, the solution to the problem is $\frac{8}{14}$.

To solve the expression $\frac{9}{10} - \frac{4}{5} + \frac{1}{2}$, we first seek a common denominator for the fractions. The denominators are 10, 5, and 2.

The least common multiple of these numbers is 10, as it is the smallest number that all denominators divide perfectly.

• Convert $\frac{4}{5}$ to a fraction with a denominator of 10: $\frac{4}{5} = \frac{4 \times 2}{5 \times 2} = \frac{8}{10}$.
• Convert $\frac{1}{2}$ to a fraction with a denominator of 10: $\frac{1}{2} = \frac{1 \times 5}{2 \times 5} = \frac{5}{10}$.

Now, the expression becomes $\frac{9}{10} - \frac{8}{10} + \frac{5}{10}$.

Perform the operations:

• Subtract: $\frac{9}{10} - \frac{8}{10} = \frac{1}{10}$.
• Add: $\frac{1}{10} + \frac{5}{10} = \frac{6}{10}$.

Thus, the value of the expression is $\frac{6}{10}$.

The correct answer is $\frac{6}{10}$.

To solve the problem, let's work through the following steps:

• Step 1: Identify the least common denominator (LCD) for all fractions.
  - The denominators are 8, 2, and 4. The LCM of these numbers is 8.

• Step 2: Convert each fraction to have this common denominator of 8.
  - $\frac{3}{8}$ is already with a denominator of 8.
  - $\frac{1}{2}$ can be rewritten as $\frac{4}{8}$ because $\frac{1 \times 4}{2 \times 4} = \frac{4}{8}$.
  - $\frac{1}{4}$ can be rewritten as $\frac{2}{8}$ because $\frac{1 \times 2}{4 \times 2} = \frac{2}{8}$.

• Step 3: Perform the arithmetic operations.
  - Add $\frac{3}{8}$ and $\frac{4}{8}$, which gives $\frac{3 + 4}{8} = \frac{7}{8}$.
  - Subtract $\frac{2}{8}$ from $\frac{7}{8}$, giving $\frac{7 - 2}{8} = \frac{5}{8}$.

• Step 4: Simplify the answer if necessary.
  $\frac{5}{8}$ is already in its simplest form.

Therefore, the solution to the problem is $\frac{5}{8}$.

To solve the problem $\frac{2}{5} + \frac{1}{2} - \frac{1}{3}$, we will follow these steps:

• Step 1: Find the least common denominator (LCD) for $\frac{2}{5}$, $\frac{1}{2}$, and $\frac{1}{3}$.
• Step 2: Convert each fraction to have this common denominator.
• Step 3: Perform the arithmetic operations.
• Step 4: Simplify the result if necessary.

Now, let's proceed with the solution:
Step 1: The denominators are 5, 2, and 3. The least common multiple of these numbers is 30. Thus, the LCD is 30.

Step 2: Convert each fraction to have the common denominator of 30:
- Convert $\frac{2}{5}$ to a fraction with denominator 30: $\frac{2}{5} = \frac{2 \times 6}{5 \times 6} = \frac{12}{30}$.
- Convert $\frac{1}{2}$ to a fraction with denominator 30: $\frac{1}{2} = \frac{1 \times 15}{2 \times 15} = \frac{15}{30}$.
- Convert $\frac{1}{3}$ to a fraction with denominator 30: $\frac{1}{3} = \frac{1 \times 10}{3 \times 10} = \frac{10}{30}$.

Step 3: With all fractions having the same denominator, perform the operations:
$\frac{12}{30} + \frac{15}{30} - \frac{10}{30} = \frac{12 + 15 - 10}{30} = \frac{17}{30}$.

Step 4: Since $\frac{17}{30}$ is in its simplest form, no further simplification is needed.

Therefore, the correct answer is $\frac{17}{30}$.

To solve $\frac{1}{2} \times \frac{1}{2} + \frac{3}{4}$, follow these steps:

• Step 1: Multiply $\frac{1}{2} \times \frac{1}{2}$ by using the multiplication of fractions formula:
  $\frac{1}{2} \times \frac{1}{2} = \frac{1 \times 1}{2 \times 2} = \frac{1}{4}$.
• Step 2: Add $\frac{1}{4}$ to $\frac{3}{4}$.
  Since $\frac{1}{4}$ and $\frac{3}{4}$ already have the same denominator, the addition can be done directly:
  $\frac{1}{4} + \frac{3}{4} = \frac{1 + 3}{4} = \frac{4}{4} = 1$.

Therefore, the correct solution to the expression is $1$.

To solve the exercise $\frac{1}{10} + \frac{3}{5} - \frac{1}{2}$, we must follow these steps:

Step 1: Find the Least Common Denominator (LCD).
The denominators we have are 10, 5, and 2. The LCD for these numbers is 10.

Step 2: Convert each fraction to have the common denominator of 10.
- $\frac{1}{10}$ is already with the denominator 10.
- Convert $\frac{3}{5}$:$\frac{3}{5} \times \frac{2}{2} = \frac{6}{10}$
- Convert $\frac{1}{2}$:
$\frac{1}{2} \times \frac{5}{5} = \frac{5}{10}$

Step 3: Perform the addition and subtraction.
Now operate: $\frac{1}{10} + \frac{6}{10} - \frac{5}{10} = \frac{1 + 6 - 5}{10} = \frac{2}{10}$

Step 4: Simplify the result.
The fraction $\frac{2}{10}$ simplifies to $\frac{1}{5}$ because both the numerator and denominator are divisible by 2.

Therefore, the solution to the problem is $\frac{1}{5}$.

To solve the expression $\frac{2}{7} + \frac{1}{2} - \frac{7}{14}$, we need to add and subtract fractions, which requires a common denominator.

• Step 1: Identify the denominators and find the least common denominator (LCD):
  • The denominators are 7, 2, and 14.
  • The LCM of 7, 2, and 14 is 14.
• Step 2: Convert each fraction to have the denominator 14:
  • $\frac{2}{7} = \frac{2 \times 2}{7 \times 2} = \frac{4}{14}$
  • $\frac{1}{2} = \frac{1 \times 7}{2 \times 7} = \frac{7}{14}$
  • $\frac{7}{14}$ is already in the form with denominator 14.
• Step 3: Perform the operations using the common denominator:
  • Add the first two fractions: $\frac{4}{14} + \frac{7}{14} = \frac{11}{14}$
  • Subtract the third fraction: $\frac{11}{14} - \frac{7}{14} = \frac{4}{14}$
• Step 4: Simplify the result if necessary:
  • $\frac{4}{14}$ is already simplified to its simplest form.

Therefore, the solution to the expression $\frac{2}{7} + \frac{1}{2} - \frac{7}{14}$ is $\frac{4}{14}$, which matches choice 3.

To solve the expression $\frac{4}{4} \times \frac{1}{2} + \frac{3}{8}$, follow these steps:

• Step 1: Simplify $\frac{4}{4}$. Since $\frac{4}{4} = 1$, the expression becomes $1 \times \frac{1}{2} + \frac{3}{8}$.
• Step 2: Perform the multiplication.
  Calculate $1 \times \frac{1}{2} = \frac{1}{2}$.
• Step 3: Add $\frac{1}{2}$ to $\frac{3}{8}$.
  First, convert $\frac{1}{2}$ to an equivalent fraction with a denominator of 8: $\frac{1}{2} = \frac{4}{8}$.
• Step 4: Now, add the fractions: $\frac{4}{8} + \frac{3}{8} = \frac{7}{8}$.

Thus, the final result is $\frac{7}{8}$.

To solve the given expression, follow these steps:

First, multiply the fractions $\frac{3}{5}$ and $\frac{1}{2}$:

$\frac{3}{5} \times \frac{1}{2} = \frac{3 \times 1}{5 \times 2} = \frac{3}{10}$

Now, add $\frac{3}{10}$ to the result of the multiplication:

Since the fractions $\frac{3}{10}$ and $\frac{3}{10}$ have the same denominator, we can simply add their numerators:

$\frac{3}{10} + \frac{3}{10} = \frac{3 + 3}{10} = \frac{6}{10}$

Simplify $\frac{6}{10}$ by dividing both the numerator and the denominator by their greatest common divisor, which is 2:

$\frac{6}{10} = \frac{6 \div 2}{10 \div 2} = \frac{3}{5}$

Therefore, the solution to the problem is $\frac{3}{5}$.

To solve the given problem, we will follow these steps:

• Step 1: Perform the multiplication of the fractions.
• Step 2: Simplify the result, if applicable.
• Step 3: Add the simplified fractional result to the given fraction, ensuring the denominators align properly.
• Step 4: Simplify the final result, if necessary.

Let's go through each step:

Step 1: Multiply the fractions $\frac{2}{3} \times \frac{2}{3} = \frac{2 \times 2}{3 \times 3} = \frac{4}{9}$.

Step 2: The result from step 1 is $\frac{4}{9}$, which cannot be further simplified.

Step 3: Add the result from Step 2 to $\frac{4}{9}$ given in the problem:
We have two fractions $\frac{4}{9}$ and $\frac{4}{9}$, and since they already have a common denominator, we add them directly:
$\frac{4}{9} + \frac{4}{9} = \frac{4 + 4}{9} = \frac{8}{9}$.

Step 4: The fraction $\frac{8}{9}$ is already in its simplest form.

Therefore, the solution to the problem is $\frac{8}{9}$.

To solve the problem, follow these steps:

• Step 1: Convert each fraction to have a common denominator.
• Step 2: Add and subtract the fractions.
• Step 3: Simplify the result.

Let's work through these steps:

Step 1: Find the Least Common Denominator (LCD) of the fractions involved. The denominators are 6, 4, and 12. The LCM of these numbers is 12, so the LCD is 12.

Convert each fraction to this common denominator:

• $\frac{3}{6}$ becomes $\frac{3 \times 2}{6 \times 2} = \frac{6}{12}$
• $\frac{2}{4}$ becomes $\frac{2 \times 3}{4 \times 3} = \frac{6}{12}$
• $\frac{1}{12} \text{ remains } \frac{1}{12}$

Step 2: Perform the operations using these equivalent fractions: $\frac{6}{12} + \frac{6}{12} - \frac{1}{12} = \frac{6 + 6 - 1}{12} = \frac{11}{12}$

Step 3: Check if the result can be simplified further. In this case, $\frac{11}{12}$ is already in simplest form.

Therefore, the solution to the problem is $\frac{11}{12}$.

To solve the problem, $\frac{1}{2}:\frac{1}{2}-\frac{1}{4}$, follow these steps:

• Step 1: First, interpret the division $\frac{1}{2} : \frac{1}{2}$ as multiplication by the reciprocal. This becomes $\frac{1}{2} \times \frac{2}{1}$.
• Step 2: Perform the multiplication: $\frac{1}{2} \times \frac{2}{1} = \frac{1 \times 2}{2 \times 1} = \frac{2}{2} = 1.$
• Step 3: Next, subtract $\frac{1}{4}$ from 1: $1 - \frac{1}{4} = \frac{4}{4} - \frac{1}{4} = \frac{3}{4}.$

Therefore, the solution to the problem is $\frac{3}{4}$.

To solve the problem $\frac{1}{4} : \frac{1}{2} + \frac{1}{4}$, follow these steps:

Step 1: Perform the division $\frac{1}{4} : \frac{1}{2}$.

• When dividing by a fraction, multiply by the reciprocal. Hence, $\frac{1}{4} : \frac{1}{2}$ becomes $\frac{1}{4} \times \frac{2}{1}$.
• Multiply the numerators: $1 \times 2 = 2$.
• Multiply the denominators: $4 \times 1 = 4$.
• So, $\frac{1}{4} \times \frac{2}{1} = \frac{2}{4} = \frac{1}{2}$ after simplification.

Step 2: Now add the result from Step 1 to $\frac{1}{4}$.

• We need to add $\frac{1}{2} + \frac{1}{4}$.
• Convert $\frac{1}{2}$ to have a common denominator with $\frac{1}{4}$. $\frac{1}{2} = \frac{2}{4}$.
• Add the fractions: $\frac{2}{4} + \frac{1}{4} = \frac{3}{4}$.

Therefore, the solution to the problem is $\frac{3}{4}$.

To solve the problem $\frac{3}{4} \times \frac{1}{2} + \frac{5}{8}$, we'll follow these steps:

• Step 1: Multiply the fractions $\frac{3}{4} \times \frac{1}{2}$.
• Step 2: Add the result to $\frac{5}{8}$.

Now, let's work through the steps:

Step 1: Compute the product of the first two fractions:
$\frac{3}{4} \times \frac{1}{2} = \frac{3 \times 1}{4 \times 2} = \frac{3}{8}$

Step 2: Add the resulting fraction to $\frac{5}{8}$ by finding a common denominator:

The fractions $\frac{3}{8}$ and $\frac{5}{8}$ already have the same denominator, so we can simply add them:
$\frac{3}{8} + \frac{5}{8} = \frac{3 + 5}{8} = \frac{8}{8} = 1$

Therefore, the solution to the problem is $1$.

To solve the problem $\frac{5}{8} + \frac{1}{2} - \frac{1}{4}$, we will follow these steps:

Step 1: Find the least common denominator (LCD).
The denominators are 8, 2, and 4. The least common multiple of these numbers is 8.

Step 2: Convert each fraction to have a denominator of 8.
- $\frac{5}{8}$ already has the denominator 8.
- $\frac{1}{2} = \frac{1 \times 4}{2 \times 4} = \frac{4}{8}$.
- $\frac{1}{4} = \frac{1 \times 2}{4 \times 2} = \frac{2}{8}$.

Step 3: Perform the arithmetic operations.
First, add $\frac{5}{8}$ and $\frac{4}{8}$:
$\frac{5}{8} + \frac{4}{8} = \frac{5 + 4}{8} = \frac{9}{8}$.
Then, subtract $\frac{2}{8}$ from $\frac{9}{8}$:
$\frac{9}{8} - \frac{2}{8} = \frac{9 - 2}{8} = \frac{7}{8}$.

Therefore, the solution to the problem is $\frac{7}{8}$.

To solve the problem $\frac{3}{5} \times \frac{2}{3} + \frac{2}{5}$, we proceed with the following steps:

• Step 1: Multiply the fractions $\frac{3}{5}$ and $\frac{2}{3}$.

The multiplication yields:

$\frac{3}{5} \times \frac{2}{3} = \frac{3 \times 2}{5 \times 3} = \frac{6}{15}$

• Step 2: Simplify the product $\frac{6}{15}$.

Both 6 and 15 share a common factor of 3:

$\frac{6}{15} = \frac{6 \div 3}{15 \div 3} = \frac{2}{5}$

• Step 3: Add $\frac{2}{5}$ to the simplified result $\frac{2}{5}$.

Since the fractions $\frac{2}{5}$ and $\frac{2}{5}$ have the same denominator, add the numerators while keeping the denominator:

$\frac{2}{5} + \frac{2}{5} = \frac{2+2}{5} = \frac{4}{5}$

Therefore, the solution to the problem is $\frac{4}{5}$.

To solve this mathematical problem, follow these steps:

• Step 1: Multiply the fractions $\frac{3}{4}$ and $\frac{3}{4}$.
• Step 2: Subtract $\frac{1}{4}$ from the product obtained in Step 1.

Let's execute each step in detail:

Step 1: Calculate the product of $\frac{3}{4}$ and $\frac{3}{4}$.

To multiply two fractions, multiply their numerators and their denominators separately:

$\frac{3}{4} \times \frac{3}{4} = \frac{3 \times 3}{4 \times 4} = \frac{9}{16}$

Step 2: Subtract $\frac{1}{4}$ from $\frac{9}{16}$.

Before we subtract $\frac{1}{4}$ from $\frac{9}{16}$, we need a common denominator. The common denominator for these fractions is 16:

$\frac{1}{4} = \frac{1 \times 4}{4 \times 4} = \frac{4}{16}$

Now subtract $\frac{4}{16}$ from $\frac{9}{16}$:

$\frac{9}{16} - \frac{4}{16} = \frac{9 - 4}{16} = \frac{5}{16}$

Therefore, the solution to the given problem is $\frac{5}{16}$.

To solve this problem, let's follow these steps:

• Step 1: Multiply the fractions. Calculate $\frac{2}{3} \times \frac{1}{3}$.
• Step 2: Add the product to another fraction. Add the result to $\frac{2}{9}$.

Now, let's work through the calculations:

Step 1: Multiply $\frac{2}{3}$ by $\frac{1}{3}$.

The formula for multiplying fractions is:

$\frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d}$.

Substitute the values:

$\frac{2}{3} \times \frac{1}{3} = \frac{2 \times 1}{3 \times 3} = \frac{2}{9}$.

Step 2: Add $\frac{2}{9}$ to the product.

We found in Step 1 that $\frac{2}{3} \times \frac{1}{3} = \frac{2}{9}$.

Now add $\frac{2}{9} + \frac{2}{9} = \frac{2 + 2}{9} = \frac{4}{9}$.

Therefore, the solution to the expression is $\frac{4}{9}$.