Multiplication and Division of Signed Mumbers: Substituting parameters

Let's start with the first option.

Let's substitute the data into the expression:

$-\frac{8}{-4}=$

First, we can see that in the fraction we are dividing a positive number by a negative number, therefore the result will be negative:

$-\times-\frac{8}{4}=$

Now we can see that we have a multiplication between two negative numbers and therefore the result must be positive:

$+\frac{8}{4}=2$

Let's continue with the second option.

Let's substitute the data into the expression:

$-\frac{-8}{4}=$

First, we can see that in the fraction we are dividing a positive number by a negative number, therefore the result will be negative:

$-\times-\frac{8}{4}=$

Now we can see that we have a multiplication between two negative numbers and therefore the result must be positive:

$+\frac{8}{4}=2$

Therefore the final answer is:

$1,2=+2$

First, we replace the data in the exercise

-(-3)*5 = 

To better understand the minus sign multiplied at the beginning, we will write it like this:

-1*-3*5 = 

Now we see that we have an exercise that is all multiplication,

We will solve according to the order of arithmetic operations, from left to right:

-1*-3 = 3

3*5 = 15

Let's start with the first option.

Let's substitute the numbers in the given expression:

$\frac{-4}{-(-(-\frac{1}{3})}=$

Let's remember the rule:

$-(-x)=+x$

Therefore:

$\frac{-4}{-(+\frac{1}{3})}=$

Let's remember the rule:

$-(+x)=-x$

Now the exercise we got is:

$\frac{-4}{-\frac{1}{3}}=$

Note that we are dividing between two negative numbers, so the result must be a positive number:

$\frac{-}{-}=+$

$\frac{4}{\frac{1}{3}}=$

Let's convert the division to multiplication and remember to switch between the numerator and denominator of the simple fraction:

$4\times\frac{3}{1}=\frac{12}{1}=12$

Let's move on to solve the second option.

Let's substitute the numbers in the given expression:

$\frac{-(-4)}{-(-(+\frac{1}{3})}=$

Let's remember the rules:

$-(-x)=+x$

$-(+x)=-x$

Now we get:

$\frac{+4}{-(-\frac{1}{3})}=\frac{+4}{+\frac{1}{3}}=$

Note that we are dividing between two positive numbers, so the result must be a positive number:

$\frac{+}{+}=+$

Let's convert the division to multiplication and remember to switch between the numerator and denominator of the simple fraction:

$4\times\frac{3}{1}=\frac{12}{1}=12$

The final answer is:

$1,2=+12$

Let's start with the first option.

Let's substitute the given data into the expression:

$0:-\frac{3}{409}+8=$

We'll solve the exercise from left to right, noting that we are first dividing by zero.

Let's remember the rule:

$\frac{0}{a}=0$

In other words, any number divided by zero will equal zero, therefore:

$\frac{0}{-\frac{3}{409}}=0$

Now we got the exercise:

$0+8=8$

Let's continue with the second option.

Let's substitute the given data into the expression:

$0:-\frac{-\frac{1}{205}}{-7}+3004=$

As we can see, just like in the first option, we are first dividing by zero.

Any number divided by zero will equal zero, therefore we got the exercise:

$0+3004=3004$

Therefore the final answer is:

$1=8,2=3004$

Let's start with the first option.

Let's substitute the data in the expression:

$-2\times(1):(1+8):\frac{1}{1}=$

We'll solve the multiplication (a negative number multiplied by a positive number gives a negative result), then solve what's in parentheses, and finally the simple fraction:

$-2:9:1=$

We'll solve from left to right.

Let's write the division as a simple fraction:

$-\frac{2}{9}:1=-\frac{2}{9}$

Let's continue with the second option.

Let's substitute the data in the expression:

$-2\times(-1):(-1+8):\frac{1}{-1}=$

First, we'll solve the multiplication (we're multiplying two negative numbers so the result will be positive), then the parentheses, and finally the fraction (we're dividing a positive number by a negative number so the result will be negative):

$2:7:-1=$

We'll solve from left to right, let's write the division as a simple fraction:

$+\frac{2}{7}:(-1)=$

Since we're dividing a positive number by a negative number, the result must be negative:

$-\frac{2}{7}$

Therefore, the final answer is:

$1=-\frac{2}{9},2=-\frac{2}{7}$

Let's start with the first option.

Let's substitute the given values in the expression:

$3:(-(-9)):2=$

First, let's solve what's inside the parentheses, keeping the appropriate sign since minus times minus equals plus:

$3:9:2=$

We'll solve the exercise from left to right.

Let's write the division as a simple fraction:

$\frac{3}{9}:2=$

Let's break down 9 into a multiplication problem:

$\frac{3}{3\times3}:2=$

Let's reduce the 3 in both numerator and denominator:

$\frac{1}{3}:2=$

Let's convert the division to multiplication, remembering to switch between numerator and denominator accordingly:

$\frac{1}{3}:\frac{2}{1}=\frac{1}{3}\times\frac{1}{2}=\frac{1}{3\times2}=\frac{1}{6}$

Let's continue with the second option.

Let's substitute the given values in the expression:

$-4:(-16):3=$

Let's solve the exercise from left to right, writing the division as a simple fraction:

$\frac{-4}{-16}:3=$

Note that we are dividing two negative numbers, so the result must be a positive number:

$\frac{4}{16}:3=$

Let's break down 16 into a multiplication problem:

$\frac{4}{4\times4}:3=$

Let's reduce the 4 in both numerator and denominator and we get:

$\frac{1}{4}:3=$

Let's convert the division to multiplication, remembering to switch between numerator and denominator:

$\frac{1}{4}:3=\frac{1}{4}:\frac{3}{1}=\frac{1}{4}\times\frac{1}{3}=\frac{1}{4\times3}=\frac{1}{12}$

Therefore, the final answer is:

$1=\frac{1}{6},2=\frac{1}{12}$

Let's substitute the numbers into the formula:

$-(-5)\times(6+2)=$

Let's remember the rule:

$-(-x)=+x$

Let's write the exercise in the appropriate form:

$5\times(6+2)=$

Let's solve the expression in parentheses:

$6+2=8$

We obtain the following exercise:

$5\times8=$

Therefore, the answer is:

$40$

Let's place the numbers in the formula:

$2\times10+(-3)=$

Let's remember the rule:

$+(-x)=-x$

Let's write the exercise in the appropriate form:

$2\times10-3=$

Let's solve the multiplication exercise:

$2\times10=20$

Now we get the exercise:

$20-3=$

Therefore, the answer is:

$17$

Let's substitute the numbers into the formula:

$-3\times(-2)+(-2)=$

Remember the rule:

$(-x)\times(-x)=+x$

First, let's solve the multiplication problem:

$-3\times-2=6$

We obtain the following expression:

$6+(-2)=$

Let's remember the rule:

$+(-x)=-x$

Let's write the expression in the appropriate form:

$6-2=$

Therefore, the answer is:

$4$

Let's start with the first option.

Let's substitute the data in the expression:

$-\frac{y:y}{-3}=$

Note that we are dividing between two negative numbers, therefore the result must be a positive number:

$\frac{-}{-}=+$

$+\frac{y:y}{3}=$

Let's remember the rule that any number divided by itself equals 1, therefore:

$\frac{y}{y}=1$

Now we got:

$\frac{1}{3}$

Let's continue with the second option.

Let's substitute the data in the expression:

$-\frac{z:-4.4}{z}=$

Let's reduce z in both numerator and denominator of the fraction and we get:

$-(1:-4.4)=$

Let's write the exercise as a simple fraction:

$-\frac{1}{-4.4}=$

Note that we are dividing between two negative numbers, therefore the result must be a positive number:

$\frac{-}{-}=+$

Let's convert 4.4 to a simple fraction, and we get:

$+\frac{1}{4\frac{2}{5}}=$

Let's write the denominator fraction as a complex fraction:

$+\frac{1}{4\frac{2}{5}}=\frac{1}{\frac{22}{5}}=$

Let's convert the fraction to a multiplication exercise, don't forget to switch between numerator and denominator:

$\frac{1}{\frac{22}{5}}=1\times\frac{5}{22}=\frac{5}{22}$

Therefore the final answer is:

$1=+\frac{1}{3},2=+\frac{5}{22}$

Let's start with the first option.

Let's substitute the given data into the expression:

$\frac{3}{-0.2}+3(-3)=$

We'll solve the exercise from left to right, first converting 0.2 to a simple fraction:

$\frac{3}{-\frac{1}{5}}+3(-3)=$

Now let's solve the multiplication problem, remembering that when we multiply a positive number by a negative number, the result must be negative:

$3\times(-3)=-9$

Now we have the exercise:

$\frac{3}{-\frac{1}{5}}+(-9)=$

Let's convert the division problem to a multiplication problem, remembering to switch between the numerator and denominator of the fraction:

$3\times-\frac{5}{1}+(-9)=$

Let's take -9 out of the parentheses and keep the appropriate sign:

$\frac{3\times(-5)}{1}-9=$$$

$3\times(-5)-9=$

$-15-9=-24$

Let's continue with the second option.

Let's substitute the given data into the expression:

$\frac{-4}{-3}+3(-(-4))=$

Let's solve the exercise from left to right.

Note that we are first dividing a negative number by a negative number, so the result must be positive:

$\frac{4}{3}+3(-(-4))=$

Let's open the parentheses and keep the appropriate sign:

$\frac{4}{3}+3\times(4)=$

Let's solve the multiplication problem:

$\frac{4}{3}+12=$

Let's break down the fraction into an addition problem:

$\frac{3+1}{3}+12=\frac{3}{3}+\frac{1}{3}+12=1+\frac{1}{3}+12=13\frac{1}{3}$

Therefore, the final answer is:

$1=-24,2=13\frac{1}{3}$

Let's start with the first option.

Let's write the division exercise in the expression as a simple fraction:

$\frac{m}{-3m}+4=$

Note that we can reduce the m in both the numerator and denominator of the fraction to get:

$\frac{1}{-3}+4=$

Since we are dividing a negative number by a positive number, we will get a negative result:

$-\frac{1}{3}+4=3\frac{2}{3}$

Let's continue with the second option.

Since in the previous exercise we saw that we can reduce the m in the numerator and denominator of the fraction, we'll do the same thing here and therefore reach the same result:

$3\frac{2}{3}$

Therefore, the final answer is that for any m the expression will equal -3 and two thirds.

Let's begin by inserting the given data into the formula:

$2\times(-2)+1=$

Remembering the rule:

$(+x)\times(-x)=-x$

Let's now solve the multiplication operation:

$2\times(-2)=-4$

In order to obtain the following expression:

$-4+1=$

Therefore, the answer is:

$-3$

Let's begin by inserting the known data into the formula:

$-6\times(-2+4)=$

First, let's solve the expression inside of the parentheses:

$-2+4=2$

We should obtain the following expression:

$-6\times2=$

Remembering the rule:

$(-x)\times(+x)=-x$

The answer should be:

$-12$

Let's substitute the numbers into the formula:

$2+(-3)\times(2+1)=$

Let's remember the rule:

$+(-x)=-x$

Let's write the exercise in the appropriate form:

$2-3\times(2+1)=$

Let's solve the expression in parentheses:

$2+1=3$

Now we get the exercise:

$2-3\times3=$

Now let's solve the multiplication exercise:

$3\times3=9$

Now we get the exercise:

$2-9=$

Therefore, the answer is:

$-7$

Let's begin by inserting the numbers into the formula:

$-1\times(-1\times5+3)=$

We must remember the following rule:

$(-x)\times(+x)=-x$

Let's now solve the expression inside of the parentheses:

$(-1\times5+3)=$

$-1\times5=-5$

$-5+3=-2$

We should obtain the following expression:

$-1\times(-2)=$

Let's again remember the rule:

$(-x)\times(-x)=+x$

Therefore, the correct answer is:

$2$