Power of a Quotient Rule for Exponents: Variables in the exponent of the power

Solve the following:

$\frac{a^{xy}}{a^{3xy}}-a^{2xy}$

$a^{-2xy}-a^{2xy}$

Solve for a:

$\frac{a^{3b}}{a^{2b}}\times a^b=$

$a^{2b}$

Insert the corresponding expression:

$\left(7\times2\right)^{2y-a-2}=$

a'+b' are correct

Insert the corresponding expression:

$\left(10\times5\right)^{4y-x}=$

$\frac{\left(10\times5\right)^{4y}}{\left(10\times5\right)^x}$

Insert the corresponding expression:

$\left(6\times9\right)^{10y}=$

A'+C' are correct

Insert the corresponding expression:

$\left(10\times4\right)^{5a}=$

$\frac{\left(10\times4\right)^{8a}}{\left(10\times4\right)^{3a}}$

Insert the corresponding expression:

$8^{ax-4}=$

$\frac{8^{ax}}{8^4}$

Insert the corresponding expression:

$10^{2x-a-1}=$

$\frac{10^{2x}}{10^{a+1}}$

Insert the corresponding expression:

$4^{3a}=$

$\frac{4^{7a}}{4^{4a}}$

Insert the corresponding expression:

$\left(4\times3\right)^{4x-y}=$

$\frac{\left(4\times3\right)^{4x}}{\left(4\times3\right)^y}$

Complete the exercise:

$\frac{a^{7+x}}{a^{10-2x}}$

$a^{-3+3x}$

Insert the corresponding expression:

$\frac{\left(xya\right)^{2x}}{\left(xya\right)^{ab}}=$

$\left(xya\right)^{2x-ab}$

Solve the exercise:

$\frac{a^{2x}}{a^y}\times\frac{a^{2y}}{a^{-y}}=$

$a^{2(x+y)}$