Simplify the Expression: a^(7+x)/a^(10-2x) Using Exponent Rules

Question

Complete the exercise:

a7+xa102x \frac{a^{7+x}}{a^{10-2x}}

Video Solution

Solution Steps

00:00 Simply
00:03 When dividing powers with equal bases
00:07 The power of the result equals the difference of the powers
00:11 We'll use this formula in our exercise, and subtract the powers
00:22 Let's calculate the power
00:35 And this is the solution to the question

Step-by-Step Solution

Note that in this problem there is a fraction where both the numerator and denominator contain terms with identical bases, therefore we will use the division law between terms with identical bases to solve the exercise:

cmcn=cmn \frac{c^m}{c^n}=c^{m-n}

Let's apply the aforementioned law:

a7+xa102x=a7+x(102x) \frac{a^{7+x}}{a^{10-2x}}=a^{7+x-(10-2x)}

In the first stage, we directly used the above exponents law and performed a simple subtraction between the exponent of the term in the numerator and the exponent of the term in the denominator, while using a common base. Since the term's exponent in the denominator is a two-term algebraic expression, we performed the subtraction carefully using parentheses.

We'll continue by simplifying the exponential expression, and use the distribution law to expand the parentheses, while remembering that the (-) sign before the parentheses is actually multiplication by minus 1:

a7+x(102x)=a7+x10+2x=a3+3x a^{7+x-(10-2x)}=a^{7+x-10+2x}=a^{-3+3x}

where in the second stage we combined like terms in the exponent.

We obtained the most simplified expression, so we are done.

Therefore, the correct answer is B.

Answer

a3+3x a^{-3+3x}