Power of a Quotient Rule for Exponents: System of equations with no solution

To simplify the expression $\frac{8^4}{8^9}$, we apply the rule of exponents for division:

• The quotient rule for exponents is $\frac{a^m}{a^n} = a^{m-n}$.

Since both the numerator and the denominator have the same base (8), we can apply this rule directly:

$\frac{8^4}{8^9} = 8^{4-9}$

Thus, the resulting expression is $8^{-5}$.

Reviewing the choices given:

• Choice 1: $8^{9-4}$ which equals $8^5$, is incorrectly stating the subtraction order.
• Choice 2: $8^{\frac{4}{9}}$ is incorrect, as it represents a different operation (taking the root) rather than division of exponents.
• Choice 3: $8^{4-9}$ is correct, as it correctly applies the quotient rule for exponents.
• Choice 4: $8^{4\times9}$ suggests multiplication of exponents, not applicable here.

Therefore, the correct answer is Choice 3: $8^{4-9}$, which simplifies to $8^{-5}$.

To solve the expression $\frac{5^7}{5^{10}}$, we need to apply the Power of a Quotient Rule for Exponents. This rule states that when dividing like bases, you subtract the exponents:

$\frac{a^m}{a^n} = a^{m-n}$.

In this particular case, the base is 5, and the exponents are 7 and 10. Using the rule, we subtract the exponent in the denominator from the exponent in the numerator:

• Numerator exponent = 7
• Denominator exponent = 10

The solution to the question is: $5^{7-10}$.

To solve the expression $\frac{7^{5b}}{7^{2b}}$, we will use the Power of a Quotient Rule for Exponents, which states that $\frac{a^m}{a^n} = a^{m-n}$ when $a$ is a nonzero number. This rule allows us to simplify expressions where the bases are the same.

1. Identify the base and the exponents in the expression. Here, the base is 7, and the exponents are $5b$ and $2b$.

2. Apply the Power of a Quotient Rule:
$\frac{7^{5b}}{7^{2b}} = 7^{5b - 2b}$

3. Simplify the expression in the exponent:
Calculate $5b - 2b = 3b$.

4. Therefore, the expression simplifies to $7^{3b}$.

However, according to the given correct answer, we are asked to provide the intermediate expression as well – that is, before calculating the difference:
So, the solution as an intermediate step is:
$7^{5b - 2b}$

The explicit step-by-step answer provided in the question's solution matches our intermediate form.

The solution to the question is:

$7^{5b - 2b}$

To solve the expression $\frac{2^a}{2^2}$, we will apply the Power of a Quotient Rule for Exponents, which states that when you divide two powers with the same base, you subtract the exponents.

Here are the steps:

• Identify the base: Both the numerator and the denominator have the same base, which is 2.

• Apply the quotient rule of exponents: $\frac{b^m}{b^n} = b^{m-n}$. By applying this rule:

  $\frac{2^a}{2^2} = 2^{a-2}$.

Thus, by utilizing the rule, we find that:

$\frac{2^a}{2^2} = 2^{a-2}$.

The solution to the question is: $2^{a-2}$

To solve this problem, we apply the Power of a Quotient Rule for Exponents, which states that for any non-zero base $a$ and integers $m$ and $n$, the expression $\frac{a^m}{a^n} = a^{m-n}$. In this case, our base $a$ is 11.

Given the expression $\frac{11^{2a}}{11^5}$, let's simplify it using the rule:

• The numerator is $11^{2a}$.
• The denominator is $11^5$.

Applying the rule:

$\frac{11^{2a}}{11^5} = 11^{2a-5}$

Thus, the expression simplifies to $11^{2a-5}$.

So, the solution to the question is: $11^{2a-5}$

To solve this problem, we'll follow a systematic approach to simplify $\frac{a^9}{a^4}$ using exponent rules:

• Step 1: Identify the expression.
  We are given $\frac{a^9}{a^4}$ and asked to simplify it.
• Step 2: Apply the Quotient Rule for Exponents.
  According to the quotient rule, when dividing two expressions with the same base, we subtract the exponents. Given
  $\frac{a^m}{a^n} = a^{m-n}$,
  we apply this rule to our expression:

$a^{9-4}$

• Step 3: Simplify the Expression.
  We simplify the exponent by performing the subtraction:
  $a^{9-4} = a^5$.

Thus, the simplified form of the expression $\frac{a^9}{a^4}$ is $\mathbf{a^5}$.

Now, let's match our simplified expression with the provided choices:

• Choice 1: $a^{9-4}$.
  This reflects the correct expression before computation.
• Choice 2: $a^{9+4}$.
  Incorrect, as it adds the exponents instead of subtracting.
• Choice 3: $a^{9\times4}$.
  Incorrect, as it multiplies the exponents instead of subtracting.
• Choice 4: $a^{\frac{9}{4}}$.
  Incorrect, as it divides the exponents instead of subtracting.

Hence, the correct choice is Choice 1: $a^{9-4}$, which is the correct representation before simplification.

I am confident in the correctness of this solution.

To solve this problem, we'll follow these steps:

• Step 1: Identify the common base in both the numerator and the denominator.

• Step 2: Apply the Power of a Quotient Rule for Exponents.

• Step 3: Simplify the expression by subtracting the exponents.

Now, let's work through each step:
Step 1: Notice that both the numerator $x^6$ and the denominator $x^2$ share the same base, $x$.
Step 2: The Power of a Quotient Rule states that $\frac{a^m}{a^n} = a^{m-n}$. We apply this rule to our expression, obtaining $x^{6-2}$.
Step 3: Simplifying $6 - 2$, we find that the expression simplifies to $x^4$.

Therefore, the simplified form of the expression $\frac{x^6}{x^2}$ is $x^4$.

Considering the given answer choices:

• Choice 1: $x^{6+2}$ is incorrect because it involves adding the exponents, which does not follow the rules for division of powers.

• Choice 2: $x^{6-2}$ is the correct as the setup simplification, and can be fully simplified to yield $x^4$ for clarity.

• Choice 3: $x^{6\times2}$ is incorrect because it multiplies the exponents, which is not applicable in division.

• Choice 4: $x^{\frac{6}{2}}$ is not directly applicable as it assumes a different interpretation not aligning with subtraction of exponents for division.

The correct choice is represented by choice 2, $x^{6-2}$.

To solve this problem, we will apply the Quotient Rule for exponents, which helps simplify expressions where both the numerator and denominator share the same base.

• Step 1: Identify the given information.
  We are given the expression $\frac{b^{11}}{b^8}$.
• Step 2: Apply the Quotient Rule for exponents.
  According to the Quotient Rule, $\frac{b^m}{b^n} = b^{m-n}$. Here, $m = 11$ and $n = 8$.
• Step 3: Subtract the exponent of the denominator from the exponent of the numerator.
  Calculate $11 - 8 = 3$, leading to the simplified expression $b^3$.

Therefore, the simplified form of the given expression is $b^{3}$.

When considering the choices:

• Choice 1: $b^{11+8}$ adds the exponents, which is incorrect for division.
• Choice 2: $b^{11\times8}$ multiplies the exponents, also incorrect for division.
• Choice 3: $b^{\frac{11}{8}}$ divides the exponents, which is incorrect for division.
• Choice 4: $b^{11-8}$, correctly subtracts the exponents as per the Quotient Rule.

Thus, the correct choice is Choice 4: $b^{11-8}$, which simplifies to $b^3$.

We are given the expression: $\frac{x^{18}}{x^7}$.

To simplify this, we use the Power of a Quotient Rule for Exponents. This rule states that when dividing like bases, you subtract the exponent in the denominator from the exponent in the numerator.

So, according to this rule:
$\frac{x^m}{x^n} = x^{m-n}$.

Apply this rule to our expression: $\frac{x^{18}}{x^7} = x^{18-7}$.

Simplify the exponent by subtracting: $18-7 = 11$.

Therefore, the simplified expression is: $x^{11}$.

However, the expected form of the answer once applying the rule (before simplification) is: $x^{18-7}$.

The solution to the question is: $x^{18-7}$.

We are given the expression: $\frac{y^{20}}{y^{11}}$

To solve this, we will use the rule for exponents known as the Power of a Quotient Rule, which states that when you divide two expressions with the same base, you can subtract the exponents: $\frac{a^m}{a^n} = a^{m-n}$.

Applying this rule to our expression:

$\frac{y^{20}}{y^{11}} = y^{20-11}$

After simplifying, we have:

$y^{9}$

The solution to the question is: $y^{9}$

We need to simplify the expression $\frac{4^5}{4^x}$.

According to the rules of exponents, specifically the power of a quotient rule, when you divide like bases you subtract the exponents. The rule is written as:

• $\frac{a^m}{a^n} = a^{m-n}$

This means we take the exponent in the numerator and subtract the exponent in the denominator. Let's apply this rule to our expression:

$\frac{4^5}{4^x} = 4^{5-x}$

Hence, the simplified form of the expression is $4^{5-x}$.

The solution to the question is: $4^{5-x}$

We start with the expression: $\frac{9^x}{9^y}$.
We need to simplify this expression using the Power of a Quotient Rule for exponents, which states that $\frac{a^m}{a^n} = a^{m-n}$. Here, the base $a$ must be the same in both the numerator and the denominator, and we subtract the exponent of the denominator from the exponent of the numerator.

Applying this rule to our expression, we identify $a = 9$, $m = x$, and $n = y$. So we have:

• $a = 9$
• $m = x$
• $n = y$

Using the Power of a Quotient Rule, we therefore rewrite the expression as:

$a^{m-n} = 9^{x-y}$

Hence, the simplified expression of $\frac{9^x}{9^y}$ is $9^{x-y}$.

The solution to the question is: $9^{x-y}$

Let's simplify the expression $\frac{\left(15\times4\right)^3}{\left(4\times15\right)^9}$:

We start by recognizing that both the numerator and the denominator share the same base: $(15 \times 4)$. Therefore, we have a quotient of powers with the same base:

$\frac{\left(15\times4\right)^3}{\left(15\times4\right)^9}$

According to the rules of exponents, when dividing like bases, we subtract the exponents:

$(15 \times 4)^{3 - 9}$

Subtracting the exponents, we have:

$(15 \times 4)^{-6}$

This matches with one of the choices:

• Choice 1: $(15\times4)^{3-9}$ is correct, as it simplifies to $(15\times4)^{-6}$.
• Choice 2 and Choice 3 involve incorrect operations on exponents (multiplication and addition respectively).
• Choice 4 reverses the subtraction order, which results differently in base powers than what is needed.

Therefore, the correct answer to the problem is:
$\left(15\times4\right)^{3-9}$.

Let's solve the expression $\frac{(3 \times x)^8}{(3 \times x)}$ step by step using the Power of a Quotient Rule for Exponents.

The expression given is:

$\frac{(3 \times x)^8}{(3 \times x)}$

The Power of a Quotient Rule states that for any non-zero number $a$, and integers $m$ and $n$, the expression $\frac{a^m}{a^n}$ is equal to $a^{m-n}$.

In this problem, $a$ is $3 \times x$, $m = 8$, and $n = 1$.

Applying the Power of a Quotient Rule:

• Subtract the exponent in the denominator from the exponent in the numerator. So we have $(3 \times x)^{8-1}$.

Thus, the simplified form of the expression is:

$(3 \times x)^{7}$

The solution to the question is: $(3 \times x)^{7}$.

Let's solve the given expression step by step by using the power of a quotient rule for exponents. The rule states that $\frac{a^n}{a^m} = a^{n-m}$, where $a$ is any non-zero number, and $n$ and $m$ are integers.

Given the expression: $\frac{\left(2\times3\right)^{6}}{\left(2\times3\right)^3}$

• First, apply the power of a quotient rule for exponents formula: $\frac{\left(2\times3\right)^{6}}{\left(2\times3\right)^3} = \left(2\times3\right)^{6-3}$.

• The exponent in the numerator is 6, and the exponent in the denominator is 3.

• Subtract the exponent in the denominator from the exponent in the numerator: $6 - 3 = 3$.

• Thus, the expression simplifies to: $\left(2\times3\right)^3$.

The solution to the question is: $\left(2\times3\right)^{6-3}$

Let's solve the given mathematical expression step by step using the rules of exponents.

• We start with the expression: $\frac{\left(11\times12\right)^{30}}{\left(11\times12\right)^{30}}$.

• According to the rules of exponents, specifically the quotient rule, which states that when you divide powers with the same base, you subtract their exponents: $\frac{a^m}{a^n} = a^{m-n}$.

• Applying this rule to the expression, since the base $11 \times 12$ is the same in both the numerator and the denominator, we subtract the exponents:

  • The numerator is $\left(11\times12\right)^{30}$ and the denominator is $\left(11\times12\right)^{30}$.

  • Therefore, $\frac{\left(11\times12\right)^{30}}{\left(11\times12\right)^{30}} = \left(11\times12\right)^{30-30}$.

• Simplifying further, we have:

  • $\left(11\times12\right)^{30-30} = \left(11\times12\right)^{0}$.

  • Any non-zero number raised to the power of 0 is 1. However, here the expression is left in the form of an exponent as requested.

The solution to the question is: $\left(11\times12\right)^{30-30}$

The given expression is $\frac{\left(15\times2\right)^{17}}{\left(2\times15\right)^{13}}$. To simplify
using the rule of exponents known as the Power of a Quotient Rule, which states

When you divide like bases you subtract the exponents:

$\frac{a^m}{a^n} = a^{m-n}$.

First, notice that both the numerator and denominator have the base $15 \times 2$. Therefore, we can simplify by subtracting the exponents in the numerator and the denominator:

• Numerator's exponent: 17
• Denominator's exponent: 13

The given expression is: $\frac{\left(x\times a\right)^{30}}{\left(a\times x\right)^{15}}$

To solve this, we can apply the quotient rule for exponents. The quotient rule states that $\frac{b^m}{b^n} = b^{m-n}$, where $b$ is the base and $m$ and $n$ are the exponents.

In this problem, both the numerator and the denominator have the same base $\left(x \times a\right)$. Thus, the expression simplifies by subtracting the exponents:

• The exponent of the numerator is 30.
• The exponent of the denominator is 15.

Applying the power of a quotient rule, we have:

$\left(x \times a\right)^{30-15}$

Thus, the simplified expression is $\left(x \times a\right)^{15}$.

The solution to the question is: $\left(x \times a\right)^{15}$.

To solve the equation, you're required to simplify the expression $\frac{\left(9\times7\right)^{2x}}{\left(7\times9\right)^{2y}}$. This expression contains powers of quotients, and you can apply the properties of exponents to simplify it.

Let's go through the solution step by step:

• Both the numerator and the denominator are raised to some powers. Notice that the base of both the numerator and the denominator is $(9 \times 7)$, since $9 \times 7 = 63$ and $7 \times 9 = 63$.
• Therefore, you can rewrite the expression as $\frac{(63)^{2x}}{(63)^{2y}}$.
• According to the property of exponents, $\frac{a^m}{a^n} = a^{m-n}$, where $a$ is a non-zero number. Apply this rule:
• $\frac{(63)^{2x}}{(63)^{2y}} = (63)^{2x-2y}$

With the simplification completed, you get $\left(63\right)^{2x-2y}$.

Finally, substitute back $63$ for $9 \times 7$, and you can express the result as $\left(9 \times 7\right)^{2x-2y}$.

The solution to the question is: $\left(9\times7\right)^{2x-2y}$.

To solve the given expression $\frac{\left(12\times2\right)^5}{\left(2\times12\right)^{3y}}$, we need to apply the rule for the power of a quotient for exponents: $\frac{a^m}{a^n} = a^{m-n}$.

The expressions in both the numerator and the denominator have the same base $\left(12 \times 2\right)$. Therefore, the expression can be rewritten as:

• Base: $\left(12 \times 2\right)$
• Exponent in the numerator: $5$
• Exponent in the denominator: $3y$

Now, applying the quotient rule:

$\frac{\left(12\times2\right)^5}{\left(2\times12\right)^{3y}} = \left(12\times2\right)^{5-3y}$

The solution to the question is:

$\left(12\times2\right)^{5-3y}$