Triangle similarity criteria

There are three criteria by which we can see the similarity between triangles:

Definition: Two triangles are similar if they have two respectively equal angles.

Given the two triangles:

$Δ ABC$
$Δ DEF$

Likewise we know that

$∢A=∢D$
$∢B=∢D$

Prove that the two triangles are similar.

The proof is immediate. We will rely on the criterion we have just learned. Let's note that we have been given two respectively equal angles in the two triangles. We will write it down as follows:

$∢A=∢D$ (angle)
$∢B=∢E$ (angle).

It follows that:
$Δ ABC$ ~ $Δ DEF$ (According to the similarity criterion Angle - Angle).

We observe that, if in two triangles there is equivalence between two pairs of corresponding angles, there must be equivalence between the third pair, since the sum of the internal angles of a triangle is always$180°$. This is the explanation of the first criterion of similarity: Angle - Angle.

Definition: Side - Angle - Side (SAS): Two triangles are similar if the ratio between two pairs of sides and also the angle they form are equal.

Given the two triangles
$Δ ABC$
$Δ DEF$

We also know that:
$BC = 4$
$CA = 6$
$EF = 2$
$FD = 3$
$∢F=∢C$

Prove that the triangles are similar and calculate the similarity ratio.

Demonstration:
We will rely on the second criterion of similarity that we just learned: Side - Angle - Side.

Let's pay attention to the relationship between the length of the sides:
$\frac{FD}{CA}=\frac{3}{6}=\frac{1}{2}$

$\frac{EF}{BC}=\frac{2}{4}=\frac{1}{2}$

That is, we see that the ratio between two pairs of sides is equal.
Also the datum
$∢F=∢C$

That is, the angles formed between the two pairs of sides are equal.
From the above we can deduce that

$Δ ABC$ ~ $Δ DEF$ (According to the similarity criterion Side - Angle - Side).

The similarity ratio is $1:2$

Side - Side - Side (SSS): Two triangles are similar if the proportion between all their sides (similarity ratio) is equal in both triangles.
Given the two triangles:
$Δ ABC$
$Δ DEF$

Likewise we know that:
$DE = 2$
$EF = 3$
$FD = 5$
$AB = 3$
$BC = 4.5$
$AC = 7.5$

All data are shown in the illustration:

Prove that the two triangles are similar.

Proof: We will use the similarity criterion we just learned, Side, Side, Side.

We will see that the following is true

$\frac{FD}{CA}=\frac{5}{7.5}=\frac{2}{3}$

$\frac{DE}{AB}=\frac{2}{3}$

$\frac{EF}{BC}=\frac{3}{4.5}=\frac{2}{3}$

That is to say that the proportion between the three sides of a triangle and the three sides of the other is equal.

Therefore, we can deduce that $Δ ABC$ ~ $Δ DEF$ (According to the similarity criterion Side - Side - Side).

The similarity ratio is the relation we saw, that is, $2:3$