Fill in the missing number:
We have hundreds of course questions with personalized recommendations + Account 100% premium
Fill in the missing number:
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: We hypothesize that the number could be 1, given that raising 1 to any power yields 1.
Step 2: Verify , which is true since any real number 1 raised to any integer power remains 1.
Step 3: As a check for understanding: with odd powers greater than 1, attempts with as choices lead to , which doesn’t meet the requirement, reinforcing .
Therefore, the solution to the problem is 1, choice number 4.
1
\( 0+0.2+0.6= \) ?
You're thinking of complex numbers! In real numbers, only 1 raised to any power gives 1. Complex 7th roots like aren't typically covered at this level.
Great question! Let's check: because 7 is odd. Since , this doesn't work. Odd powers of negative numbers stay negative!
, not 1! Zero raised to any positive power always equals zero, never 1.
Think of it this way: 1 is the multiplicative identity. When you multiply 1 by itself any number of times, you always get 1 back. It's like adding zeros - they don't change the result!
Yes! For , both 1 and -1 work. For , we have 1 and -1. The pattern depends on whether the exponent is even or odd.
Get unlimited access to all 18 Powers and Roots - Basic questions, detailed video solutions, and personalized progress tracking.
Unlimited Video Solutions
Step-by-step explanations for every problem
Progress Analytics
Track your mastery across all topics
Ad-Free Learning
Focus on math without distractions
No credit card required • Cancel anytime