Solve ((9xyz)^3)^4 + (a^y)^x: Complex Compound Exponents

Question

((9xyz)3)4+(ay)x= ((9xyz)^3)^4+(a^y)^x=

Video Solution

Solution Steps

00:00 Simplify the expression
00:03 When there is a power of a power, the combined exponent is the product of the exponents
00:13 Let's use this formula in our exercise
00:20 Multiply the exponents
00:31 When there is a power of a product, all terms are raised to that power
00:41 Let's use this formula in our exercise
00:46 Raise each factor to the power
00:52 And this is the solution to the question

Step-by-Step Solution

We'll use the power rule for a power:

(bm)n=bmn (b^m)^n=b^{m\cdot n}

We'll apply this rule to the expression in the problem in two stages:

((9xyz)3)4+(ay)x=(9xyz)34+(ay)x=(9xyz)12+ayx ((9xyz)^3)^4+(a^y)^x= (9xyz)^{3\cdot4}+(a^y)^x=(9xyz)^{12}+a^{yx}

In the first stage, for good order, we applied the above power rule first to the first term in the expression and dealt with the outer parentheses, then we simplified the expression in the exponent while simultaneously applying the mentioned power rule to the second term in the sum in the problem's expression,

We'll continue and recall the power rule for powers that applies to parentheses containing multiplication of terms:

(wt)n=wntn (w\cdot t)^n=w^n\cdot t^n

We'll apply this power rule to the expression we got in the last stage:

(9xyz)12+(ay)x=912x12y12z12+ayx (9xyz)^{12}+(a^y)^x =9^{12} x^{12} y^{12}z^{12}+a^{yx}

When we applied the mentioned power rule to the first term in the sum in the expression we got in the last stage, and applied the power on the parentheses to each of the multiplication terms inside the parentheses,

Let's summarize the solution steps so far, we got that:

((9xyz)3)4+(ay)x=(9xyz)12+ayx=912x12y12z12+ayx ((9xyz)^3)^4+(a^y)^x=(9xyz)^{12}+a^{yx} =9^{12} x^{12} y^{12} z^{12}+a^{yx}

Therefore the correct answer is answer D.

Answer

912x12y12z12+ayx 9^{12}x^{12}y^{12}z^{12}+a^{yx}