Compare Square Areas: 6 vs 7 Side Length Analysis

Question

Given that the length of the sides of square 1 is 6

and the length of the side of square 2 is 7.

Which square has the larger area, 1 or 2?

00:00 Which square has a larger area?

00:03 Let's use the formula to calculate the square area (side squared)

00:06 Let's substitute appropriate values and solve to find the area

00:09 This is the area of square 1

00:12 Let's use the same method to find the area of square 2

00:20 Let's determine which area is larger

00:25 And this is the solution to the question

To solve this problem, we will calculate the area of each square and compare them:

Let's work through these steps:

Step 1:

The area of a square is calculated using the formula:

$\text{Area} = \text{side length}^2$

For square 1, the side length is 6:

$\text{Area}_1 = 6^2 = 36$

Step 2:

For square 2, the side length is 7:

$\text{Area}_2 = 7^2 = 49$

Step 3:

Now, compare the two areas:

$36$ (Area of square 1) is less than $49$ (Area of square 2).

Therefore, square 2 has a larger area.

Based on our calculations, the square with the larger area is square 2.