All Operations in the Order of Operations: Using powers

$6\sqrt{4}:6\sqrt{4}=$

$4$

$\frac{21:\sqrt{49}+2}{8-(2+2\times3)}=$

In the numerator we solve the square root exercise:

$\sqrt{49}=7$

In the denominator we solve the exercise within parentheses:

$(2+2\times3)=$

$2+6=8$

The exercise we now have is:

$\frac{21:7+2}{8-8}=$

We solve the exercise in the numerator of fractions from left to right:

$21:7=3$

$3+2=5$

We obtain the exercise:

$\frac{5}{8-8}=\frac{5}{0}$

Since it is impossible for the denominator of the fraction to be 0, it is impossible to solve the exercise.

Cannot be solved

$\frac{9m}{3m^2}\times\frac{3m}{6}=$

According to the laws of multiplication, we must first simplify everything into one exercise:

$\frac{9m\times3m}{3m^2\times6}=$

We will simplify and get:

$\frac{9m^2}{m^2\times6}=$

We will simplify and get:

$\frac{9}{6}=$

We will factor the expression into a multiplication:

$\frac{3\times3}{3\times2}=$

We will simplify and get:

$\frac{3}{2}=1.5$

$0.5m$

$\frac{8x^2}{4x}+3x=$

$5x$

What is the result of the following power?

$(\frac{2}{3})^3$

$\frac{8}{27}$