All Operations in the Order of Operations: Using 1

$8\times(5\times1)=$

According to the order of operations, we first solve the expression in parentheses:

$5\times1=5$

Now we multiply:

$8\times5=40$

40

$7\times1+\frac{1}{2}=$

According to the order of operations rules, we first insert the multiplication exercise into parentheses:

$(7\times1)+\frac{1}{2}=$

Let's solve the exercise inside the parentheses:

$7\times1=7$

And now we get the exercise:

$7+\frac{1}{2}=7\frac{1}{2}$

$7\frac{1}{2}$

$\frac{6}{3}\times1=$

According to the order of operations rules, we will solve the exercise from left to right, since there are only multiplication and division operations:

$\frac{6}{3}=2$

$2\times1=2$

$2$

$6+\text{8}.4\times1=$

According to the order of operations rules, we first insert the multiplication exercise into parentheses:

$6+(8.4\times1)=$

Let's solve the expression inside the parentheses:

$8.4\times1=8.4$

And we get the exercise:

$6+8.4=14.4$

14.4

$18-1\times0.1=$

According to the order of operations rules, we first enter the multiplication exercise into parentheses:

$18-(1\times0.1)=$

Let's solve the multiplication exercise:

$1\times0.1=0.1$

And we get the exercise:

$18-0.1=17.9$

17.9

$18+2\times1=$

According to the order of operations rules, we first enter the multiplication exercise into parentheses:

$18+(2\times1)=$

Let's solve the exercise inside the parentheses:

$2\times1=2$

Now we get the exercise:

$18+2=20$

20

$1\times\frac{1}{2}:2$

According to the order of operations rules, we will solve the exercise from left to right since there are only multiplication and division operations:

$1\times\frac{1}{2}=\frac{1}{2}$

$\frac{1}{2}:2=\frac{1}{4}$

1/4

$8\times(7\times1)=$

According to the order of operations, we must first solve the expression inside of the parentheses:

$7\times1=7$

Resulting in the following expression:

$8\times7=56$

56

$8:1+2=$

According to the order of operations in arithmetic, we first put the division problem in parentheses:

$(8:1)+2=$

Let's solve the problem inside the parentheses:

$8:1=8$

And we get the expression:

$8+2=10$

10

$\frac{6}{3}-1=$

According to the order of operations rules, we must first solve the fraction:

$\frac{6}{3}=2$

Resulting in the following expression:

$2-1=1$

$1$

$\frac{3}{2}\times1\times\frac{1}{3}=$

According to the order of operations rules, we will solve the exercise from left to right since there are only multiplication operations:

$\frac{3}{2}\times1=\frac{3}{2}$

$\frac{3}{2}\times\frac{1}{3}=$

We will multiply the three by three and get:

$\frac{1}{2}\times1=\frac{1}{2}$

1\over2$1\over2$