All Operations in the Order of Operations: Using 0

According to the order of operations rules, we first divide and then add:

$0:7=0$

$0+1=1$

According to the order of operations rules, since the exercise only involves addition operations, we will solve the problem from left to right:

$12+1=13$

$13+0=13$

According to the order of operations rules, since the exercise only involves addition operations, we will solve the problem from left to right:

$0+0.2=0.2$

$0.2+0.6=0.8$

According to the order of operations, since the exercise only involves addition operations, we will solve the problem from left to right:

$\frac{1}{2}+0=\frac{1}{2}$

$\frac{1}{2}+\frac{1}{2}=\frac{1}{1}=1$

According to the order of operations rules, since the exercise only involves addition and subtraction, we will solve the problem from left to right:

$9-0=9$

$9+0.5=9.5$

According to the order of operations rules, since the exercise only involves addition and subtraction operations, we will solve the problem from left to right:

$19+1=20$

$20-0=20$

According to the order of operations rules, we first divide and then add:

$0:3=0$

$2+0=2$

According to the order of operations, we first multiply and then add:

$3\times0=0$

$12+0=12$

According to the order of operations rules, we first solve the expression in parentheses:

$1-1=0$

And we get the expression:

$0.18+0=0.18$

According to the order of operations, we will solve the exercise from left to right.

$\frac{1}{2}=0.5$

$0.5+0.5=1$

$1-0=1$

According to the order of operations, we first solve the expression in parentheses:

$18-0=18$

Now we divide:

$18:3=6$

According to the order of operations, we'll first solve the expression in parentheses:

$19-1=18$

Now we have the expression:

$0\times18+2=$

According to the order of operations, we'll multiply first and then add:

$0\times18=0$

$0+2=2$

This simple example demonstrates the order of operations, which states that exponentiation precedes multiplication and division, which come before addition and subtraction, and that operations within parentheses come first,

In the given example, the operation of division between parentheses (the denominators) by a number (which is also in parentheses but only for clarification purposes), thus according to the order of operations mentioned we start with the parentheses that contain the denominators first, this parentheses that contain the denominators includes multiplication between two numbers which are also in parentheses, therefore according to the order of operations mentioned, we start with the numbers inside them, paying attention that each of these numbers, including the ones in strength, and therefore assuming that exponentiation precedes multiplication and division we consider their numerical values only in the first step and only then do we perform the operations of multiplication and division on these numbers:

$$$$$\lbrack(3^2-4-5)\cdot(4+\sqrt{16})-5 \rbrack:(-5)=\\ \lbrack(9-4-5)\cdot(4+4)-5 \rbrack:(-5)=\\ \lbrack0\cdot8-5 \rbrack:(-5)\\$Continuing with the simple division in parentheses ,and according to the order of operations mentioned, we proceed from the multiplication calculation and remember that the multiplication of the number 0 by any number will yield the result 0, in the first step the operation of subtraction is performed and finally the operation of division is initiated on the number in parentheses:

$\lbrack0\cdot8-5 \rbrack:(-5)= \\ \lbrack0-5 \rbrack:(-5)= \\ -5 :(-5)=\\ 1$ Therefore, the correct answer is answer c.

According to the order of operations rules, since the exercise only involves addition and subtraction, we will solve the problem from left to right:

$\frac{1}{4}+0=\frac{1}{4}$

$\frac{1}{4}-\frac{1}{4}=0$

$0-0=0$