6+64−4=
\( 6+\sqrt{64}-4= \)
\( 3\times3+3^2= \)
\( 7 + \sqrt{49} - 5 = \)
\( 3 \times 2 + \sqrt{81} = \)
\( 8 - \sqrt{16} \times 3 = \)
To solve the expression , we need to follow the order of operations (PEMDAS/BODMAS):
In this expression, we first need to evaluate the square root since it falls under the exponent category:
Next, we substitute the computed value back into the expression:
We then perform the addition and subtraction from left to right:
Thus, the final answer is:
10
Let's recall the order of operations:
Parentheses
Exponents and Roots
Multiplication and Division
Addition and Subtraction
There are no parentheses in this problem, so we'll start with exponents:
3*3+3² =
3*3+9 =
Let's continue to the next step, multiplication operations:
3*3+9 =
9 + 9 =
Now we're left with just a simple addition problem:
9+9= 18
And that's the solution!
18
First, evaluate the square root: .
Then, follow the order of operations (PEMDAS/BODMAS):
1. Addition:
2. Subtraction:
So, the correct answer is .
First, evaluate the square root: .
Then, follow the order of operations (PEMDAS/BODMAS):
1. Multiplication:
2. Addition:
So, the correct answer is .
First, evaluate the square root: .
Then, follow the order of operations (PEMDAS/BODMAS):
1. Multiplication:
2. Subtraction:
So, the correct answer is .
\( 10-5^2:5= \)
\( 15-4^2:2= \)
\( 20-3^3:3= \)
\( 8 + 3 \times 2 - 4^2 = \)
\( 6 - 3 + 5 \times 2^2 = \)
First, compute the power: .
Next, divide: .
Finally, subtract: .
First, compute the power: .
Next, divide: .
Finally, subtract: .
First, compute the power: .
Next, divide: .
Finally, subtract: .
First, follow the order of operations (BODMAS/BIDMAS):
Step 1: Calculate the exponent:
Step 2: Perform the multiplication:
Step 3: Perform the addition and subtraction from left to right:
The correct result is: .
First, follow the order of operations (BODMAS/BIDMAS):
Step 1: Calculate the exponent:
Step 2: Perform the multiplication:
Step 3: Perform the addition and subtraction from left to right:
The correct result is: .
\( 4 + \sqrt{49} \times 3 = \)
\( 5^2 - \sqrt{16} + 2 = \)
\( 81:3^2+4^2= \)
\( 64:2^3+5^2= \)
\( 5^3:5^2\times2^3= \)
First, solve the square root: .
Next, multiply 7 by 3: .
Finally, add 4 to 21: .
Start by calculating the power: .
Then, calculate the square root: .
Subtract 4 from 25: .
Finally, add 2: .
First, calculate the powers:
Now substitute these values into the expression:
Perform the division:
Finally, add the result to 16:
First, calculate the powers:
Now substitute these values into the expression:
Perform the division:
Finally, add the result to 25:
In the first stage, let's calculate the powers of each of the terms:
Now let's write the resulting expression:
Since the only operations in the expression are multiplication and division, we will solve the expression from left to right
In other words, we will divide first and then multiply:
40
\( \sqrt{16}\times\sqrt{25}+8^3\times3= \)
\( \sqrt{36}\times\sqrt{49}+7^2\times2= \)
\( 18^2-(100+\sqrt{9})= \)
\( 2\times(\sqrt{36}+9)= \)
\( (20-3\times2^2)^2= \)
The given expression is: .
First, calculate the square roots: and .
Multiply the square roots: .
Next, calculate the cube: .
Multiply the result by 3: .
Finally, add the two results: .
Thus, the answer is: .
The given expression is: .
First, calculate the square roots: and .
Multiply the square roots: .
Next, calculate the square: .
Multiply the result by 2: .
Finally, add the two results: .
Thus, the answer is: .
150
The given expression is
We need to follow the order of operations (PEMDAS/BODMAS), which stands for:
Parentheses
Exponents (i.e., powers and square roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
Let's solve step by step:
Step 1: Evaluate the exponent and the square root in the expression:
So, the expression becomes
Step 2: Simplify the parentheses:
So, the expression becomes
Step 3: Subtract:
Therefore, the value of the expression is 221.
221
Let's solve this problem step by step using the order of operations (PEMDAS: Parentheses, Exponents, Multiplication/Division, Addition/Subtraction):
1. First, let's focus on what's inside the parentheses:
2. We need to evaluate the square root first:
(because )
3. Now our expression looks like this:
4. Next, we perform the addition inside the parentheses:
5. Our expression is now:
6. Finally, we perform the multiplication:
Therefore,
This matches the provided correct answer of 30.
30
We begin by solving the expression inside the parentheses . According to the order of operations (PEMDAS/BODMAS), we first handle any calculations inside parentheses and deal with exponents before performing multiplication, division, addition, or subtraction.
Thus, equals .
64