Rules of Logarithms Combined: Applying the formula

To simplify the expression $3\log_76$, we apply the power property of logarithms, which states:

$a\log_b c = \log_b(c^a)$

Step 1: Identify the given expression: $3\log_76$.

Step 2: Apply the power property of logarithms:

$3\log_76 = \log_7(6^3)$

Step 3: Calculate $6^3$:

$6^3 = 6 \times 6 \times 6 = 36 \times 6 = 216$

Step 4: Substitute back into the logarithmic expression:

$\log_7(6^3) = \log_7216$

Therefore, the simplified expression is $\log_7216$.

Comparing with the answer choices, the correct choice is:

$\log_7216$

To solve the problem, let's use the rules of logarithms:

• Step 1: Recognize that we are dealing with the subtraction of logarithms sharing the same base, which calls for the identity $\log_b M - \log_b N = \log_b \left(\frac{M}{N}\right)$.
• Step 2: Apply this identity to the expression $\log_7 5 - \log_7 2$.
• Step 3: Realize that this can thus be expressed as a single logarithm: $\log_7 \left(\frac{5}{2}\right)$.
• Step 4: Simplify the fraction, yielding $\log_7 2.5$.

Therefore, the simplification results in the expression: $\log_7 2.5$.

This matches the correct answer from the given choices.

To solve the problem of evaluating $\log_2 9 - \log_2 3$, we apply the properties of logarithms as follows:

• Step 1: Recognize that the expression uses a subtraction of logarithms with the same base: $\log_2 9 - \log_2 3$.
• Step 2: Use the logarithmic subtraction rule: $\log_b A - \log_b B = \log_b \left(\frac{A}{B}\right)$.
• Step 3: Simplify using this rule: $\log_2 9 - \log_2 3 = \log_2 \left(\frac{9}{3}\right)$.
• Step 4: Perform the division: $\frac{9}{3} = 3$.
• Step 5: Therefore, $\log_2 \left(\frac{9}{3}\right) = \log_2 3$.

Thus, the simplified and evaluated result is $\log_2 3$.

To solve the problem of finding what $\log_m n \times \log_z r$ equals, we will apply some rules of logarithms:

Let's work through the solution step-by-step:

• Step 1: Apply the change of base formula.
• Step 2: Simplify the expression using properties of logarithms.
• Step 3: Identify the expression among the given choices.

Now, let's apply the steps:

Step 1: Use the change of base formula.
By the change of base formula, we know that:

$\log_m n = \frac{\log_k n}{\log_k m}$
$\log_z r = \frac{\log_k r}{\log_k z}$

for any base $k$. Using the natural logarithm base $(\ln)$ for simplicity, we substitute into these expressions:

$\log_m n = \frac{\ln n}{\ln m}$
$\log_z r = \frac{\ln r}{\ln z}$

Step 2: Simplify.

Now, multiply the two expressions:

$\log_m n \times \log_z r = \left(\frac{\ln n}{\ln m}\right) \times \left(\frac{\ln r}{\ln z}\right)$

Simplifying, we get:

$= \frac{\ln n \times \ln r}{\ln m \times \ln z}$

Step 3: Expression equivalence analysis.

By rearranging the terms using logarithmic properties, it follows that the expression simplifies to:

$\log_z n \times \log_m r$

Therefore, the solution to the problem is $\log_z n \times \log_m r$.

This matches option 1 in the multiple choice answers provided.

To solve the problem $\log_49 \times \log_{13}7$, we'll employ the change of base formula for logarithms:

• Step 1: Apply the change of base formula to each logarithm.
• Step 2: Use logarithm properties and analyze transformations for a match with choices.

Now, let's work through each step:
Step 1: Use the change of base formula on each log:
$\log_49 = \frac{\log_a 9}{\log_a 4}$ and $\log_{13}7 = \frac{\log_b 7}{\log_b 13}$, where $a$ and $b$ are arbitrary positive bases.
Both expressions use a common base not relevant for the solution but illustrate the transformation ability.

Step 2: We'll recombine and look for products that can utilize these, such as:

$\log_{13}9\times\log_47$ becomes $\frac{\log_a 9}{\log_a 13} \times \frac{\log_b 7}{\log_b 4}$
Applying cross multiplication or iteration forms, the structure aligns with the multiplication identity for this problem due to independence of base.

Therefore, the transformed expression satisfying the criteria is $\log_{13}9\times\log_47$.

To solve the problem, we employ the property of logarithms for subtraction:

• Step 1: Recognize the expression $\log_5 3 - \log_5 2$.
• Step 2: Apply the logarithmic property for subtraction, $\log_b a - \log_b c = \log_b \left( \frac{a}{c} \right)$.
• Step 3: Substitute into the property: $\log_5 3 - \log_5 2 = \log_5 \left( \frac{3}{2} \right)$.

By applying the property, we simplify the expression to $\log_5 \frac{3}{2}$. This is equivalent to $\log_5 1.5$. Therefore:

Therefore, the result of the expression is $\log_5 1.5$.

To solve this problem, let's simplify $2\log_3 8$ using logarithm rules.

• Step 1: Recognize the expression form
  The expression is of the form $a \cdot \log_b c$, where $a = 2$, $b = 3$, and $c = 8$.
• Step 2: Apply the power property
  According to the power property of logarithms, $2 \cdot \log_3 8$ can be simplified to $\log_3 (8^2)$.
• Perform the calculation
  Calculate $8^2$, which is $64$.
• Step 3: Simplify further
  Therefore, we have $\log_3 64$.

This is a straightforward application of the power property of logarithms. By applying this property correctly, we've simplified the original expression correctly.

Therefore, the simplified form of $2\log_3 8$ is $\log_3 64$.

To solve this problem, let's simplify the given expression $\frac{\log_85}{\log_89}$.

• Step 1: Recognize that both the numerator and denominator have the same base, 8.
• Step 2: The division property of logarithms states that $\frac{\log_b M}{\log_b N} = \log_N M$.
• Step 3: Apply the division rule to the given expression: $\frac{\log_8 5}{\log_8 9} = \log_9 5$.

Thus, after simplifying, we see that $\frac{\log_85}{\log_89} = \log_9 5$.

Hence, the correct answer is $\log_9 5$, which corresponds to the choice 1.

To solve this problem, we'll apply the following steps:

• Step 1: Identify given logarithms and their base.
• Step 2: Employ the sum of logarithms property to combine the terms.
• Step 3: Calculate the resulting argument of the logarithm.

Now, let's work through each step:

Step 1: We have two logarithms: $\log_9 74$ and $\log_9 \frac{1}{2}$, sharing the base of $9$.

Step 2: Since the bases are the same, we use the sum property of logarithms:

$\log_9 74 + \log_9 \frac{1}{2} = \log_9 (74 \times \frac{1}{2})$.

Step 3: Calculate the product $74 \times \frac{1}{2}$:

$74 \times \frac{1}{2} = 37$.

So, we have:

$\log_9 (74 \times \frac{1}{2}) = \log_9 37$.

Therefore, the solution to the problem is $\log_9 37$.

To solve this problem, we'll follow these steps:

• Step 1: Identify the given expression as $\log_2 4 + \log_2 5$.
• Step 2: Use the sum of logarithms rule to simplify the expression.
• Step 3: Calculate the product and express the result.

Let's work through each step:

Step 1: We have $\log_2 4 + \log_2 5$ as our expression.

Step 2: Apply the sum of logarithms formula:

$\log_2 4 + \log_2 5 = \log_2 (4 \cdot 5)$

Step 3: Calculate the product:

$4 \times 5 = 20$

Thus, $\log_2 (4 \cdot 5) = \log_2 20$.

Therefore, the solution to the problem is $\log_2 20$.

To solve this problem, we'll follow these steps:

• Step 1: Identify the property of logarithms that relates inverses.
• Step 2: Apply this property to the given expression.
• Step 3: Compare with provided choices to identify the correct option.

Now, let's work through each step:

Step 1: The problem asks us to find the expression equal to $\frac{1}{\log_4 9}$.

Step 2: We use the logarithmic property $\log_b a = \frac{1}{\log_a b}$. Thus, replacing $b$ with 9 and $a$ with 4, we have:

$\frac{1}{\log_4 9} = \log_9 4$.

Step 3: Comparing this result to the provided choices, we find that the correct answer is $\log_9 4$, corresponding to Choice 1.

Therefore, the solution to the problem is $\log_9 4$.

To solve this problem, we will use the property of logarithms that allows us to combine the sum of two logarithms:

• Step 1: Identify the formula. We use the property $\log_b(x) + \log_b(y) = \log_b(x \cdot y)$ where both logarithms must have the same base.
• Step 2: Recognize the base. Here, both logarithms are in base 10: $\log_{10}3$ and $\log_{10}4$.
• Step 3: Apply the property. Add the two logarithms using the formula: $\log_{10}3 + \log_{10}4 = \log_{10}(3 \cdot 4)$.
• Step 4: Perform the multiplication. Compute $3 \cdot 4$ to get 12.
• Step 5: Express the result as a single logarithm: $\log_{10}12$.

Therefore, the expression $\log_{10}3 + \log_{10}4$ simplifies to $\log_{10}12$.

$2\log_82=\log_82^2=\log_84$

$2\log_82+\log_83=\log_84+\log_83=$

$\log_84\cdot3=\log_812$

To solve the expression $\log_3 7 \times \log_7 9$, we use a known logarithmic property. This property states that:

$\log_a b \times \log_b c = \log_a c$

Applying this property allows us to simplify:

$\log_3 7 \times \log_7 9 = \log_3 9$

Next, we need to calculate $\log_3 9$. Since 9 can be expressed as $3^2$, we have:

$\log_3 9 = \log_3(3^2)$

Using the power rule of logarithms, $\log_b (x^n) = n \cdot \log_b x$, we find:

$\log_3(3^2) = 2 \cdot \log_3 3$

Since $\log_3 3 = 1$, it follows that:

$2 \cdot 1 = 2$

Therefore, the value of $\log_3 7 \times \log_7 9$ is $2$.

The correct answer choice is therefore Choice 3: $2$.

To solve the given expression $\frac{\log_{4x}9}{\log_{4x}a}$ using the change-of-base formula, follow these steps:

• Step 1: Apply the change-of-base formula to both the numerator and the denominator expressions.
  This gives us: $\log_{4x}9 = \frac{\log_a 9}{\log_a (4x)}$ and $\log_{4x}a = \frac{\log_a a}{\log_a (4x)}$.
• Step 2: Substitute these into our original expression:
  $\frac{\log_{4x}9}{\log_{4x}a} = \frac{\frac{\log_a 9}{\log_a (4x)}}{\frac{\log_a a}{\log_a (4x)}}$.
• Step 3: Simplify the fraction:
  The $\log_a (4x)$ cancels out from the numerator and the denominator, leaving us with $\frac{\log_a 9}{\log_a a}$.
• Step 4: Further simplify using the fact that $\log_a a = 1$ because any number $a$ to the power of 1 is $a$.
  This results in $\frac{\log_a 9}{1} = \log_a 9$.

Therefore, the expression simplifies to $\log_a 9$.

The correct answer is $\log_a 9$, which matches choice 1.

To solve the problem, follow these steps:

• Step 1: Identify the expression to simplify, $\frac{1}{\ln 8}$.
• Step 2: Apply the change of base formula:

Using the change of base formula, we have:
$\log_8 e = \frac{\ln e}{\ln 8}$ Since $\ln e = 1$, substituting gives:
$\log_8 e = \frac{1}{\ln 8}$

Therefore, the expression $\frac{1}{\ln 8}$ can be rewritten as $\log_8 e$.

Thus, the correct choice is $\log_8 e$.

To solve the problem of evaluating $\log_7 4$, we will use the change-of-base formula for logarithms.

The change-of-base formula is:

• $\log_b a = \frac{\log_k a}{\log_k b}$, where $k$ can be any base, commonly chosen as 10 (common logs) or $e$ (natural logs).

We will choose natural logarithms ($\ln$) for simplicity, therefore:

$\log_7 4 = \frac{\ln 4}{\ln 7}$

By applying the change-of-base formula, we find that the logarithm $\log_7 4$ can be expressed as $\frac{\ln 4}{\ln 7}$.

Upon examining the provided choices, we identify that choice 2: $\frac{\ln 4}{\ln 7}$ matches our result.

Therefore, the solution to the problem is $\frac{\ln 4}{\ln 7}$.

To solve the problem $\frac{1}{2}\log_39-\log_31.5$, we need to apply the rules of logarithms:

• Step 1: Simplify with the power rule
  Using the power rule $\frac{1}{2}\log_39 = \log_39^{1/2}$. Since $9 = 3^2$, we have $9^{1/2} = 3^{2 \cdot 1/2} = 3^1$. Thus, $\frac{1}{2}\log_39 = \log_3 3 = 1$.

• Step 2: Apply the subtraction rule
  Now, the expression becomes $1 - \log_3 1.5$. Using the subtraction rule: $1 - \log_3 1.5 = \log_3 3 - \log_3 1.5 = \log_3 \left(\frac{3}{1.5}\right)$.

• Step 3: Simplify the fraction
  Calculate $\frac{3}{1.5}$: it simplifies to 2 because $3 \div 1.5 = 2$.

Thus, the simplified expression is $\log_3 2$.

Using the provided answer choices, the correct answer matches choice $\log_3 2$, which corresponds to choice 2.

Therefore, the solution to the problem is $\log_3 2$.

To solve the problem $\log_6 8$, we need to express the number 8 as a power of a base that simplifies the logarithm. We can write 8 as $2^3$, because 8 equals 2 multiplied by itself three times.

Let's use the power property of logarithms, which is:

• $\log_b (a^n) = n \log_b a$

Applying this property to $\log_6 8$, we have:

$\log_6 8 = \log_6 (2^3)$

Using the power property, this becomes:

$\log_6 (2^3) = 3 \log_6 2$

Therefore, the expression for $\log_6 8$ in terms of $\log_6 2$ is:

$3 \log_6 2$.

To solve this problem, we'll begin by simplifying the given expression using logarithmic rules:

• Step 1: Simplify the first term $\frac{1}{5}\log_8 1024$:
  Since $1024 = 2^{10}$, we can rewrite this as $\log_8 (2^{10}) = 10 \log_8 2$. Thus, $\frac{1}{5} \log_8 1024 = \frac{1}{5} (10 \log_8 2) = 2 \log_8 2$.
• Step 2: Simplify the second term $2 \log_8 \frac{1}{2}$:
  Note $\frac{1}{2} = 2^{-1}$. Therefore, $\log_8 \left(\frac{1}{2}\right) = \log_8(2^{-1}) = -1 \log_8 2$. Thus, $2 \log_8 \left(\frac{1}{2}\right) = 2(-\log_8 2) = -2 \log_8 2$.
• Step 3: Subtract the expressions:
  Combine the terms using the difference rule:
  $2 \log_8 2 - (-2 \log_8 2) = 2 \log_8 2 + 2 \log_8 2 = 4 \log_8 2$.
• Step 4: Simplify further:
  Since $4 = 2^2$, we can express this as $\log_8 (2^4) = \log_8 (16)$.

Therefore, the simplified form of the expression is $\log_8 16$.

The correct choice is thus $\log_8 16$, matching with choice (1).