12log24×log38+log39×log37= \frac{1}{2}\log_24\times\log_38+\log_39\times\log_37= 21log24×log38+log39×log37=
We break it down into parts
log24=x \log_24=x log24=x
2x=4 2^x=4 2x=4
x=2 x=2 x=2
log39=x \log_39=x log39=x
3x=9 3^x=9 3x=9
We substitute into the equation
12⋅2log38+2log37= \frac{1}{2}\cdot2\log_38+2\log_37= 21⋅2log38+2log37=
1⋅log38+2log37= 1\cdot\log_38+2\log_37= 1⋅log38+2log37=
log38+log372= \log_38+\log_37^2= log38+log372=
log38+log349= \log_38+\log_349= log38+log349=
log3(8⋅49)=log3392 \log_3\left(8\cdot49\right)=\log_3392 log3(8⋅49)=log3392x=2 x=2 x=2
log3392 \log_3392 log3392