Examples with solutions for Factorization - Common Factor: Decomposing a Number into smaller numbers/parts

Exercise #1

Break down the expression into basic terms:

8y2 8y^2

Step-by-Step Solution

To break down the expression 8y2 8y^2 , we identify the basic components. The expression y2 y^2 is a shorthand fory×y y \times y . Therefore, 8y2 8y^2 can be decomposed as 8yy 8 \cdot y \cdot y .

Answer

8yy 8\cdot y\cdot y

Exercise #2

Break down the expression into basic terms:

3a3 3a^3

Step-by-Step Solution

To break down the expression 3a3 3a^3 , we recognize that a3 a^3 means a×a×a a \times a \times a . Therefore, 3a3 3a^3 can be decomposed as 3aaa 3 \cdot a\cdot a\cdot a .

Answer

3aaa 3 \cdot a\cdot a\cdot a

Exercise #3

Break down the expression into basic terms:

8y 8y

Step-by-Step Solution

To break down the expression 8y 8y , we can see it as the multiplication of 8 8 and y y :

8y=8y 8y = 8 \cdot y

This shows the expression as a product of two factors, 8 8 and y y .

Answer

8y 8\cdot y

Exercise #4

Break down the expression into basic terms:

5m 5m

Step-by-Step Solution

To break down the expression 5m 5m , we recognize it as the product of 5 5 and m m :

5m=5m 5m = 5 \cdot m

This expression can be seen as a multiplication of the constant 5 5 and the variable m m .

Answer

5m 5\cdot m

Exercise #5

Break down the expression into basic terms:

5x2 5x^2

Step-by-Step Solution

To break down the expression 5x2 5x^2 into its basic terms, we identify each component in the expression:

5is a constant multiplier 5 \, \text{is a constant multiplier}

x2 x^2 means xx x \cdot x

Therefore, 5x2 5x^2 can be rewritten as 5xx 5 \cdot x \cdot x .

Answer

5xx 5\cdot x\cdot x

Exercise #6

Break down the expression into basic terms:

3y3 3y^3

Step-by-Step Solution

To break down the expression 3y3 3y^3 into its basic terms, we understand the components of the expression:

3is a constant multiplier 3 \, \text{is a constant multiplier}

y3 y^3 can be rewritten as yyy y \cdot y \cdot y

Thus, 3y3 3y^3 can be decomposed into 3yyy 3 \cdot y \cdot y \cdot y .

Answer

3yyy 3\cdot y\cdot y \cdot y

Exercise #7

Break down the expression into basic terms:

4a2 4a^2

Step-by-Step Solution

To break down the expression 4a2 4a^2 into basic terms, we need to look at each factor:

4is a constant multiplier 4 \, \text{is a constant multiplier}

a2 a^2 means aa a \cdot a

Hence, 4a2 4a^2 is equivalent to 4aa 4 \cdot a \cdot a .

Answer

4aa 4\cdot a\cdot a

Exercise #8

Break down the expression into basic terms:

6b2 6b^2

Step-by-Step Solution

To break down the expression 6b2 6b^2 into its fundamental parts, we analyze each element:

6is a constant multiplier 6 \, \text{is a constant multiplier}

b2 b^2 represents bb b \cdot b

Therefore, 6b2 6b^2 is decomposed as 6bb 6 \cdot b \cdot b .

Answer

6bb 6\cdot b\cdot b

Exercise #9

Break down the expression into basic terms:

3x2+2x 3x^2 + 2x

Step-by-Step Solution

The expression can be broken down as follows:

3x2+2x 3x^2 + 2x

Breaking down each term we have:

- 3x2 3x^2 becomes 3xx 3\cdot x\cdot x

- 2x 2x remains 2x 2 \cdot x

Finally, the expression is:

3xx+2x 3\cdot x\cdot x+2\cdot x

Answer

3xx+2x 3\cdot x\cdot x+2\cdot x

Exercise #10

Break down the expression into basic terms:

4x2+3x 4x^2 + 3x

Step-by-Step Solution

The expression can be broken down as follows:

4x2+3x 4x^2 + 3x

1. Notice that both terms contain a common factor of x x .

2. Factor out the common x x :

x(4x+3) x(4x + 3) .

3. Thus, breaking down each term we have:

- 4x2 4x^2 becomes 4xx 4x \cdot x after factoring out x x .

- 3x 3x remains 3x 3 \cdot x after factoring out x x .

Finally, the expression is:

4xx+3x 4x\cdot x + 3\cdot x

Answer

4xx+3x 4\cdot x\cdot x+3\cdot x

Exercise #11

Simplify the expression:

5x3+3x2 5x^3 + 3x^2

Step-by-Step Solution

To simplify the expression 5x3+3x2 5x^3 + 3x^2 , we can break it down into basic terms:

The term 5x3 5x^3 can be written as 5xxx 5 \cdot x \cdot x \cdot x .

The term3x2 3x^2 can be written as 3xx 3 \cdot x \cdot x .

Thus, the expression simplifies to5xxx+3xx 5 \cdot x \cdot x \cdot x + 3 \cdot x \cdot x .

Answer

5xxx+3xx 5\cdot x\cdot x\cdot x + 3\cdot x\cdot x

Exercise #12

Rewrite using basic components:

6z2+z 6z^2 + z

Step-by-Step Solution

To rewrite the expression 6z2+z 6z^2 + z , break it down into basic components:

The term 6z2 6z^2 can be expressed as 6zz 6 \cdot z \cdot z .

The term z z is 1z 1 \cdot z .

Thus, rewriting gives 6zz+1z 6 \cdot z \cdot z + 1 \cdot z .

Answer

6zz+1z 6\cdot z\cdot z + 1\cdot z

Exercise #13

Break down the expression into basic terms:

4x2+6x 4x^2 + 6x

Step-by-Step Solution

To break down the expression4x2+6x 4x^2 + 6x into its basic terms, we need to look for a common factor in both terms.

The first term is 4x2 4x^2 , which can be rewritten as 4xx 4\cdot x\cdot x .

The second term is6x 6x , which can be rewritten as 23x 2\cdot 3\cdot x .

The common factor between the terms is x x .

Thus, the expression can be broken down into 4x2+6x 4\cdot x^2 + 6\cdot x , and further rewritten with common factors as 4xx+6x 4\cdot x\cdot x + 6\cdot x .

Answer

4xx+6x 4\cdot x\cdot x+6\cdot x

Exercise #14

Break down the expression into basic terms:

5x2+10 5x^2 + 10

Step-by-Step Solution

To break down the expression 5x2+10 5x^2 + 10 , identify the common factors.

The first term is 5x2 5x^2 , which can be rewritten as 5xx 5\cdot x\cdot x .

The second term is 10 10 , which can be rewritten as 52 5\cdot 2 .

Notice that both terms share a common factor of 5 5 .

This allows the expression to be broken down to 5(x2)+10 5(x^2) + 10 , which translates to 5xx+10 5\cdot x\cdot x + 10 using common terms.

Answer

5xx+10 5\cdot x\cdot x+10

Exercise #15

Break down the expression into basic terms:

3y2+6 3y^2 + 6

Step-by-Step Solution

To break down the expression 3y2+6 3y^2 + 6 , we need to recognize common factors or express terms in basic forms.

The term 3y2 3y^2 can be rewritten by breaking down the operations: 3yy 3\cdot y\cdot y .

The constant 6 6 remains as it is in its basic term.

Thus, the broken down expression becomes 3yy+6 3\cdot y\cdot y + 6 .

Answer

3yy+6 3\cdot y\cdot y+6

Exercise #16

Factor the expression completely:

4y2+2y 4y^2 + 2y

Step-by-Step Solution

To factor the expression 4y2+2y 4y^2 + 2y , we identify the common factor in both terms:

The term 4y2 4y^2 can be written as2y2y 2y \cdot 2y .

The term 2y 2y can be written as 2y 2 \cdot y .

The common factor is 2y 2y .

Factorizing gives 2y(2y+1) 2y \cdot (2y + 1) .

Answer

2y(2y+1) 2y \cdot (2y + 1)

Exercise #17

Simplify the expression:

7y23y+4 7y^2 - 3y + 4

Step-by-Step Solution

The expression is already in its simplest form as it consists of terms where none can be combined due to differing degrees of the variable y y . Thus, the simplified expression is: 7y23y+4 7y^2 - 3y + 4 .

Answer

7y23y+4 7y^2 - 3y + 4