Circle - Examples, Exercises and Solutions

Question Types:
Area of a Circle: A shape consisting of several shapes (requiring the same formula)Area of a Circle: Calculate The Missing Side based on the formulaCircumference: Increasing a specific element by addition of.....or multiplication by.......Circumference: Using Pythagoras' theoremCircumference: Verifying whether or not the formula is applicableArea of a Circle: Increasing a specific element by addition of.....or multiplication by.......Circumference: Subtraction or addition to a larger shapeArea of a Circle: Using Pythagoras' theoremArea of a Circle for ninth grade: Impact of a radius change on the area of a circleCircumference: A shape consisting of several shapes (requiring the same formula)Circumference: Using variablesCircumference for ninth grade: Calculate by how much the perimeter has increasedArea of a Circle: Calculating parts of the circleArea of a Circle: Using additional geometric shapesArea of a Circle for ninth grade: Calculating parts of the circleCircumference: Calculating parts of the circleCircumference: Identifying and defining elementsCircumference for ninth grade: Calculating arc lengthArea of a Circle: Finding Area based off Perimeter and Vice VersaArea of a Circle: Subtraction or addition to a larger shapeCircumference: Using additional geometric shapesArea of a Circle: Applying the formulaCircumference: Worded problemsArea of a Circle for ninth grade: Finding Area based off Perimeter and Vice VersaCircumference: Identify the greater valueArea of a Circle for ninth grade: Calculate The Missing Side based on the formulaArea of a Circle for ninth grade: Applying the formulaCircumference: Finding Area based off Perimeter and Vice VersaCircumference: Calculate The Missing Side based on the formulaCircumference: Applying the formula

Elements of the circumference

What is circumference?

This question is not easy to answer and even more complicated to understand. If you imagine any point on a flat surface and a series of points whose distance from that point is identical, then you are looking at a circle.

A circumference is the boundary of a circle, and its elements include:

  • Radius: The distance from the center of the circle to any point on the circumference.
  • Diameter: A straight line passing through the center that connects two points on the circumference, equal to twice the radius.
  • Arc: A portion of the circumference.
  • Chord: A line segment connecting two points on the circle.
  • Tangent: A line that touches the circle at exactly one point.
B - What is circumference

Practice Circle

Examples with solutions for Circle

Exercise #1

O is the center of the circle in the figure below.

888OOO What is its circumference?

Video Solution

Step-by-Step Solution

We use the formula:P=2πr P=2\pi r

We replace the data in the formula:P=2×8π P=2\times8\pi

P=16π P=16\pi

Answer

16π 16\pi cm

Exercise #2

Given that the diameter of the circle is 7 cm

What is the area?

777

Video Solution

Step-by-Step Solution

First we need the formula for the area of a circle:

 πr2 \pi r^2

In the question, we are given the diameter of the circle, but we still need the radius.

It is known that the radius is actually half of the diameter, therefore:

r=7:2=3.5 r=7:2=3.5

We substitute the value into the formula.

π3.52=12.25π \pi3.5^2=12.25\pi

Answer

12.25π 12.25\pi cm².

Exercise #3

O is the center of the circle in the diagram below.

What is its area?

333OOO

Video Solution

Step-by-Step Solution

Remember that the formula for the area of a circle is

πR²

 

We insert the known data:

π3²

π9

 

Answer

9π 9\pi cm²

Exercise #4

Look at the circle in the figure:

444

Its radius is equal to 4.

What is its circumference?

Video Solution

Step-by-Step Solution

The formula for the circumference is equal to:

2πr 2\pi r

Answer

Exercise #5

Look at the circle in the figure:

777

The radius is equal to 7.

What is the area of the circle?

Video Solution

Step-by-Step Solution

Remember that the formula for the area of a circle is

πR²

 

We replace the data we know:

π7²

π49

Answer

49π

Exercise #6

Look at the circle in the figure.

What is its circumference if its radius is equal to 6?

6

Video Solution

Step-by-Step Solution

Formula of the circumference:

P=2πr P=2\pi r

We insert the given data into the formula:

P=2×6×π P=2\times6\times\pi

P=12π P=12\pi

Answer

12π 12\pi

Exercise #7

Is it possible that the circumference of a circle is 8 meters and its diameter is 4 meters?

Video Solution

Step-by-Step Solution

To calculate, we will use the formula:

P2r=π \frac{P}{2r}=\pi

Pi is the ratio between the circumference of the circle and the diameter of the circle.

The diameter is equal to 2 radii.

Let's substitute the given data into the formula:

84=π \frac{8}{4}=\pi

2π 2\ne\pi

Therefore, this situation is not possible.

Answer

Impossible

Exercise #8

Look at the circle in the diagram.

AB is a chord.

Is it possible to calculate the area of the circle?

555AAABBB

Video Solution

Step-by-Step Solution

Since AB is just a chord and we know nothing else about the diameter or the radius, we cannot calculate the area of the circle.

Answer

It is not possible.

Exercise #9

A circle has an area of 25 cm².

What is its radius?

Video Solution

Step-by-Step Solution

Area of the circle:

S=πr2 S=\pi r^2

We insert the known data:

25=πr2 25=\pi r^2

Divide by Pi:25π=r2 \frac{25}{\pi}=r^2

Extract the root:25π=r \sqrt{\frac{25}{\pi}}=r

5π=r \frac{5}{\sqrt{\pi}}=r

Answer

5π \frac{5}{\sqrt{\pi}} cm

Exercise #10

Look at the circle in the figure.

The radius of the circle is 23 \frac{2}{3} .

What is its perimeter?

Video Solution

Step-by-Step Solution

The radius is a straight line that extends from the center of the circle to its outer edge.

The radius is essential for calculating the circumference of the circle, which can be found using the following formula:

If we substitute in the radius we have, the formula will be:

2*π*2/3

To solve this, first we'll rearrange the formula like so:

π*2*2/3 =

We'll then multiply the fraction by the whole number:

π*(2*2)/3 =

π*4/3 =

4/3π

Answer

43π \frac{4}{3}\pi

Exercise #11

Look at the circle in the figure:

131313

The diameter of the circle is 13.

What is its area?

Video Solution

Step-by-Step Solution

First, let's remember what the formula for the area of a circle is:

S=πr2 S=\pi r^2

The problem gives us the diameter, and we know that the radius is half of the diameter therefore:

132=6.5 \frac{13}{2}=6.5

We replace in the formula and solve:

S=π×6.52 S=\pi\times6.5^2

S=42.25π S=42.25\pi

Answer

42.25π

Exercise #12

The circumference of a circle is 14.

How long is the circle's radius?

Video Solution

Step-by-Step Solution

We begin by using the formula:

P=2πr P=2\pi r

We then insert the given data into the formula:

14=2×π×r 14=2\times\pi\times r

Lastly we divide Pi by 2:

142π=2πr2π \frac{14}{2\pi}=\frac{2\pi r}{2\pi}

7π=r \frac{7}{\pi}=r

Answer

7π \frac{7}{\pi}

Exercise #13

A circle has a circumference of 31.41.

What is its radius?

Video Solution

Step-by-Step Solution

To solve the exercise, first we must remember the circumference formula:

P=2πR P= 2\pi R

P is the circumference and Pi has a value of 3.14 (approximately).

We substitute in the known data:

31.41=23.141R 31.41=2\cdot3.141\cdot R

Keep in mind that the result can be easily simplified using Pi:

31.413.141=2R \frac{31.41}{3.141}=2R

10=2R 10=2R

Finally, we simplify by 2:

5=R 5=R

Answer

5

Exercise #14

A circle has a circumference of 50.25.

What is its radius?

Video Solution

Step-by-Step Solution

We use the formula:

P=2πr P=2\pi r

We insert the known data into the formula:

50.25=3.14×2r 50.25=3.14\times2r

50.25=2×r×3.14 50.25=2\times r\times3.14

50.25=6.28r 50.25=6.28r

50.256.28=6.28r6.28 \frac{50.25}{6.28}=\frac{6.28r}{6.28}

r=8 r=8

Answer

8

Exercise #15

Given the semicircle:
141414
What is the area?

Video Solution

Step-by-Step Solution

Formula for the area of a circle:

S=πr2 S=\pi r^2

We complete the shape into a full circle and notice that 14 is the diameter.

A diameter is equal to 2 radii, so:r=7 r=7

We replace in the formula:S=π×72 S=\pi\times7^2

S=49π S=49\pi

Answer

24.5π