Area of a Rectangle - Examples, Exercises and Solutions

To calculate the area of the rectangle, we multiply the length by the width:

$15\times3=45$

We begin by multiplying side AB by side BC

We then substitute the given data and we obtain the following:

$4.5\times2=9$

Hence the area of rectangle ABCD equals 9

Let's begin by multiplying side AB by side BC

If we insert the known data into the above equation we should obtain the following:

$10\times2.5=25$

Thus the area of rectangle ABCD equals 25.

We will use the formula to calculate the area of a rectangle: length times width

$9\times6=54$

Let's calculate the area of the rectangle by multiplying the length by the width:

$4\times8=32$

Let's calculate the area of the rectangle by multiplying the length by the width:

$2\times5=10$

Let's calculate the area of the rectangle by multiplying the length by the width:

$11\times7=77$

Let's calculate the area of the rectangle by multiplying the length by the width:

$AB\times BC=10\times5=50$

Let's calculate the area of the rectangle by multiplying the length by the width:

$AB\times BC=7\times5=35$

Remember that the formula for the area of a rectangle is width times height

We are given that the width of the rectangle is 6

and that the length of the rectangle is 4

 Therefore we calculate:

6*4=24

We use the formula to calculate a rectangle: length times width:

According to the existing data:

$4^2\times5^=S$

$S=16\times5$

$S=80$

Let's calculate the area of the rectangle by multiplying the length and width:

$4.5\times8=36$

Let's calculate the area of the rectangle by multiplying the length by the width:

$\text{10}.5\times5=52.5$

Let's calculate the area of the rectangle by multiplying the length by the width:

$3.5\times6=21$

We use the formula to calculate a rectangle: length times width:

$AB\times AC=S$

We place the existing data into the formula:

$AB\times7=63$

$7AB=63$

We divide both sides by 7:

$AB=9$