Addition and Subtraction of Directed Numbers: Using the number line

Let's locate negative 2 on the number line.

Since negative 2 is less than 0, we'll move two steps left from zero, where each step represents one whole number as follows:

Now let's look at the operation in the exercise.

Since the operation is $+3$

And since 3 is greater than 0, we'll move three steps right from negative 2, where each step represents one whole number as follows:

We can see that we arrived at the number 1.

Let's locate the number 5 on the number line.

Since the number 5 is greater than 0, we will move five steps to the right from zero, where each step represents one whole number as follows:

Now let's look at the operation in the exercise.

Since the operation is $+(-2)$

And the number minus 2 is less than 0, we will move two steps to the left from number 5, where each step represents one whole number as follows:

We can see that the number we reached is 3.

Let's remember the rule:

$-(-x)=+x$

Therefore, the exercise we received is:

$-5+2=$

We'll locate minus 5 on the number line and move two steps to the right (since 2 is greater than zero):

We can see that we've arrived at the number minus 3.

We'll locate minus 4 on the number line and move two steps to the left (since minus 2 is less than zero):

We can see that we've arrived at the number minus 6.

We will locate the number 3 on the number line, then move 4 steps to the left from it (since minus 4 is less than zero):

We can see that we have reached the number minus 1.

Let's remember the rule:

$-(-x)=+$

We'll write the exercise in the appropriate form:

$3+(2)=$

We'll locate the number 3 on the number line, from which we'll move 2 steps to the right (since 2 is greater than zero):

We can see that we've reached the number 5.

Let's locate negative 3 on the number line.

Since negative 3 is less than 0, we'll move three steps left from zero, where each step represents one whole number as follows:

Now let's look at the operation in the exercise.

Since the operation is $+(-3)$

and negative 3 is less than 0, we'll move three steps left from negative 3, where each step represents one whole number as follows:

We can see that we arrived at negative 6.

Let's locate negative 5 on the number line.

Since negative 5 is less than 0, we'll move five steps to the left from zero, where each step represents one whole number as follows:

Now let's look at the operation in the exercise.

Since the operation is $+(-2)$

And negative 2 is less than 0, we'll move two steps to the left from negative 5, where each step represents one whole number as follows:

We can see that we reached negative 7.

Let's locate negative 4 on the number line.

Since negative 4 is less than 0, we'll move four steps left from zero, where each step represents one whole number as follows:

Now let's look at the operation in the exercise.

Since the operation is $+7$

And since 7 is greater than 0, we'll move seven steps to the right from negative 4, where each step represents one whole number as follows:

We can see that we arrived at the number 3.

We will locate the number 10 on the number line, then move 12 steps to the left from it (since minus 12 is less than zero):

We can see that we have reached the number minus 2.

Let's remember the rule:

$-(-x)=+$

We'll write the exercise in the appropriate form:

$-3+(4)=$

We'll locate the number negative 3 on the number line, from which we'll move 4 steps to the right (since 4 is greater than zero):

We can see that we've reached the number 1.