−30−(−2)+(−8)+5=
\( -30-(-2)+(-8)+5= \)
\( -30+4+(-8)= \)
\( 4+3+(-6)+(-9)= \)
\( (-4)+2+(-3)+(-5)= \)
\( (-30)+(-2)+30+(-5)= \)
Let's remember the rule:
Now let's write the exercise in the appropriate way:
We'll locate negative 28 on the number line and go 8 steps left (since negative 8 is less than zero):
We can see that we reached negative 36.
Now the exercise we got is:
We'll locate negative 36 on the number line and go 5 steps right (since 5 is greater than zero):
We can see that we reached negative 31
Let's locate negative 30 on the number line and move 4 steps to the right (since 4 is greater than zero):
We can see that we reached negative 26.
Now the exercise we got is:
Now let's locate negative 26 on the number line and move 8 steps to the left (since negative 8 is less than zero):
We can see that we reached negative 34
First, let's look at the first exercise:
We will locate the number 4 on the axis, and move right three steps, where each step represents a whole number in the following way:
We can see that we reached the number 7.
Now we get the exercise:
Let's look at the exercise:
We will locate the number 7 on the axis, and move left six steps, where each step represents a whole number in the following way:
We can see that we reached the number 1.
Now we got the exercise:
We will locate the number 1 on the axis, and move left nine steps, where each step represents a whole number in the following way:
We can see that we reached the number minus 8.
Let's start with the leftmost exercise:
We'll locate negative 4 on the axis and move two steps to the right, where each step represents one whole number:
We can see that we've reached negative 2.
Now we'll get the exercise:
Let's focus on the exercise:
We'll locate negative 2 on the axis and move three steps to the left, where each step represents one whole number:
We can see that we've reached negative 5.
Now we'll get the exercise:
We'll locate negative 5 on the axis and move five steps to the left, where each step represents one whole number:
We can see that we've reached negative 10.
First, let's organize the exercise in a way that will make it easier and more convenient to solve.
Notice that the number 30 appears twice in the exercise, so let's start with it:
Let's look at the exercise:
Since we move left from zero to minus 30, and then return right 30 steps, we will arrive at the same number we started from: 0
Now let's continue the exercise in the following way:
We'll locate the number minus 2 on the number line, and move left five steps where each step represents one whole number:
We can see that we arrived at minus 7.
\( 25-(-5)+(-6)-4= \)
\( 15+5-(-4)+(-9)+8-4= \)
\( -27-(-7)+(-6)+2-11= \)
\( 7.5+(-9.5)+5+(-13.5)=\text{?} \)
\( -\frac{3}{8}-(-\frac{5}{8})-(-\frac{1}{2})= \)
Let's remember the rule:
Let's write the exercise in the appropriate form:
Let's solve the exercise from left to right:
Now we get the exercise:
Let's remember the rule:
Let's write the exercise in the appropriate form:
Let's solve the exercise from left to right:
Let's remember the rule:
We'll write the exercise in the appropriate form:
Let's solve the exercise from left to right:
Now we'll get the exercise:
Let's solve the exercise from left to right:
Now we'll get the exercise:
Let's remember the rule:
We'll write the exercise in the appropriate form:
Let's solve the exercise from left to right:
First, we solve the multiplication exercise, that is where there is a plus or minus sign before another sign.
Now we solve as a common exercise from left to right:
Let's begin by expanding the parentheses whilst paying attention to the minus and plus signs, which change accordingly:
We should obtain the following:
Now let's solve the exercise from left to right:
\( -\frac{14}{7}+(-3)-\frac{1}{2}-(-\frac{1}{4})= \)
Solve:
\( -\frac{4}{16}-(-\frac{3}{8})+\frac{2}{8}+(-\frac{1}{4})= \)
\( (-10)+(-3)+4+(-12)= \)
\( -3+(-\frac{1}{2})+(\frac{3}{8})+\frac{5}{8}= \)
\( -\frac{1}{2}+\frac{3}{4}+-\frac{1}{5}+(-\frac{4}{5})= \)
Solve:
\( -\frac{4}{9}+5+(-2)+\frac{5}{9}= \)
\( -5+-\frac{1}{2}+10+(-\frac{3}{4})= \)