Expand and Simplify: (3b+7a)(-5a+2b) Binomial Multiplication

Question

(3b+7a)(5a+2b)= (3b+7a)(-5a+2b)=

Video Solution

Step-by-Step Solution

Let's simplify the given expression, open the parentheses using the extended distribution law:

(t+k)(c+d)=tc+td+kc+kd (\textcolor{red}{t}+\textcolor{blue}{k})(c+d)=\textcolor{red}{t}c+\textcolor{red}{t}d+\textcolor{blue}{k}c+\textcolor{blue}{k}d

Note that in the formula template for the above distribution law, we take as a default that the operation between the terms inside the parentheses is addition, therefore we won't forget of course that the sign preceding the term is an inseparable part of it, and we'll also apply the rules of sign multiplication and thus we can present any expression in parentheses, which we'll open using the above formula, first as an expression where addition operation exists between all terms:

(3b+7a)(5a+2b)(3b+7a)((5a)+2b) (3b+7a)(-5a+2b) \\ (\textcolor{red}{3b}+\textcolor{blue}{7a})((-5a)+2b)\\ Let's begin then with opening the parentheses:

(3b+7a)((5a)+2b)3b(5a)+3b2b+7a(5a)+7a2b15ab+6b235a2+14ab (\textcolor{red}{3b}+\textcolor{blue}{7a})((-5a)+2b)\\ \textcolor{red}{3b}\cdot (-5a)+\textcolor{red}{3b}\cdot2b+\textcolor{blue}{7a}\cdot (-5a) +\textcolor{blue}{7a}\cdot2b\\ -15ab+6b^2-35a^2+14ab

In calculating the above multiplications, we used the multiplication table and the laws of exponents for multiplication between terms with identical bases:

xmxn=xm+n x^m\cdot x^n=x^{m+n}

In the next step, we'll combine like terms, we'll define like terms as terms where the variable(s) (or each variable separately), in this case a and b, have identical exponents (in the absence of one of the variables from the expression, we'll consider its exponent as zero power, since raising any number to the zero power yields 1), we'll use the commutative law of addition, additionally we'll arrange the expression from highest to lowest power from left to right (we'll treat the free number as zero power):
15ab+6b235a2+14ab6b235a215ab+14ab6b235a2ab \textcolor{purple}{-15ab}\textcolor{green}{+6b^2}-35a^2\textcolor{purple}{+14ab}\\ \textcolor{green}{6b^2}-35a^2\textcolor{purple}{-15ab}\textcolor{purple}{+14ab}\\ \textcolor{green}{6b^2}-35a^2\textcolor{purple}{-ab}

In the combining of like terms performed above, we highlighted the different terms using colors, and as emphasized before, we made sure that the sign preceding the term is an inseparable part of it,

We therefore got that the correct answer is answer B.

Answer

6b235a2ab 6b^2-35a^2 -ab