The Commutative Property of Addition - Examples, Exercises and Solutions

According to the order of operations, addition and subtraction are on the same level and, therefore, must be resolved from left to right.

However, in the exercise we can use the substitution property to make solving simpler.

-5+4+1-3

4+1-5-3

5-5-3

0-3

-3

According to the order of operations, we first solve the division exercise:

$4:2=2$

Now we obtain the exercise:

$2+2=4$

According to the order of operations, we first solve the multiplication exercise:

We add the 4 in the numerator of the fraction:

$\frac{1\times4}{4}+2=$

We solve the exercise in the numerator of the fraction and obtain:

$\frac{4}{4}+2=1+2=3$

According to the order of operations, we solve the exercise from left to right:

$-2-4=-6$

$-6+6=0$

$0-1=-1$

According to the order of operations, we start with the multiplication exercise and then with the addition.

$12\times13=156$

Now we get the exercise:

$156+14=170$

According to the rules of the order of arithmetic operations, in an exercise where there is only one multiplication operation, the order of the numbers can be changed.

Hence we can rearrange the exercise to obtain a round number that will help us later in the solution:

$5\times2\times17=$

Now we solve the exercise from left to right:

$5\times2=10$

$10\times17=170$

Given that the entire exercise is with subtraction, we solve the exercise from left to right:

$10-5=5$

$5-2=3$

$3-3=0$

Given that we are referring to addition and subtraction exercises, we solve the exercise from left to right:

$4-2=2$

$2+2=4$

$4-4=0$

If we draw a line that starts at negative five and ends at 5

We will go from the point negative five two steps forward (+2) we will arrive at the number negative 3.

In order to simplify our calculations, we try to add numbers that give us a round result.

Keep in mind that:

$19+21=40$

$34+6=40$

Now, we get a more manageable exercise to solve:

$40+40+10=80+10=90$

In order to simplify the resolution process we try to add numbers that give us a round result.

Keep in mind that:

$4+4=8$

Now we get the exercise:

$74+36+6+8=$

Keep in mind that:

$74+6=80$

$32+8=40$

Now, we get a more manageable exercise to solve:

$80+40=120$

In this exercise, it is not possible to use the substitution property, therefore we solve it as is from left to right according to the order of arithmetic operations.

That is, we first solve the multiplication exercise and then we add:

$11\times3=33$

$33+7=40$

Since the exercise involves only multiplication, we will use the commutative property to simplify the calculation:

$2\times15\times8=$

Now let's solve the multiplication on the right:

$15\times8=120$

We obtain the following expression:

$2\times120=240$

Since the exercise only involves addition, we will use the commutative property to calculate more conveniently:

$5+5+14=$

We will then solve the exercise from left to right:

$5+5=10$

$10+14=24$

Since the exercise only involves addition, we will use the commutative property to solve it.

$8+2+9=$

Now let's solve the exercise from left to right:

$8+2=10$

$10+9=19$